{"id":1603,"date":"2024-05-14T22:51:23","date_gmt":"2024-05-15T02:51:23","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/?post_type=chapter&#038;p=1603"},"modified":"2024-06-12T14:47:29","modified_gmt":"2024-06-12T18:47:29","slug":"at-most-and-at-least","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/chapter\/at-most-and-at-least\/","title":{"raw":"Calculating At Least, At Most and More Than 'X' Events","rendered":"Calculating At Least, At Most and More Than &#8216;X&#8217; Events"},"content":{"raw":"<div class=\"textbox textbox--learning-objectives\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Learning Objectives<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nCalculate the probability of at least, at most or more than a certain number of events, [latex]x[\/latex].\r\n\r\n<\/div>\r\n<\/div>\r\n<h2>Calculating the Probability of At Most '<em>X<\/em>' Events Occurring<\/h2>\r\n<ol>\r\n \t<li><span style=\"color: #333333\">Use <a href=\"https:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda366j.htm\">the formula<\/a> to calculate each probability up to and including x<\/span>: [latex]P(X\\le x) = P(X=0)+P(X=1)+...+P(X=x)[\/latex]<\/li>\r\n \t<li><span style=\"color: #333333\">Use cumulative = [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\le x)[\/latex] = <span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\r\n<\/ol>\r\n<em>Which is better?<\/em> It is often much quicker to use Excel's <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>\u00a0than <a href=\"https:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda366j.htm\">the formula<\/a>.\r\n<h2>Calculating the Probability of More Than '<em>X<\/em>' Events Occurring<\/h2>\r\n<ol>\r\n \t<li><span style=\"color: #333333\">Use the formula and a complement to calculate<\/span>: [latex]P(X\\gt x) = 1-[P(0)+P(1)+...+P(x)][\/latex]<\/li>\r\n \t<li><span style=\"color: #333333\">Use a complement and [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\gt x) =1\u2212[\/latex]<span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\r\n<\/ol>\r\n<em>Why use a complement<\/em>? Since there is no upper limit to the number of events that can occur, [latex]P(X\\gt x) = P(x+1)+P(x+2)+...+P(\\infty)[\/latex]. We cannot perform this calculation without using limit theory. Instead, we use a complement of up to the probability of [latex]x[\/latex] events occurring.\r\n<h2>Calculating the Probability of At Least '<em>X<\/em>' Events Occurring<\/h2>\r\n<ol>\r\n \t<li><span style=\"color: #333333\">Use the formula and a complement<\/span>: [latex]P(X\\ge x) = 1-[P(0)+P(1)+...+P(x-1)][\/latex]<\/li>\r\n \t<li><span style=\"color: #333333\">Use a complement and [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\ge x)[\/latex] =\u00a01\u2212 <span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x-1[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\r\n<\/ol>\r\n<em>Why do we use <\/em>[latex]x-1[\/latex]\u00a0<em>instead of<\/em> [latex]x[\/latex]? Since [latex]x[\/latex] is included in the interval, it needs to be excluded when taking the complement. Ie: [latex]P(X\\ge x) = 1-P(X \\lt x) = 1-P(X \\le x-1)[\/latex]\r\n<h1>'At MOST' Example (VIDEO)<\/h1>\r\n<ul>\r\n \t<li>It is important to stress that we must always match the time units.<\/li>\r\n \t<li>In the example from the previous section, the average arrival rate was given per minute.<\/li>\r\n \t<li>The question's time interval was also one minute: \"What is the probability of 5 customers arriving in any given minute.\"<\/li>\r\n \t<li>So, no adjustment of lambda ([latex]\\lambda[\/latex]) was needed since the time intervals matched.<\/li>\r\n \t<li>See the next example to see where an adjustment of [latex]\\lambda[\/latex] is needed.