{"id":1528,"date":"2024-05-13T16:16:22","date_gmt":"2024-05-13T20:16:22","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/?post_type=chapter&#038;p=1528"},"modified":"2024-06-12T14:46:21","modified_gmt":"2024-06-12T18:46:21","slug":"an-introduction-to-poisson-distributions","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/chapter\/an-introduction-to-poisson-distributions\/","title":{"raw":"Distribution Properties and Probabilities of Exactly 'X' Events","rendered":"Distribution Properties and Probabilities of Exactly &#8216;X&#8217; Events"},"content":{"raw":"<div class=\"textbox textbox--learning-objectives\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Learning Objectives<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nUnderstand what it means for events to follow a Poisson distribution and calculate the probability of [latex]x[\/latex] events occurring per time period using the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Poisson_distribution#:~:text=Probability%20mass%20function,-A%20discrete%20random&amp;text=The%20Poisson%20distribution%20can%20be,number%20with%20a%20Poisson%20distribution.\">Poisson Probability Mass Function<\/a>.\r\n\r\n<\/div>\r\n<\/div>\r\n<h2>Five Properties of Poisson Distributions<\/h2>\r\n<ol>\r\n \t<li>There are only two possible outcomes for events \u2013 they can occur or not occur.<\/li>\r\n \t<li>Each event must be random and independent of the others.<\/li>\r\n \t<li>The occurrences must be uniformly distributed (see more in the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Continuous_uniform_distribution\">uniform distributions<\/a> section).<\/li>\r\n \t<li>Probabilities are calculated on the number of occurrences, [latex]x[\/latex], over a specific time interval.<\/li>\r\n \t<li>An average number of occurrences over a given time period is denoted as [latex]\\lambda[\/latex].<\/li>\r\n<\/ol>\r\n<h2>Two Ways of Calculating the Probability of '<em>x<\/em>' Successes<\/h2>\r\nIf we want to calculate the probability of exactly [latex]x[\/latex] events occurring per time period, we can:\r\n<ol>\r\n \t<li><span style=\"color: #333333\">Use the formula<\/span>: [latex]P(x) = \\frac{{\\lambda}^x e^{-\\lambda}}{x!}[\/latex]<\/li>\r\n \t<li><span style=\"color: #333333\">Use Excel<\/span>: = <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], FALSE)<\/li>\r\n<\/ol>\r\n<h1>three examples of poisson distributions<\/h1>\r\nThree examples of events that follow a Poisson Distribution:\r\n<ol>\r\n \t<li>The number of bad checks received by a bank per day.<\/li>\r\n \t<li>The number of motor vehicle accidents in a busy street corner per week.<\/li>\r\n \t<li>The number of shoppers arriving at a supermarket check-out counter per minute.<\/li>\r\n<\/ol>\r\n<h1>Calculating the probability of x events using the Formula (ViDEO)<\/h1>\r\nLet us better understand the Poisson formula by working through an example.\r\n<h2>Example 30.1.1<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: On a busy Friday evening, the average number of shoppers arriving at a supermarket check-out counter waiting to be served by a cashier is 6 per minute. The arrivals follow a Poisson distribution.\r\n\r\n<span style=\"color: #003366\"><strong>Question<\/strong><\/span>: In any given minute, what is the probability that exactly 5 shoppers will arrive?\r\n\r\n<span style=\"color: #003366\"><strong>Written solution:<\/strong><\/span>\u00a0Let us look at the formula a little more carefully now.\r\n<ul>\r\n \t<li>There are really only 2 variables in this formula.<\/li>\r\n \t<li>One is [latex]\\lambda[\/latex], the average; in this example, which is 6.<\/li>\r\n \t<li>The other is [latex]x[\/latex], the number for which we want to find the probability.\u00a0 In this example it is 5.<\/li>\r\n \t<li>The other letter, [latex]e[\/latex], is a constant. It is the base of the natural log and equal 2.71828.<\/li>\r\n \t<li>This gives: \\[P(x=5) =\\frac{6^5 e^{-6}}{5!}=\\frac{(7,776) \\times (0.002478752)}{ 120}=0.1606\\]<\/li>\r\n<\/ul>\r\n<span style=\"color: #003366\"><strong>Video solution:<\/strong><\/span> <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example_30-1-1_First_Poisson_Formula_Example_Written_Solution.jpg\">Click here<\/a> to download the written solutions to the video below:\r\n\r\nhttps:\/\/youtu.be\/JPv_ZJVgOqo\r\n\r\n<span style=\"color: #003366\"><strong>Conclusion:<\/strong><\/span> There is a 16.06% chance that 5 shoppers will arrive in any given minute.