{"id":1528,"date":"2018-04-11T22:52:23","date_gmt":"2018-04-12T02:52:23","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/chapter\/6-4-electronic-structure-of-atoms-electron-configurations\/"},"modified":"2019-05-13T17:00:09","modified_gmt":"2019-05-13T21:00:09","slug":"6-4-electronic-structure-of-atoms-electron-configurations","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/chapter\/6-4-electronic-structure-of-atoms-electron-configurations\/","title":{"raw":"8.4 Electronic Structure of Atoms","rendered":"8.4 Electronic Structure of Atoms"},"content":{"raw":"<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\nBy the end of this section, you will be able to:\r\n<ul>\r\n \t<li>Derive the predicted ground-state electron configurations of atoms<\/li>\r\n \t<li>Identify and explain exceptions to predicted electron configurations for atoms and ions<\/li>\r\n \t<li>Relate electron configurations to element classifications in the periodic table<\/li>\r\n<\/ul>\r\n<\/div>\r\n<p id=\"fs-idp32474800\">Having introduced the basics of atomic structure and quantum mechanics, we can use our understanding of quantum numbers to determine how atomic orbitals relate to one another. This allows us to determine which orbitals are occupied by electrons in each atom. The specific arrangement of electrons in orbitals of an atom determines many of the chemical properties of that atom.<\/p>\r\n\r\n<section id=\"fs-idp61895104\">\r\n<h2>Electronic Structure of Atoms<\/h2>\r\n<p id=\"fs-idp45944160\">The arrangement of electrons in the orbitals of an atom is called the <strong>electron configuration<\/strong> of the atom. We describe an electron configuration with a symbol that contains three pieces of information (<a href=\"#CNX_Chem_06_04_Econfig\" class=\"autogenerated-content\">Figure 1<\/a>):<\/p>\r\n\r\n<ol id=\"fs-idp16888336\">\r\n \t<li>The number of the principal quantum <span style=\"text-decoration: underline\">shell<\/span>, <em>n<\/em>,<\/li>\r\n \t<li>The letter that designates the orbital type also called the <span style=\"text-decoration: underline\">subshell<\/span>, and<\/li>\r\n \t<li>A superscript number that designates the number of electrons in that particular subshell.<\/li>\r\n<\/ol>\r\n<p id=\"fs-idp148323904\">For example, the notation 2<em>p<\/em><sup>4<\/sup> (read \"two\u2013p\u2013four\") indicates four electrons in a <em>p<\/em> subshell with a principal quantum number (<em>n<\/em>) of 2. The notation 3<em>d<\/em><sup>8<\/sup> (read \"three\u2013d\u2013eight\") indicates eight electrons in the <em>d<\/em> subshell of the principal shell for which <em>n<\/em> = 3.<\/p>\r\n\r\n<figure id=\"CNX_Chem_06_04_Econfig\"><figcaption>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"975\"]<a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Econfig.jpg\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Econfig-2.jpg\" alt=\"A light blue hemisphere is labeled H. At a location about midway between the center and outer edge of the hemisphere, a small yellow-orange sphere is shown that is labeled with a negative sign. To the right of this diagram is the electron configuration 1 s superscript 1. The superscript is shown in a small yellow-orange circle. This superscript is labeled, \u201cNumber of electrons in subshell,\u201d and the s is labeled, \u201cSubshell.\u201d\" width=\"975\" height=\"186\" \/><\/a> <strong>Figure 1.<\/strong> Electron configuration of hydrogen is 1s<sup>1<\/sup>, which indicates there is one electron in the s subshell of the principal shell n=1.[\/caption]\r\n\r\n<\/figcaption><\/figure>\r\n<\/section><section id=\"fs-idp52797152\">\r\n<h2>The Aufbau Principle<\/h2>\r\n<p id=\"fs-idp6137968\">To determine the electron configuration for any particular atom, we can \u201cbuild\u201d the structures in the order of atomic numbers. Beginning with hydrogen, and continuing across the periods of the periodic table, we add one proton at a time to the nucleus and one electron to the proper subshell until we have described the electron configurations of all the elements. This procedure is called the <strong>Aufbau principle<\/strong>, from the German word <em>Aufbau<\/em> (\u201cto build up\u201d). Each added electron occupies the subshell of lowest energy available (in the order shown in <a href=\"#CNX_Chem_06_04_eLeveldiag\" class=\"autogenerated-content\">Figure 4 in section 7.3<\/a>), subject to the limitations imposed by the Pauli exclusion principle. Electrons enter higher-energy subshells only after lower-energy subshells have been filled to capacity. <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> illustrates the traditional way to remember the filling order for atomic orbitals. Since the arrangement of the periodic table is based on the electron configurations, Figure 3 and\u00a0<a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 4<\/a> provides an alternative method for determining the electron configuration. The filling order simply begins at hydrogen and includes each subshell as you proceed in increasing <em>Z<\/em> order. For example, after filling the 3<em>p<\/em> block up to Ar, we see the orbital will be 4s (K, Ca), followed by the 3<em>d<\/em> orbitals.