<\/li>\r\n<\/ul>\r\n<h2>Example 32.1<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: The <a href=\"https:\/\/antifraudcentre-centreantifraude.ca\/index-eng.htm\">Canadian Anti-Fraud Centre<\/a> received an average of 3,578 <a href=\"https:\/\/www.rcmp-grc.gc.ca\/en\/news\/2023\/fraud-prevention-month-2023-fraud-losses-canada-reach-historic-level\">reports of fraud<\/a> per month so far in 2024, with losses totaling $123,000,000 in the first quarter of 2024 alone!\r\n\r\n<span style=\"color: #003366\"><strong>Question<\/strong><\/span>: If we assume that the number of frauds reported to the Canadian Anti-Fraud Centre follows a Poisson distribution, what is the probability of there being at most 3,578 frauds reported in the month of May?\r\n\r\n<span style=\"color: #003366\"><strong>Solutions<\/strong><\/span>: <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-1.xlsx\">Click here<\/a>\u00a0to download the Excel solutions shown in the video below:\r\n\r\nhttps:\/\/youtu.be\/vyQ-3KOl8yk\r\n\r\n<span style=\"color: #003366\"><strong>Conclusion:<\/strong><\/span> We use =POISSON.DIST(3578, 3578, TRUE). This gives a 50.44% chance that the number of reports received by the Anti-Fraud Centre in the month of May do not exceed the monthly average for 2024 to date.\r\n<h1>'More than' Example (EXERCISE)<\/h1>\r\nLet us now review how to calculate the probability of more than [latex]x[\/latex] events occurring during a certain time frame in the exercise in the next example<span style=\"font-size: 20.5333px\">.<\/span>\r\n<h2>Example 32.2<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: The Canadian Anti-Fraud Centre reports an average of 2,636 victims of fraud per month so far in 2024.<span style=\"font-size: 20.5333px\"> They reported a total of 41,988 victims in 2023 (or 3,499 victims per month).\u00a0 Let us assume that the number of victims of fraud in 2024 follows a Poisson distribution with an average of 2,636 victims per month.<\/span>\r\n\r\n<span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>What is the probability of there being more than 3,499 victims of fraud in any given month in 2024? Ie: What is the probability that any given month in 2024, the number of victims of fraud will exceed the monthly average for 2023?\r\n\r\n<strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Solve the above problem by placing the values in the correct positions below:\r\n\r\n[h5p id=\"83\"]\r\n<div>\r\n<h1>Click here to reveal the solutions:<\/h1>\r\n<ul>\r\n \t<li>We will set [latex]\\lambda = 2636[\/latex] and calculate [latex]P(x \\gt 3499)[\/latex].<\/li>\r\n \t<li>This gives: [latex] P(x \\gt 3499) = 1 - P(x \\le 3499) = 1-\\text{POISSON.DIST(}3499, 2636, TRUE) = 0.0000[\/latex]<\/li>\r\n \t<li><a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-2.xlsx\">Click here<\/a>\u00a0to download the Excel solutions for this problem.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<h1>'At Least' Example (Video)<\/h1>\r\n<ul>\r\n \t<li>Finally, we will practice calculating the probability of 'at least' [latex]x[\/latex] events in a certain time-frame.<\/li>\r\n \t<li>See the next example for a video walk-through of how to calculate [latex]P(X \\ge x)[\/latex] in Excel<span style=\"font-size: 20.5333px\">.<\/span><\/li>\r\n<\/ul>\r\n<h2>Example 32.3<\/h2>\r\n<span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: There are, on average, 28,000 bankruptcies filed in Canada per year according to the <a href=\"https:\/\/ised-isde.canada.ca\/site\/office-superintendent-bankruptcy\/en\/statistics-and-research\/insolvency-statistics-canada-march-2023#t2\">Office of the Superintendent of Bankruptcy<\/a> in Canada<span style=\"font-size: 20.5333px\">.<\/span>\r\n\r\n<span style=\"color: #003366\"><strong>Question:<\/strong> <\/span><span style=\"font-size: 20.5333px\">If the number of bankruptcies follows a Poisson distribution, what is<\/span> the probability of at least 2,400 bankruptcies getting filed in any given month in Canada?