{"id":2024,"date":"2018-04-11T23:47:49","date_gmt":"2018-04-12T03:47:49","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/back-matter\/appendix-b-essential-mathematics\/"},"modified":"2018-06-23T01:02:20","modified_gmt":"2018-06-23T05:02:20","slug":"appendix-b-essential-mathematics","status":"publish","type":"back-matter","link":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/back-matter\/appendix-b-essential-mathematics\/","title":{"raw":"Appendix B: Essential Mathematics","rendered":"Appendix B: Essential Mathematics"},"content":{"raw":"
\r\n

Exponential Arithmetic<\/h1>\r\n

Exponential notation is used to express very large and very small numbers as a product of two numbers. The first number of the product, the digit term<\/em>, is usually a number not less than 1 and not greater than 10. The second number of the product, the exponential term<\/em>, is written as 10 with an exponent. Some examples of exponential notation are:<\/p>\r\n\r\n

$latex \\begin{array}{r @{{}={}} l} 1000 & 1\\;\\times\\;10^3 \\\\[0.75em] 100 & 1\\;\\times\\;10^2 \\\\[0.75em] 10 & 1\\;\\times\\;10^1 \\\\[0.75em] 1 & 1\\;\\times\\;10^0 \\\\[0.75em] 0.1 & 1\\;\\times\\;10^{-1} \\\\[0.75em] 0.001 & 1\\;\\times\\;10^{-3} \\\\[0.75em] 2386 & 2.386\\;\\times\\;1000 = 2.386\\;\\times\\;10^3 \\\\[0.75em] 0.123 & 1.23\\;\\times\\;0.1 = 1.23\\;\\times\\;10^{-1} \\end{array}$<\/div>\r\n

The power (exponent) of 10 is equal to the number of places the decimal is shifted to give the digit number. The exponential method is particularly useful notation for every large and very small numbers. For example, 1,230,000,000 = 1.23 \u00d7 109<\/sup>, and 0.00000000036 = 3.6 \u00d7 10\u221210<\/sup>.<\/p>\r\n\r\n

\r\n

Addition of Exponentials<\/h2>\r\n

Convert all numbers to the same power of 10, add the digit terms of the numbers, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.<\/p>\r\n\r\n

\r\n

Example 1<\/h3>\r\n

Adding Exponentials<\/strong>\r\nAdd 5.00 \u00d7 10\u22125<\/sup> and 3.00 \u00d7 10\u22123<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex 3.00\\;\\times\\;10^{-3} = 300\\;\\times\\;10^{-5}$\r\n$latex (5.00\\;\\times\\;10^{-5})\\;+\\;(300\\;\\times\\;10^{-5}) = 305\\;\\times\\;10^{-5} = 3.05\\;\\times\\;10^{-3} $<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Subtraction of Exponentials<\/h2>\r\n

Convert all numbers to the same power of 10, take the difference of the digit terms, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.<\/p>\r\n\r\n

\r\n

Example 2<\/h3>\r\n

Subtracting Exponentials<\/strong>\r\nSubtract 4.0 \u00d7 10\u22127<\/sup> from 5.0 \u00d7 10\u22126<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex 4.0\\;\\times\\;10^{-7} = 0.40\\;\\times\\;10^{-6}$\r\n$latex (5.0\\;\\times\\;10^{-6})\\;-\\;(0.40\\;\\times\\;10^{-6}) = 4.6\\;\\times\\;10^{-6}$<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Multiplication of Exponentials<\/h2>\r\n

Multiply the digit terms in the usual way and add the exponents of the exponential terms.<\/p>\r\n\r\n

\r\n

Example 3<\/h3>\r\n

Multiplying Exponentials<\/strong>\r\nMultiply 4.2 \u00d7 10\u22128<\/sup> by 2.0 \u00d7 103<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex (4.2\\;\\times\\;10^{-8})\\;\\times\\;(2.0\\;\\times\\;10^3) = (4.2\\;\\times\\;2.0)\\;\\times\\;10^{(-8)+(+3)} = 8.4\\;\\times\\;10^{-5}$<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Division of Exponentials<\/h2>\r\n

Divide the digit term of the numerator by the digit term of the denominator and subtract the exponents of the exponential terms.<\/p>\r\n\r\n