\r\n<h1>Calculating the probability of x events using Excel (ViDEO)<\/h1>\r\nLet us now use Excel's <a href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a> function to solve the above example.\r\n<h2>Example 30.1.2<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: Let us now use Excel to solve for the following problem:\r\n<ul>\r\n \t<li>An average of 6 shoppers arrive per minute at the till.<\/li>\r\n \t<li>Solve for the probability of exactly\u00a05 shoppers will arriving in any given minute.<\/li>\r\n<\/ul>\r\n<span style=\"color: #003366\"><strong>Solution:<\/strong><\/span> Use = POISSON.DIST(5, 6, 0). <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example30-1.xlsx\">Click here<\/a> to download the Excel solutions shown below:\r\n\r\nhttps:\/\/youtu.be\/Vi3tz_FGuvQ\r\n\r\n<span style=\"color: #003366\"><strong>Conclusion<\/strong><\/span>: There is a 16.06% chance that exactly 5 shoppers will arrive in any given minute.\r\n\r\n<span style=\"color: #003366\"><strong>Note<\/strong><\/span>: When using Excel's <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>(), we set cumulative = FALSE when calculating the probability of exactly [latex]x[\/latex] events occurring. We will examine when we use cumulative = TRUE in later sections in this Chapter.\r\n<h1>Calculating the probability of No events w\/ Formula (Exercise)<\/h1>\r\nIn the first case, it was \u2018a busy Friday evening.\u2019 Let\u2019s find out why in the next example<span style=\"font-size: 20.5333px\">.<\/span>\r\n<h2>Example 30.2.1<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: An<span style=\"font-size: 20.5333px\"> average of 6 shoppers arrive per minute at the check-out counter.\u00a0<\/span>\r\n\r\n<span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>In any given minute, what is the probability that no shoppers arrive at the counter?\r\n\r\n<strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Solve the problem by placing the values in the correct positions below:\r\n\r\n[h5p id=\"79\"]\r\n<div>\r\n<h1>Click here to reveal written solution:<\/h1>\r\n<ul>\r\n \t<li>If no shoppers arrive, then we know that [latex]x = 0[\/latex]<\/li>\r\n \t<li>We also know that the average arrival rate:\u00a0[latex]\\lambda = 6[\/latex]<\/li>\r\n \t<li>We use the formula: [latex]P(x) = \\frac{{\\lambda}^x e^{-\\lambda}}{x!}[\/latex] and add the above values in.<\/li>\r\n \t<li>This gives: [latex]P(x=0) =\\frac{6^0 \\times e^{-6}}{0!}[\/latex]<\/li>\r\n \t<li>We know that: [latex]6^0 = 1[\/latex], [latex]0! = 1[\/latex], and [latex]e^{-6} = 0.0025[\/latex]<\/li>\r\n \t<li>This gives: [latex] P(x=0) =\\frac{1 \\times 0.0025}{ 1}=0.0025[\/latex]<\/li>\r\n<\/ul>\r\n<\/div>\r\n<span style=\"color: #003366\"><strong>Conclusion: <\/strong><\/span>There is 0.25% chance that no shoppers will arrive in any given minute. In other words, there is almost NO chance that there are no shoppers arriving. This means that shoppers are almost constantly arriving, keeping the cashier busy.\r\n<h1>Calculating the probability of No events using Excel (Exercise)<\/h1>\r\nLet us now use Excel's <a href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a> function to solve the above example. This time, I'm going to put you to work in setting up the Excel formula.\r\n<h2>Example 30.2.2<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: An<span style=\"font-size: 20.5333px\"> average of 6 shoppers arrive per minute at a till, ready to check out.\u00a0<\/span>\r\n\r\n<span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>In any given minute, what is the probability that there are no shoppers arriving at this check-out counter? Can you set up the problem in Excel?\r\n\r\n<strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Complete the exercise below to calculate the probability of no shoppers arriving:\r\n\r\n[h5p id=\"78\"]\r\n\r\n<span style=\"color: #003366\"><strong>Solution: <\/strong><\/span><a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example30-2.xlsx\">Download the Excel solutions<\/a> or click below to reveal the solutions:\r\n\r\n[h5p id=\"80\"]\r\n\r\n<span style=\"color: #003366\"><strong>Conclusion: <\/strong><\/span>There is 0.25% chance that no shoppers will arrive in any given minute.