\r\n\r\n<span style=\"color: #003366\"><strong>Solution:<\/strong><\/span> Use = 1\u2212 POISSON.DIST(2399, 28000\/12, TRUE). <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-3.xlsx\">Click here<\/a>\u00a0to download the Excel solutions shown below:\r\n\r\nhttps:\/\/youtu.be\/Yqb_d-pnTIc\r\n<h1>Key Takeaways (EXERCISE)<\/h1>\r\n<div class=\"textbox textbox--key-takeaways\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Key Takeaways: Calculating At Least, At Most and More Than 'X' Events<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[h5p id=\"88\"]\r\n\r\n[h5p id=\"89\"]\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Your Own Notes (EXERCISE)<\/h1>\r\n<ul>\r\n \t<li>Are there any notes you want to take from this section? Is there anything you'd like to copy and paste below?<\/li>\r\n \t<li>These notes are for you only (they will not be stored anywhere)<\/li>\r\n \t<li>Make sure to download them at the end to use as a reference<\/li>\r\n<\/ul>\r\n[h5p id=\"16\"]","rendered":"<div class=\"textbox textbox--learning-objectives\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Learning Objectives<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Calculate the probability of at least, at most or more than a certain number of events, [latex]x[\/latex].<\/p>\n<\/div>\n<\/div>\n<h2>Calculating the Probability of At Most &#8216;<em>X<\/em>&#8216; Events Occurring<\/h2>\n<ol>\n<li><span style=\"color: #333333\">Use <a href=\"https:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda366j.htm\">the formula<\/a> to calculate each probability up to and including x<\/span>: [latex]P(X\\le x) = P(X=0)+P(X=1)+...+P(X=x)[\/latex]<\/li>\n<li><span style=\"color: #333333\">Use cumulative = [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\le x)[\/latex] = <span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\n<\/ol>\n<p><em>Which is better?<\/em> It is often much quicker to use Excel&#8217;s <span style=\"background-color: #ffffff;color: #000000\"><a style=\"background-color: #ffffff;color: #000000\" href=\"https:\/\/support.microsoft.com\/en-us\/office\/poisson-dist-function-8fe148ff-39a2-46cb-abf3-7772695d9636\">POISSON.DIST<\/a><\/span>\u00a0than <a href=\"https:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda366j.htm\">the formula<\/a>.<\/p>\n<h2>Calculating the Probability of More Than &#8216;<em>X<\/em>&#8216; Events Occurring<\/h2>\n<ol>\n<li><span style=\"color: #333333\">Use the formula and a complement to calculate<\/span>: [latex]P(X\\gt x) = 1-[P(0)+P(1)+...+P(x)][\/latex]<\/li>\n<li><span style=\"color: #333333\">Use a complement and [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\gt x) =1\u2212[\/latex]<span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\n<\/ol>\n<p><em>Why use a complement<\/em>? Since there is no upper limit to the number of events that can occur, [latex]P(X\\gt x) = P(x+1)+P(x+2)+...+P(\\infty)[\/latex]. We cannot perform this calculation without using limit theory. Instead, we use a complement of up to the probability of [latex]x[\/latex] events occurring.<\/p>\n<h2>Calculating the Probability of At Least &#8216;<em>X<\/em>&#8216; Events Occurring<\/h2>\n<ol>\n<li><span style=\"color: #333333\">Use the formula and a complement<\/span>: [latex]P(X\\ge x) = 1-[P(0)+P(1)+...+P(x-1)][\/latex]<\/li>\n<li><span style=\"color: #333333\">Use a complement and [latex]TRUE[\/latex] in Excel<\/span>: [latex]P(X\\ge x)[\/latex] =\u00a01\u2212 <span style=\"background-color: #ffffff;color: #000000\">POISSON.DIST<\/span>([latex]x-1[\/latex], [latex]\\lambda[\/latex], TRUE)<\/li>\n<\/ol>\n<p><em>Why do we use <\/em>[latex]x-1[\/latex]\u00a0<em>instead of<\/em> [latex]x[\/latex]? Since [latex]x[\/latex] is included in the interval, it needs to be excluded when taking the complement. Ie: [latex]P(X\\ge x) = 1-P(X \\lt x) = 1-P(X \\le x-1)[\/latex]<\/p>\n<h1>&#8216;At MOST&#8217; Example (VIDEO)<\/h1>\n<ul>\n<li>It is important to stress that we must always match the time units.<\/li>\n<li>In the example from the previous section, the average arrival rate was given per minute.