\r\n

Example 4<\/h3>\r\n

Dividing Exponentials<\/strong>\r\nDivide 3.6 \u00d7 105<\/sup> by 6.0 \u00d7 10\u22124<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex \\frac{3.6\\;\\times\\;10^{-5}}{6.0\\;\\times\\;10^{-4}} = (\\frac{3.6}{6.0})\\;\\times\\;10^{(-5)-(-4)} = 0.60\\;\\times\\;10^{-1} = 6.0\\;\\times\\;10^{-2}$<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Squaring of Exponentials<\/h2>\r\n

Square the digit term in the usual way and multiply the exponent of the exponential term by 2.<\/p>\r\n\r\n

\r\n

Example 5<\/h3>\r\n

Squaring Exponentials<\/strong>\r\nSquare the number 4.0 \u00d7 10\u22126<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex (4.0\\;\\times\\;10^{-6})^2 = 4\\;\\times\\;4\\;\\times\\;10^{2\\;\\times\\;(-6)} = 16\\;\\times\\;10^{-12} = 1.6\\;\\times\\;10^{-11}$<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Cubing of Exponentials<\/h2>\r\n

Cube the digit term in the usual way and multiply the exponent of the exponential term by 3.<\/p>\r\n\r\n

\r\n

Example 6<\/h3>\r\n

Cubing Exponentials<\/strong>\r\nCube the number 2 \u00d7 104<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex (2\\;\\times\\;10^4)^3 = 2\\;\\times\\;2\\;\\times\\;2\\;\\times\\;10^{3\\;\\times\\;4} = 8\\;\\times\\; 10^{12}$<\/div>\r\n<\/div>\r\n<\/section>
\r\n

Taking Square Roots of Exponentials<\/h2>\r\n

If necessary, decrease or increase the exponential term so that the power of 10 is evenly divisible by 2. Extract the square root of the digit term and divide the exponential term by 2.<\/p>\r\n\r\n

\r\n

Example 7<\/h3>\r\n

Finding the Square Root of Exponentials<\/strong>\r\nFind the square root of 1.6 \u00d7 10\u22127<\/sup>.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex 1.6\\;\\times\\;10^{-7} = 16\\;\\times\\;10^{-8}$\r\n$latex \\sqrt{16\\;\\times\\;10^{-8}} = \\sqrt{16}\\;\\times\\;\\sqrt{10^{-8}} = \\sqrt{16}\\;\\times\\;\\sqrt{10}^{-\\frac{8}{2}} = 4.0\\;\\times\\;10^{-4}$<\/div>\r\n<\/div>\r\n<\/section><\/section>
\r\n

Significant Figures<\/h1>\r\n

A beekeeper reports that he has 525,341 bees. The last three figures of the number are obviously inaccurate, for during the time the keeper was counting the bees, some of them died and others hatched; this makes it quite difficult to determine the exact number of bees. It would have been more accurate if the beekeeper had reported the number 525,000. In other words, the last three figures are not significant, except to set the position of the decimal point. Their exact values have no meaning useful in this situation. In reporting any information as numbers, use only as many significant figures as the accuracy of the measurement warrants.<\/p>\r\n

The importance of significant figures lies in their application to fundamental computation. In addition and subtraction, the sum or difference should contain as many digits to the right of the decimal as that in the least certain of the numbers used in the computation (indicated by underscoring in the following example).<\/p>\r\n\r\n

\r\n

Example 8<\/h3>\r\n

Addition and Subtraction with Significant Figures<\/strong>\r\nAdd 4.383 g and 0.0023 g.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex \\begin{array}{l} 4.38\\underline{3}\\;\\text{g} \\\\ 0.002\\underline{3}\\;\\text{g} \\\\ \\hline 4.38\\underline{5}\\;\\text{g} \\end{array}$<\/div>\r\n<\/div>\r\n

In multiplication and division, the product or quotient should contain no more digits than that in the factor containing the least number of significant figures.<\/p>\r\n\r\n

\r\n

Example 9<\/h3>\r\n

Multiplication and Division with Significant Figures<\/strong>\r\nMultiply 0.6238 by 6.6.<\/p>\r\n \r\n

Solution<\/strong><\/p>\r\n\r\n

$latex 0.623\\underline{8}\\;\\times\\;6.\\underline{6} = 4.\\underline{1}$<\/div>\r\n<\/div>\r\n

When rounding numbers, increase the retained digit by 1 if it is followed by a number larger than 5 (\u201cround up\u201d). Do not change the retained digit if the digits that follow are less than 5 (\u201cround down\u201d). If the retained digit is followed by 5, round up if the retained digit is odd, or round down if it is even (after rounding, the retained digit will thus always be even).<\/p>\r\n\r\n<\/section>","rendered":"