\r\n<h1>Key Takeaways (EXERCISE)<\/h1>\r\n<div class=\"textbox textbox--key-takeaways\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Key Takeaways: Distribution Properties and Probabilities of Exactly 'X' Events<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[h5p id=\"84\"]\r\n\r\n[h5p id=\"85\"]\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Your Own Notes (EXERCISE)<\/h1>\r\n<ul>\r\n \t<li>Are there any notes you want to take from this section? Is there anything you'd like to copy and paste below?<\/li>\r\n \t<li>These notes are for you only (they will not be stored anywhere)<\/li>\r\n \t<li>Make sure to download them at the end to use as a reference<\/li>\r\n<\/ul>\r\n[h5p id=\"16\"]","rendered":"<div class=\"textbox textbox--learning-objectives\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Learning Objectives<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Understand what it means for events to follow a Poisson distribution and calculate the probability of [latex]x[\/latex] events occurring per time period using the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Poisson_distribution#:~:text=Probability%20mass%20function,-A%20discrete%20random&amp;text=The%20Poisson%20distribution%20can%20be,number%20with%20a%20Poisson%20distribution.\">Poisson Probability Mass Function<\/a>.<\/p>\n<\/div>\n<\/div>\n<h2>Five Properties of Poisson Distributions<\/h2>\n<ol>\n<li>There are only two possible outcomes for events \u2013 they can occur or not occur.<\/li>\n<li>Each event must be random and independent of the others.<\/li>\n<li>The occurrences must be uniformly distributed (see more in the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Continuous_uniform_distribution\">uniform distributions<\/a> section).<\/li>\n<li>Probabilities are calculated on the number of occurrences, [latex]x[\/latex], over a specific time interval.<\/li>\n<li>An average number of occurrences over a given time period is denoted as [latex]\\lambda[\/latex].<\/li>\n<\/ol>\n<h2>Two Ways of Calculating the Probability of &#8216;<em>x<\/em>&#8216; Successes<\/h2>\n<p>If we want to calculate the probability of exactly [latex]x[\/latex] events occurring per time period, we can:<\/p>\n<ol>\n<li><span style=\"color: #333333\">Use the formula<\/span>: [latex]P(x) = \\frac{{\\lambda}^x e^{-\\lambda}}{x!}[\/latex]<\/li>\n<li><span style=\"color: #333333\">Use Excel<\/span>: = <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], FALSE)<\/li>\n<\/ol>\n<h1>three examples of poisson distributions<\/h1>\n<p>Three examples of events that follow a Poisson Distribution:<\/p>\n<ol>\n<li>The number of bad checks received by a bank per day.<\/li>\n<li>The number of motor vehicle accidents in a busy street corner per week.<\/li>\n<li>The number of shoppers arriving at a supermarket check-out counter per minute.<\/li>\n<\/ol>\n<h1>Calculating the probability of x events using the Formula (ViDEO)<\/h1>\n<p>Let us better understand the Poisson formula by working through an example.<\/p>\n<h2>Example 30.1.1<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: On a busy Friday evening, the average number of shoppers arriving at a supermarket check-out counter waiting to be served by a cashier is 6 per minute. The arrivals follow a Poisson distribution.<\/p>\n<p><span style=\"color: #003366\"><strong>Question<\/strong><\/span>: In any given minute, what is the probability that exactly 5 shoppers will arrive?<\/p>\n<p><span style=\"color: #003366\"><strong>Written solution:<\/strong><\/span>\u00a0Let us look at the formula a little more carefully now.<\/p>\n<ul>\n<li>There are really only 2 variables in this formula.<\/li>\n<li>One is [latex]\\lambda[\/latex], the average; in this example, which is 6.<\/li>\n<li>The other is [latex]x[\/latex], the number for which we want to find the probability.\u00a0 In this example it is 5.<\/li>\n<li>The other letter, [latex]e[\/latex], is a constant. It is the base of the natural log and equal 2.71828.