<\/li>\n<li>The question&#8217;s time interval was also one minute: &#8220;What is the probability of 5 customers arriving in any given minute.&#8221;<\/li>\n<li>So, no adjustment of lambda ([latex]\\lambda[\/latex]) was needed since the time intervals matched.<\/li>\n<li>See the next example to see where an adjustment of [latex]\\lambda[\/latex] is needed.<\/li>\n<\/ul>\n<h2>Example 32.1<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: The <a href=\"https:\/\/antifraudcentre-centreantifraude.ca\/index-eng.htm\">Canadian Anti-Fraud Centre<\/a> received an average of 3,578 <a href=\"https:\/\/www.rcmp-grc.gc.ca\/en\/news\/2023\/fraud-prevention-month-2023-fraud-losses-canada-reach-historic-level\">reports of fraud<\/a> per month so far in 2024, with losses totaling $123,000,000 in the first quarter of 2024 alone!<\/p>\n<p><span style=\"color: #003366\"><strong>Question<\/strong><\/span>: If we assume that the number of frauds reported to the Canadian Anti-Fraud Centre follows a Poisson distribution, what is the probability of there being at most 3,578 frauds reported in the month of May?<\/p>\n<p><span style=\"color: #003366\"><strong>Solutions<\/strong><\/span>: <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-1.xlsx\">Click here<\/a>\u00a0to download the Excel solutions shown in the video below:<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"How to calculate at most a certain number of frauds reported using Poisson.Dist() in Excel.\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/vyQ-3KOl8yk?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><span style=\"color: #003366\"><strong>Conclusion:<\/strong><\/span> We use =POISSON.DIST(3578, 3578, TRUE). This gives a 50.44% chance that the number of reports received by the Anti-Fraud Centre in the month of May do not exceed the monthly average for 2024 to date.<\/p>\n<h1>&#8216;More than&#8217; Example (EXERCISE)<\/h1>\n<p>Let us now review how to calculate the probability of more than [latex]x[\/latex] events occurring during a certain time frame in the exercise in the next example<span style=\"font-size: 20.5333px\">.<\/span><\/p>\n<h2>Example 32.2<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: The Canadian Anti-Fraud Centre reports an average of 2,636 victims of fraud per month so far in 2024.<span style=\"font-size: 20.5333px\"> They reported a total of 41,988 victims in 2023 (or 3,499 victims per month).\u00a0 Let us assume that the number of victims of fraud in 2024 follows a Poisson distribution with an average of 2,636 victims per month.<\/span><\/p>\n<p><span style=\"color: #003366\"><strong>Question:<\/strong> <\/span>What is the probability of there being more than 3,499 victims of fraud in any given month in 2024? Ie: What is the probability that any given month in 2024, the number of victims of fraud will exceed the monthly average for 2023?<\/p>\n<p><strong><span style=\"color: #003366\">You Try<\/span><\/strong>: Solve the above problem by placing the values in the correct positions below:<\/p>\n<div id=\"h5p-83\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-83\" class=\"h5p-iframe\" data-content-id=\"83\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Example 32.2 \u2013 Poisson - Using Excel - More Than\"><\/iframe><\/div>\n<\/div>\n<div>\n<h1>Click here to reveal the solutions:<\/h1>\n<ul>\n<li>We will set [latex]\\lambda = 2636[\/latex] and calculate [latex]P(x \\gt 3499)[\/latex].<\/li>\n<li>This gives: [latex]P(x \\gt 3499) = 1 - P(x \\le 3499) = 1-\\text{POISSON.DIST(}3499, 2636, TRUE) = 0.0000[\/latex]<\/li>\n<li><a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-2.xlsx\">Click here<\/a>\u00a0to download the Excel solutions for this problem.<\/li>\n<\/ul>\n<\/div>\n<h1>&#8216;At Least&#8217; Example (Video)<\/h1>\n<ul>\n<li>Finally, we will practice calculating the probability of &#8216;at least&#8217; [latex]x[\/latex] events in a certain time-frame.