\n

Exponential Arithmetic<\/h1>\n

Exponential notation is used to express very large and very small numbers as a product of two numbers. The first number of the product, the digit term<\/em>, is usually a number not less than 1 and not greater than 10. The second number of the product, the exponential term<\/em>, is written as 10 with an exponent. Some examples of exponential notation are:<\/p>\n

[latex]\\begin{array}{r @{{}={}} l} 1000 & 1\\;\\times\\;10^3 \\\\[0.75em] 100 & 1\\;\\times\\;10^2 \\\\[0.75em] 10 & 1\\;\\times\\;10^1 \\\\[0.75em] 1 & 1\\;\\times\\;10^0 \\\\[0.75em] 0.1 & 1\\;\\times\\;10^{-1} \\\\[0.75em] 0.001 & 1\\;\\times\\;10^{-3} \\\\[0.75em] 2386 & 2.386\\;\\times\\;1000 = 2.386\\;\\times\\;10^3 \\\\[0.75em] 0.123 & 1.23\\;\\times\\;0.1 = 1.23\\;\\times\\;10^{-1} \\end{array}[\/latex]<\/div>\n

The power (exponent) of 10 is equal to the number of places the decimal is shifted to give the digit number. The exponential method is particularly useful notation for every large and very small numbers. For example, 1,230,000,000 = 1.23 \u00d7 109<\/sup>, and 0.00000000036 = 3.6 \u00d7 10\u221210<\/sup>.<\/p>\n

\n

Addition of Exponentials<\/h2>\n

Convert all numbers to the same power of 10, add the digit terms of the numbers, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.<\/p>\n

\n

Example 1<\/h3>\n

Adding Exponentials<\/strong>
\nAdd 5.00 \u00d7 10\u22125<\/sup> and 3.00 \u00d7 10\u22123<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]3.00\\;\\times\\;10^{-3} = 300\\;\\times\\;10^{-5}[\/latex]
\n[latex](5.00\\;\\times\\;10^{-5})\\;+\\;(300\\;\\times\\;10^{-5}) = 305\\;\\times\\;10^{-5} = 3.05\\;\\times\\;10^{-3}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Subtraction of Exponentials<\/h2>\n

Convert all numbers to the same power of 10, take the difference of the digit terms, and if appropriate, convert the digit term back to a number between 1 and 10 by adjusting the exponential term.<\/p>\n

\n

Example 2<\/h3>\n

Subtracting Exponentials<\/strong>
\nSubtract 4.0 \u00d7 10\u22127<\/sup> from 5.0 \u00d7 10\u22126<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]4.0\\;\\times\\;10^{-7} = 0.40\\;\\times\\;10^{-6}[\/latex]
\n[latex](5.0\\;\\times\\;10^{-6})\\;-\\;(0.40\\;\\times\\;10^{-6}) = 4.6\\;\\times\\;10^{-6}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Multiplication of Exponentials<\/h2>\n

Multiply the digit terms in the usual way and add the exponents of the exponential terms.<\/p>\n

\n

Example 3<\/h3>\n

Multiplying Exponentials<\/strong>
\nMultiply 4.2 \u00d7 10\u22128<\/sup> by 2.0 \u00d7 103<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex](4.2\\;\\times\\;10^{-8})\\;\\times\\;(2.0\\;\\times\\;10^3) = (4.2\\;\\times\\;2.0)\\;\\times\\;10^{(-8)+(+3)} = 8.4\\;\\times\\;10^{-5}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Division of Exponentials<\/h2>\n

Divide the digit term of the numerator by the digit term of the denominator and subtract the exponents of the exponential terms.<\/p>\n

\n

Example 4<\/h3>\n

Dividing Exponentials<\/strong>
\nDivide 3.6 \u00d7 105<\/sup> by 6.0 \u00d7 10\u22124<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]\\frac{3.6\\;\\times\\;10^{-5}}{6.0\\;\\times\\;10^{-4}} = (\\frac{3.6}{6.0})\\;\\times\\;10^{(-5)-(-4)} = 0.60\\;\\times\\;10^{-1} = 6.0\\;\\times\\;10^{-2}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Squaring of Exponentials<\/h2>\n

Square the digit term in the usual way and multiply the exponent of the exponential term by 2.<\/p>\n