<\/p>\r\n\r\n<figure id=\"CNX_Chem_06_04_Efillorder\"><figcaption>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"650\"]<a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Efillorder.jpg\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Efillorder-2.jpg\" alt=\"This figure includes a chart used to order the filling of electrons into atoms. At the top is a blue circle labeled \u201c1 s.\u201d In a row beneath this circle are 6 additional blue circles labeled \u201c2 s\u201d through \u201c7 s.\u201d A column to the right begins just right of 2 s and contains pink circles labeled 2 p through 7 p. A column to the right begins just right of 3 p and contains yellow circles labeled 3 d through 6 d. No circles are placed to the right of the 7 s and 7 p circles. A final column on the right begins right of 4 d. It includes grey circles labeled, \u201c4 f\u201d and, \u201c5 f.\u201d No circles are placed right of 6 d. Through these circles, arrows are included in the figure pointing down and to the left. The first arrow begins in the upper right and passes through 1 s. The second arrow begins just below and passes through 2 s. The third arrow passes through 2 p and 3 s. The fourth arrow passes through 3 p and 4 s. This pattern of parallel arrows pointing downward to the left continues through all circles completing the pattern 1 s 2 s 2 p 3 s 3 p 4 s 3 d 4 p 5 s 4 d 5 p 6 s 4 f 5 d 6 p 7 s 5 f 6 d 7 p.\" width=\"650\" height=\"469\" \/><\/a> <strong>Figure 2.<\/strong> The arrow leads through each subshell in the appropriate filling order for electron configurations. This chart is straightforward to construct. Simply make a column for all the s orbitals with each <em>n<\/em> shell on a separate row. Repeat for <em>p<\/em>, <em>d<\/em>, and <em>f<\/em>. Be sure to only include orbitals allowed by the quantum numbers (no 1<em>p<\/em> or 2<em>d<\/em>, and so forth). Finally, draw diagonal lines from top to bottom as shown.[\/caption]\r\n\r\n&nbsp;\r\n\r\n[caption id=\"attachment_2379\" align=\"aligncenter\" width=\"600\"]<a href=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1.png\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1.png\" alt=\"\" width=\"600\" height=\"357\" class=\"wp-image-2379 size-full\" \/><\/a> <strong>Figure 3.<\/strong> The arrangement of the periodic table is based on electron configurations, therefore the four sections here are coloured to stress the final subshell of each atom.[\/caption]\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n<\/figcaption>&nbsp;<\/figure>\r\n<figure id=\"CNX_Chem_06_04_Econtable\"><figcaption>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"1300\"]<a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Econtable.jpg\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Econtable-2.jpg\" alt=\"In this figure, a periodic table is shown that is entitled, \u201cElectron Configuration Table.\u201d Beneath the table, a square for the element hydrogen is shown enlarged to provide detail. The element symbol, H, is placed in the upper left corner. In the upper right is the number of electrons, 1. The lower central portion of the element square contains the subshell, 1 s. Helium and elements in groups 1 and 2 are shaded blue. In this region, the rows are labeled 1 s through 7 s moving down the table. Groups 3 through 12 are shaded orange, and the rows are labeled 3 d through 6 d moving down the table. Groups 13 through 18, except helium, are shaded pink and are labeled 2 p through 6 p moving down the table. The lanthanide and actinide series across the bottom of the table are shaded grey and are labeled 4 f and 5 f respectively.\" width=\"1300\" height=\"1016\" \/><\/a> <strong>Figure 4.<\/strong> This periodic table shows the electron configuration for each subshell. By \u201cbuilding up\u201d from hydrogen, this table can be used to determine the electron configuration for any atom on the periodic table.[\/caption]\r\n\r\n<\/figcaption><\/figure>\r\n<p id=\"fs-idp96036896\">We will now construct the ground-state electron configuration and orbital diagram for a selection of atoms in the first and second periods of the periodic table. <strong>Orbital diagrams<\/strong> are pictorial representations of the electron configuration, showing the individual orbitals and the pairing arrangement of electrons. We start with a single hydrogen atom (atomic number 1), which consists of one proton and one electron. Referring to <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>, we would expect to find the electron in the 1<em>s<\/em> orbital. By convention, spin up = + \\frac{1}{2}$ value is usually filled first. The electron configuration and the orbital box diagram are:<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Hydrog1_img-2.jpg\" alt=\"In this figure, the element symbol H is followed by the electron configuration is 1 s superscript 1. An orbital diagram is provided that consists of a single square. The square is labeled below as, \u201c1 s.