<\/li>\n<li>See the next example for a video walk-through of how to calculate [latex]P(X \\ge x)[\/latex] in Excel<span style=\"font-size: 20.5333px\">.<\/span><\/li>\n<\/ul>\n<h2>Example 32.3<\/h2>\n<p><span style=\"color: #003366\"><strong>Problem Setup<\/strong><\/span>: There are, on average, 28,000 bankruptcies filed in Canada per year according to the <a href=\"https:\/\/ised-isde.canada.ca\/site\/office-superintendent-bankruptcy\/en\/statistics-and-research\/insolvency-statistics-canada-march-2023#t2\">Office of the Superintendent of Bankruptcy<\/a> in Canada<span style=\"font-size: 20.5333px\">.<\/span><\/p>\n<p><span style=\"color: #003366\"><strong>Question:<\/strong> <\/span><span style=\"font-size: 20.5333px\">If the number of bankruptcies follows a Poisson distribution, what is<\/span> the probability of at least 2,400 bankruptcies getting filed in any given month in Canada?<\/p>\n<p><span style=\"color: #003366\"><strong>Solution:<\/strong><\/span> Use = 1\u2212 POISSON.DIST(2399, 28000\/12, TRUE). <a href=\"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-content\/uploads\/sites\/2128\/2024\/05\/Example32-3.xlsx\">Click here<\/a>\u00a0to download the Excel solutions shown below:<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"How to calculate the probability of at least a certain number of events using Excel&#39;s POISSON.DIST\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/Yqb_d-pnTIc?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h1>Key Takeaways (EXERCISE)<\/h1>\n<div class=\"textbox textbox--key-takeaways\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Key Takeaways: Calculating At Least, At Most and More Than &#8216;X&#8217; Events<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<div id=\"h5p-88\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-88\" class=\"h5p-iframe\" data-content-id=\"88\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Calculating At Least, At Most and More Than &#039;X&#039; Events Key Takeaways\"><\/iframe><\/div>\n<\/div>\n<div id=\"h5p-89\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-89\" class=\"h5p-iframe\" data-content-id=\"89\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Calculating At Least, At Most and More Than &#039;X&#039; Events Key Takeaways Solutions\"><\/iframe><\/div>\n<\/div>\n<\/div>\n<\/div>\n<h1>Your Own Notes (EXERCISE)<\/h1>\n<ul>\n<li>Are there any notes you want to take from this section? Is there anything you&#8217;d like to copy and paste below?<\/li>\n<li>These notes are for you only (they will not be stored anywhere)<\/li>\n<li>Make sure to download them at the end to use as a reference<\/li>\n<\/ul>\n<div id=\"h5p-16\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-16\" class=\"h5p-iframe\" data-content-id=\"16\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Key takeaways, notes and comments from this section document tool.\"><\/iframe><\/div>\n<\/div>\n","protected":false},"author":865,"menu_order":3,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1603","chapter","type-chapter","status-publish","hentry"],"part":237,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1603","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/users\/865"}],"version-history":[{"count":25,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1603\/revisions"}],"predecessor-version":[{"id":1959,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1603\/revisions\/1959"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/parts\/237"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapters\/1603\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/media?parent=1603"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/pressbooks\/v2\/chapter-type?post=1603"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/contributor?post=1603"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/1130sandbox\/wp-json\/wp\/v2\/license?post=1603"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}