\n

Example 5<\/h3>\n

Squaring Exponentials<\/strong>
\nSquare the number 4.0 \u00d7 10\u22126<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex](4.0\\;\\times\\;10^{-6})^2 = 4\\;\\times\\;4\\;\\times\\;10^{2\\;\\times\\;(-6)} = 16\\;\\times\\;10^{-12} = 1.6\\;\\times\\;10^{-11}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Cubing of Exponentials<\/h2>\n

Cube the digit term in the usual way and multiply the exponent of the exponential term by 3.<\/p>\n

\n

Example 6<\/h3>\n

Cubing Exponentials<\/strong>
\nCube the number 2 \u00d7 104<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex](2\\;\\times\\;10^4)^3 = 2\\;\\times\\;2\\;\\times\\;2\\;\\times\\;10^{3\\;\\times\\;4} = 8\\;\\times\\; 10^{12}[\/latex]<\/div>\n<\/div>\n<\/section>\n
\n

Taking Square Roots of Exponentials<\/h2>\n

If necessary, decrease or increase the exponential term so that the power of 10 is evenly divisible by 2. Extract the square root of the digit term and divide the exponential term by 2.<\/p>\n

\n

Example 7<\/h3>\n

Finding the Square Root of Exponentials<\/strong>
\nFind the square root of 1.6 \u00d7 10\u22127<\/sup>.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]1.6\\;\\times\\;10^{-7} = 16\\;\\times\\;10^{-8}[\/latex]
\n[latex]\\sqrt{16\\;\\times\\;10^{-8}} = \\sqrt{16}\\;\\times\\;\\sqrt{10^{-8}} = \\sqrt{16}\\;\\times\\;\\sqrt{10}^{-\\frac{8}{2}} = 4.0\\;\\times\\;10^{-4}[\/latex]<\/div>\n<\/div>\n<\/section>\n<\/section>\n
\n

Significant Figures<\/h1>\n

A beekeeper reports that he has 525,341 bees. The last three figures of the number are obviously inaccurate, for during the time the keeper was counting the bees, some of them died and others hatched; this makes it quite difficult to determine the exact number of bees. It would have been more accurate if the beekeeper had reported the number 525,000. In other words, the last three figures are not significant, except to set the position of the decimal point. Their exact values have no meaning useful in this situation. In reporting any information as numbers, use only as many significant figures as the accuracy of the measurement warrants.<\/p>\n

The importance of significant figures lies in their application to fundamental computation. In addition and subtraction, the sum or difference should contain as many digits to the right of the decimal as that in the least certain of the numbers used in the computation (indicated by underscoring in the following example).<\/p>\n

\n

Example 8<\/h3>\n

Addition and Subtraction with Significant Figures<\/strong>
\nAdd 4.383 g and 0.0023 g.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]\\begin{array}{l} 4.38\\underline{3}\\;\\text{g} \\\\ 0.002\\underline{3}\\;\\text{g} \\\\ \\hline 4.38\\underline{5}\\;\\text{g} \\end{array}[\/latex]<\/div>\n<\/div>\n

In multiplication and division, the product or quotient should contain no more digits than that in the factor containing the least number of significant figures.<\/p>\n

\n

Example 9<\/h3>\n

Multiplication and Division with Significant Figures<\/strong>
\nMultiply 0.6238 by 6.6.<\/p>\n

 <\/p>\n

Solution<\/strong><\/p>\n

[latex]0.623\\underline{8}\\;\\times\\;6.\\underline{6} = 4.\\underline{1}[\/latex]<\/div>\n<\/div>\n

When rounding numbers, increase the retained digit by 1 if it is followed by a number larger than 5 (\u201cround up\u201d). Do not change the retained digit if the digits that follow are less than 5 (\u201cround down\u201d). If the retained digit is followed by 5, round up if the retained digit is odd, or round down if it is even (after rounding, the retained digit will thus always be even).<\/p>\n<\/section>\n","protected":false},"author":330,"menu_order":2,"template":"","meta":{"pb_show_title":"on","pb_short_title":"Appendix B: Essential Mathematics","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"back-matter-type":[],"contributor":[64,63,65],"license":[54],"class_list":["post-2024","back-matter","type-back-matter","status-publish","hentry","contributor-david-w-ball","contributor-jessie-a-key","contributor-shirley-wacowich-sgarbi","license-cc-by-nc-sa"],"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter\/2024","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/users\/330"}],"version-history":[{"count":1,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter\/2024\/revisions"}],"predecessor-version":[{"id":4331,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter\/2024\/revisions\/4331"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter\/2024\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/media?parent=2024"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/back-matter-type?post=2024"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/contributor?post=2024"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/license?post=2024"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}