\u201d It contains a single upward pointing half arrow.\" class=\"alignnone\" \/>\r\n\r\nFollowing hydrogen is the noble gas helium, which has an atomic number of 2. The helium atom contains two protons and two electrons. The two electrons will occupy the same orbital but they will have different spin states, one will be spin-up (<span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><span style=\"font-family: Arial, sans-serif\"><span style=\"font-size: large\">\u02e6<\/span><\/span><\/span><\/span>) and the other spin-down (<span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><span style=\"font-family: Arial, sans-serif\"><span style=\"font-size: large\">\u02e8<\/span><\/span><\/span><\/span>).\u00a0This is in accord with the Pauli exclusion principle. \u00a0For orbital diagrams, this means two half-arrows go in each box (representing two electrons in each orbital) and the half-arrows must point in opposite directions (representing paired spins). The electron configuration and orbital box diagram of helium are:\r\n\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Helium1_img-2.jpg\" alt=\"In this figure, the element symbol H e is followed by the electron configuration, \u201c1 s superscript 2.\u201d An orbital diagram is provided that consists of a single square. The square is labeled below as \u201c1 s.\u201d It contains a pair of half arrows: one pointing up and the other down.\" class=\"alignnone\" \/>\r\n<p id=\"fs-idp9284128\">The <em>n<\/em> = 1 shell is completely filled in a helium atom.<\/p>\r\n<p id=\"fs-idp29682592\">The next atom is the alkali metal lithium with an atomic number of 3. The first two electrons in lithium fill the 1<em>s<\/em> orbital. \u00a0The remaining electron must occupy the orbital of next lowest energy, the 2<em>s<\/em> orbital (<a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>). Thus, the electron configuration and orbital box diagram of lithium are:<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Lithium12_img-2.jpg\" alt=\"In this figure, the element symbol L i is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 1.\u201d An orbital diagram is provided that consists of two individual squares. The first square is labeled below as, \u201c1 s.\u201d The second square is similarly labeled, \u201c2 s.\u201d The first square contains a pair of half arrows: one pointing up and the other down. The second square contains a single upward pointing arrow.\" \/>\r\n<p id=\"fs-idp10466880\">An atom of the alkaline earth metal beryllium, with an atomic number of 4, contains four protons in the nucleus and four electrons surrounding the nucleus. The fourth electron fills the remaining space in the 2<em>s<\/em> orbital.<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Beryll12_img-2.jpg\" alt=\"In this figure, the element symbol B e is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2.\u201d An orbital diagram is provided that consists of two individual squares. The first square is labeled below as, \u201c1 s.\u201d The second square is similarly labeled, \u201c2 s.\u201d Both squares contain a pair of half arrows: one pointing up and the other down.\" \/>\r\n<p id=\"fs-idp164718432\">An atom of boron (atomic number 5) contains five electrons. The <em>n<\/em> = 1 shell is filled with two electrons and three electrons will occupy the <em>n<\/em> = 2 shell. Because any <em>s<\/em> subshell can contain only two electrons, the fifth electron must occupy the next energy level, which will be a 2<em>p<\/em> orbital. There are three <strong>degenerate<\/strong> 2<em>p<\/em> orbitals, meaning they are equal in energy,\u00a0and the electron can occupy any one of these <em>p<\/em> orbitals. When drawing orbital diagrams, we include empty boxes to depict any empty orbitals in the same subshell that we are filling.<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Boron122_img-2.jpg\" alt=\"In this figure, the element symbol B is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2 2 p superscript 1.\u201d The orbital diagram consists of two individual squares followed by 3 connected squares in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected contain a pair of half arrows: one pointing up and the other down. The first square in the group of 3 contains a single upward pointing arrow.