<\/li>\n<li>This gives: \\[P(x=5) =\\frac{6^5 e^{-6}}{5!}=\\frac{(7,776) \\times (0.002478752)}{ 120}=0.1606\\]<\/li>\n<\/ul>\n<p><span style=\"color: #003366\"><strong>Video solution:<\/strong><\/span> <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example_30-1-1_First_Poisson_Formula_Example_Written_Solution.jpg\">Click here<\/a> to download the written solutions to the video below:<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"How to use Poisson&#39;s Probability Mass Function to calculate the probability of exactly no arrivals.\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/JPv_ZJVgOqo?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><span style=\"color: #003366\"><strong>Conclusion:<\/strong><\/span> There is a 16.06% chance that 5 shoppers will arrive in any given minute.<\/p>\n<h1>Calculating the probability of x events using Excel (ViDEO)<\/h1>\n<p>Let us now use Excel&#8217;s <a href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a> function to solve the above example.<\/p>\n<h2>Example 30.1.2<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: Let us now use Excel to solve for the following problem:<\/p>\n<ul>\n<li>An average of 6 shoppers arrive per minute at the till.<\/li>\n<li>Solve for the probability of exactly\u00a05 shoppers will arriving in any given minute.<\/li>\n<\/ul>\n<p><span style=\"color: #003366\"><strong>Solution:<\/strong><\/span> Use = POISSON.DIST(5, 6, 0). <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example30-1.xlsx\">Click here<\/a> to download the Excel solutions shown below:<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Using Excel&#39;s POISSON.DIST() function to calculate the odds of exactly &#39;x&#39; events occurring\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/Vi3tz_FGuvQ?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><span style=\"color: #003366\"><strong>Conclusion<\/strong><\/span>: There is a 16.06% chance that exactly 5 shoppers will arrive in any given minute.<\/p>\n<p><span style=\"color: #003366\"><strong>Note<\/strong><\/span>: When using Excel&#8217;s <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>(), we set cumulative = FALSE when calculating the probability of exactly [latex]x[\/latex] events occurring. We will examine when we use cumulative = TRUE in later sections in this Chapter.<\/p>\n<h1>Calculating the probability of No events w\/ Formula (Exercise)<\/h1>\n<p>In the first case, it was \u2018a busy Friday evening.\u2019 Let\u2019s find out why in the next example<span style=\"font-size: 20.5333px\">.<\/span><\/p>\n<h2>Example 30.2.1<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: An<span style=\"font-size: 20.5333px\"> average of 6 shoppers arrive per minute at the check-out counter.\u00a0<\/span><\/p>\n<p><span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>In any given minute, what is the probability that no shoppers arrive at the counter?<\/p>\n<p><strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Solve the problem by placing the values in the correct positions below:<\/p>\n<div id=\"h5p-79\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-79\" class=\"h5p-iframe\" data-content-id=\"79\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Example 28.2.1 \u2013 Poisson - Using Formula - Exactly Equal To\"><\/iframe><\/div>\n<\/div>\n<div>\n<h1>Click here to reveal written solution:<\/h1>\n<ul>\n<li>If no shoppers arrive, then we know that [latex]x = 0[\/latex]<\/li>\n<li>We also know that the average arrival rate:\u00a0[latex]\\lambda = 6[\/latex]<\/li>\n<li>We use the formula: [latex]P(x) = \\frac{{\\lambda}^x e^{-\\lambda}}{x!}[\/latex] and add the above values in.<\/li>\n<li>This gives: [latex]P(x=0) =\\frac{6^0 \\times e^{-6}}{0!}[\/latex]<\/li>\n<li>We know that: [latex]6^0 = 1[\/latex], [latex]0! = 1[\/latex], and [latex]e^{-6} = 0.0025[\/latex]<\/li>\n<li>This gives: [latex]P(x=0) =\\frac{1 \\times 0.0025}{ 1}=0.0025[\/latex]<\/li>\n<\/ul>\n<\/div>\n<p><span style=\"color: #003366\"><strong>Conclusion: <\/strong><\/span>There is 0.25% chance that no shoppers will arrive in any given minute. In other words, there is almost NO chance that there are no shoppers arriving. This means that shoppers are almost constantly arriving, keeping the cashier busy.