{"id":73,"date":"2022-02-07T21:13:52","date_gmt":"2022-02-08T02:13:52","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/?post_type=chapter&#038;p=73"},"modified":"2025-06-03T19:11:31","modified_gmt":"2025-06-03T23:11:31","slug":"covalent-bonds","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/chapter\/covalent-bonds\/","title":{"raw":"Covalent bonds","rendered":"Covalent bonds"},"content":{"raw":"Atoms with similar electronegativities will not transfer electrons to form an ionic bond between one another. Instead, they may <strong>share <\/strong>electrons to form a <strong>covalent bond<\/strong>. For example, carbon (C) has an atomic number of 6 and hydrogen (H) has an atomic number of 1. The valence shell of C is the second shell and it is <em>half-full<\/em>. The valence shell of H is the first shell and it is also <em>half-full<\/em>. Therefore, these atoms have <strong>similar electronegativities<\/strong>. When they come into proximity of one another, the valence electrons of C will complete the valence of H atoms and vice versa. Because these atoms pull on the shared electrons with <em>equal force<\/em>, the bonds between C and H are <strong>nonpolar covalent bonds<\/strong>. The electrons are shared equally between the bonding partners.\r\n\r\n<a id=\"covalent-bonds\"><\/a>In contrast, oxygen (O) has an atomic number of 8 and its valence shell is the second shell. O is much closer to filling its valence shell than H; therefore, <strong>O is more electronegative than H<\/strong>. O and H can react to form water (H<sub>2<\/sub>O). In water, O and H will <em>share <\/em>their valence electrons to fill each other\u2019s valence shells. However, because O pulls on electrons with more force, the shared electrons tend to reside with O more often than with either H atom. That means that O carries a <strong>partial negative charge (\u03b4<\/strong><strong>-) <\/strong>and C carries a <strong>partial positive charge<\/strong> <strong>(\u03b4<\/strong><strong>+)<\/strong>, resulting in a <strong>polar covalent bond<\/strong> between the atoms. Covalent bonds are relatively strong bonds as compared to electrostatic interactions such as ionic or hydrogen bonds.\r\n\r\n&nbsp;\r\n<div class=\"activity-title\"><strong>Activity:<\/strong> Drag and drop the correct type of covalent bonds that form methane (left) and water (right).<\/div>\r\n[h5p id=\"67\"]\r\n<div class=\"important-section\">\r\n<p class=\"important-section-title\"><strong>IMPORTANT<\/strong>: Molecules and compounds are not the same thing!<\/p>\r\n<p class=\"important-section-body\">The atoms in molecules are joined by <strong>covalent bonds<\/strong>. Compounds contain two different atoms joined by either covalent or ionic bonds. Molecular oxygen (O<sub>2<\/sub>) is a molecule containing two of the same atoms joined by <strong>nonpolar covalent bonds<\/strong>. However, O<sub>2<\/sub> is not a compound because it contains only one type of atom. Water (H<sub>2<\/sub>O) is both a molecule and a compound because the atoms in water are joined by covalent bonds and it contains two different atoms: O and H.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"activity-title\"><strong>Activity:<\/strong> Read the statements below and decide whether the statements are true or false.<\/div>\r\n[h5p id=\"55\"]\r\n[h5p id=\"56\"]\r\n<div class=\"chemistry-in-clinic\">\r\n<p class=\"chemistry-title\">Chemistry in the clinic:<\/p>\r\n<p class=\"chemistry-body\">The <strong>polarity<\/strong> of a molecule is determined by the polarity of the covalent bonds within the molecule as well as the way the bonds are arranged. For example, <strong>carbon dioxide <\/strong>(CO<sub>2<\/sub>) is a <strong>nonpolar molecule<\/strong>, despite containing two atoms with very different electronegativities. In CO<sub>2<\/sub>, carbon forms two double bonds to each of the two oxygen atoms. Because the electron pairs strongly repel one another, CO<sub>2<\/sub> takes on a linear shape (Figure 8). The two oxygens face away from one another symmetrically, effectively <em>cancelling the polarity of the C-O bonds<\/em>. For this reason, CO<sub>2<\/sub> is poorly soluble in aqueous solutions such as blood plasma. You will learn in a future lecture on blood that CO<sub>2<\/sub> must be converted into a soluble compound called carbonic acid (H<sub>2<\/sub>CO<sub>3<\/sub>) by the action of an enzyme called <strong>carbonic anhydrase<\/strong> in red blood cells.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n\r\n[caption id=\"attachment_481\" align=\"aligncenter\" width=\"620\"]<img class=\"wp-image-481\" src=\"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-300x150.png\" alt=\"Figure 8. Carbon dioxide is a linear, nonpolar molecule\" width=\"620\" height=\"310\" \/> Figure 8. Carbon dioxide is a linear, nonpolar molecule[\/caption]","rendered":"<p>Atoms with similar electronegativities will not transfer electrons to form an ionic bond between one another. Instead, they may <strong>share <\/strong>electrons to form a <strong>covalent bond<\/strong>. For example, carbon (C) has an atomic number of 6 and hydrogen (H) has an atomic number of 1. The valence shell of C is the second shell and it is <em>half-full<\/em>. The valence shell of H is the first shell and it is also <em>half-full<\/em>. Therefore, these atoms have <strong>similar electronegativities<\/strong>. When they come into proximity of one another, the valence electrons of C will complete the valence of H atoms and vice versa. Because these atoms pull on the shared electrons with <em>equal force<\/em>, the bonds between C and H are <strong>nonpolar covalent bonds<\/strong>. The electrons are shared equally between the bonding partners.<\/p>\n<p><a id=\"covalent-bonds\"><\/a>In contrast, oxygen (O) has an atomic number of 8 and its valence shell is the second shell. O is much closer to filling its valence shell than H; therefore, <strong>O is more electronegative than H<\/strong>. O and H can react to form water (H<sub>2<\/sub>O). In water, O and H will <em>share <\/em>their valence electrons to fill each other\u2019s valence shells. However, because O pulls on electrons with more force, the shared electrons tend to reside with O more often than with either H atom. That means that O carries a <strong>partial negative charge (\u03b4<\/strong><strong>-) <\/strong>and C carries a <strong>partial positive charge<\/strong> <strong>(\u03b4<\/strong><strong>+)<\/strong>, resulting in a <strong>polar covalent bond<\/strong> between the atoms. Covalent bonds are relatively strong bonds as compared to electrostatic interactions such as ionic or hydrogen bonds.<\/p>\n<p>&nbsp;<\/p>\n<div class=\"activity-title\"><strong>Activity:<\/strong> Drag and drop the correct type of covalent bonds that form methane (left) and water (right).<\/div>\n<div id=\"h5p-67\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-67\" class=\"h5p-iframe\" data-content-id=\"67\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Activity 4 (covalent bonds): Drag and drop the correct type of covalent bonds that form methane (left) and water (right).\"><\/iframe><\/div>\n<\/div>\n<div class=\"important-section\">\n<p class=\"important-section-title\"><strong>IMPORTANT<\/strong>: Molecules and compounds are not the same thing!<\/p>\n<p class=\"important-section-body\">The atoms in molecules are joined by <strong>covalent bonds<\/strong>. Compounds contain two different atoms joined by either covalent or ionic bonds. Molecular oxygen (O<sub>2<\/sub>) is a molecule containing two of the same atoms joined by <strong>nonpolar covalent bonds<\/strong>. However, O<sub>2<\/sub> is not a compound because it contains only one type of atom. Water (H<sub>2<\/sub>O) is both a molecule and a compound because the atoms in water are joined by covalent bonds and it contains two different atoms: O and H.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"activity-title\"><strong>Activity:<\/strong> Read the statements below and decide whether the statements are true or false.<\/div>\n<div id=\"h5p-55\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-55\" class=\"h5p-iframe\" data-content-id=\"55\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Chapter 2 Covalent Bonds - Activity #2 - Q1\"><\/iframe><\/div>\n<\/div>\n<div id=\"h5p-56\">\n<div class=\"h5p-iframe-wrapper\"><iframe id=\"h5p-iframe-56\" class=\"h5p-iframe\" data-content-id=\"56\" style=\"height:1px\" src=\"about:blank\" frameBorder=\"0\" scrolling=\"no\" title=\"Chapter 2 Covalent Bonds - Activity #2 - Q2\"><\/iframe><\/div>\n<\/div>\n<div class=\"chemistry-in-clinic\">\n<p class=\"chemistry-title\">Chemistry in the clinic:<\/p>\n<p class=\"chemistry-body\">The <strong>polarity<\/strong> of a molecule is determined by the polarity of the covalent bonds within the molecule as well as the way the bonds are arranged. For example, <strong>carbon dioxide <\/strong>(CO<sub>2<\/sub>) is a <strong>nonpolar molecule<\/strong>, despite containing two atoms with very different electronegativities. In CO<sub>2<\/sub>, carbon forms two double bonds to each of the two oxygen atoms. Because the electron pairs strongly repel one another, CO<sub>2<\/sub> takes on a linear shape (Figure 8). The two oxygens face away from one another symmetrically, effectively <em>cancelling the polarity of the C-O bonds<\/em>. For this reason, CO<sub>2<\/sub> is poorly soluble in aqueous solutions such as blood plasma. You will learn in a future lecture on blood that CO<sub>2<\/sub> must be converted into a soluble compound called carbonic acid (H<sub>2<\/sub>CO<sub>3<\/sub>) by the action of an enzyme called <strong>carbonic anhydrase<\/strong> in red blood cells.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<figure id=\"attachment_481\" aria-describedby=\"caption-attachment-481\" style=\"width: 620px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-481\" src=\"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-300x150.png\" alt=\"Figure 8. Carbon dioxide is a linear, nonpolar molecule\" width=\"620\" height=\"310\" srcset=\"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-300x150.png 300w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-1024x512.png 1024w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-768x384.png 768w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-65x33.png 65w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-225x113.png 225w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14-350x175.png 350w, https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-content\/uploads\/sites\/1545\/2022\/02\/Artboard-14.png 1080w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><figcaption id=\"caption-attachment-481\" class=\"wp-caption-text\">Figure 8. Carbon dioxide is a linear, nonpolar molecule<\/figcaption><\/figure>\n","protected":false},"author":1456,"menu_order":2,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-73","chapter","type-chapter","status-publish","hentry"],"part":35,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapters\/73","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/wp\/v2\/users\/1456"}],"version-history":[{"count":25,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapters\/73\/revisions"}],"predecessor-version":[{"id":559,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapters\/73\/revisions\/559"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/parts\/35"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapters\/73\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/wp\/v2\/media?parent=73"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=73"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/wp\/v2\/contributor?post=73"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/biology1190chemistry\/wp-json\/wp\/v2\/license?post=73"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}