<\/p>\n<h1>Calculating the probability of No events using Excel (Exercise)<\/h1>\n<p>Let us now use Excel&#8217;s <a href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a> function to solve the above example. This time, I&#8217;m going to put you to work in setting up the Excel formula.<\/p>\n<h2>Example 30.2.2<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: An<span style=\"font-size: 20.5333px\"> average of 6 shoppers arrive per minute at a till, ready to check out.\u00a0<\/span><\/p>\n<p><span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>In any given minute, what is the probability that there are no shoppers arriving at this check-out counter? Can you set up the problem in Excel?<\/p>\n<p><strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Complete the exercise below to calculate the probability of no shoppers arriving:<\/p>\n<div id=\"h5p-78\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-78\" class=\"h5p-iframe\" data-content-id=\"78\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Example 32.2 \u2013 Poisson - Using Excel - More Than\"><\/iframe><\/div>\n<\/div>\n<p><span style=\"color: #003366\"><strong>Solution: <\/strong><\/span><a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example30-2.xlsx\">Download the Excel solutions<\/a> or click below to reveal the solutions:<\/p>\n<div id=\"h5p-80\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-80\" class=\"h5p-iframe\" data-content-id=\"80\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Example 30.2.2 \u2013 Poisson - Using Excel - Exactly Equal To Solution\"><\/iframe><\/div>\n<\/div>\n<p><span style=\"color: #003366\"><strong>Conclusion: <\/strong><\/span>There is 0.25% chance that no shoppers will arrive in any given minute.<\/p>\n<h1>Key Takeaways (EXERCISE)<\/h1>\n<div class=\"textbox textbox--key-takeaways\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Key Takeaways: Distribution Properties and Probabilities of Exactly &#8216;X&#8217; Events<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<div id=\"h5p-84\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-84\" class=\"h5p-iframe\" data-content-id=\"84\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"An Introduction to Poisson Distributions Key Takeaways\"><\/iframe><\/div>\n<\/div>\n<div id=\"h5p-85\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-85\" class=\"h5p-iframe\" data-content-id=\"85\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"An Introduction to Poisson Distributions Key Takeaways Solutions\"><\/iframe><\/div>\n<\/div>\n<\/div>\n<\/div>\n<h1>Your Own Notes (EXERCISE)<\/h1>\n<ul>\n<li>Are there any notes you want to take from this section? Is there anything you&#8217;d like to copy and paste below?<\/li>\n<li>These notes are for you only (they will not be stored anywhere)<\/li>\n<li>Make sure to download them at the end to use as a reference<\/li>\n<\/ul>\n<div id=\"h5p-16\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-16\" class=\"h5p-iframe\" data-content-id=\"16\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Key takeaways, notes and comments from this section document tool.\"><\/iframe><\/div>\n<\/div>\n","protected":false},"author":865,"menu_order":1,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1528","chapter","type-chapter","status-publish","hentry"],"part":237,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1528","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/users\/865"}],"version-history":[{"count":25,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1528\/revisions"}],"predecessor-version":[{"id":1957,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1528\/revisions\/1957"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/parts\/237"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1528\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/media?parent=1528"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapter-type?post=1528"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/contributor?post=1528"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/license?post=1528"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}