\" class=\"alignnone\" \/>\r\n\r\nIn the orbital box diagrams, notice the space between the box for the 1s and 2s orbitals - space between boxes are used to indicate a difference in energy. \u00a0Therefore, a \" lack of space\" between boxes, indicate the orbitals are degenerate, meaning equal in energy.\r\n<p id=\"fs-idp35410400\">Carbon (atomic number 6) has six electrons. Four of them fill the 1<em>s<\/em> and 2<em>s<\/em> orbitals. The remaining two electrons occupy the 2<em>p<\/em> subshell. We now have a choice of filling one of the 2<em>p<\/em> orbitals and pairing the electrons or of leaving the electrons unpaired in two different, but degenerate, <em>p<\/em> orbitals. The orbitals are filled as described by <strong>Hund\u2019s rule<\/strong>: the lowest-energy configuration for an atom with electrons within a set of degenerate orbitals is that having the maximum number of unpaired electrons. Thus, the two electrons in the carbon 2<em>p<\/em> orbitals occupy different p-orbitals - this minimizes electron-electron repulsion within the atom. \u00a0The electron configuration and orbital box diagram for carbon are:<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Carbon122_img-2.jpg\" alt=\"In this figure, the element symbol C is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2 2 p superscript 2.\u201d The orbital diagram consists of two individual squares followed by 3 connected squares in a single row. The first blue square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected to each other contain a pair of half arrows: one pointing up and the other down. The first two squares in the group of 3 each contain a single upward pointing arrow.\" class=\"alignnone\" \/>\r\n<p id=\"fs-idp243804816\">Nitrogen (atomic number 7) fills the 1<em>s<\/em> and 2<em>s<\/em> subshells and has one electron in each of the three 2<em>p<\/em> orbitals, in accordance with Hund\u2019s rule. These three electrons have unpaired spins. Oxygen (atomic number 8) has a pair of electrons in any one of the 2<em>p<\/em> orbitals (the electrons have opposite spins) and a single electron in each of the other two. Fluorine (atomic number 9) has only one 2<em>p<\/em> orbital containing an unpaired electron. All of the electrons in the noble gas neon (atomic number 10) are paired, and all of the orbitals in the <em>n<\/em> = 1 and the <em>n<\/em> = 2 shells are filled. The electron configurations and orbital box diagrams of these four elements are:<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_NOFNe_img-2.jpg\" alt=\"This figure includes electron configurations and orbital diagrams for four elements, N, O, F, and N e. Each diagram consists of two individual squares followed by 3 connected squares in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected to each other contain a pair of half arrows: one pointing up and the other down. For the element N, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 3. Each of the squares in the group of 3 contains a single upward pointing arrow for this element. For the element O, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 4. The first square in the group of 3 contains a pair of arrows and the last two squares contain single upward pointing arrows. For the element F, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 5. The first two squares in the group of 3 each contain a pair of arrows and the last square contains a single upward pointing arrow. For the element N e, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 6. The squares in the group of 3 each contains a pair of arrows.\" \/>\r\n<p id=\"fs-idm31105888\">The alkali metal sodium (atomic number 11) has one more electron than the neon atom. This electron must go into the lowest-energy subshell available, the 3<em>s<\/em> orbital, giving a 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup> configuration. The electrons occupying the outermost shell orbital(s) (highest value of <em>n<\/em>) are called <strong>outer electrons<\/strong>, and those occupying the inner shell orbitals are called <strong>core electrons or inner electrons<\/strong> (<a href=\"#CNX_Chem_06_04_Valence\" class=\"autogenerated-content\">Figure 4<\/a>). \u00a0<strong>Valence electrons\u00a0<\/strong>are outer electrons plus any electrons found in partially filled d or f orbitals. \u00a0Often valence electron are the same as the outer electrons. \u00a0But there are examples where there is a difference. \u00a0Since the core electron shells correspond to noble gas electron configurations, we can abbreviate electron configurations by writing the noble gas that matches the core electron configuration, along with the valence electrons in a condensed format. For our sodium example, the symbol [Ne] represents core electrons, (1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>) and our abbreviated or condensed electron configuration is [Ne]3<em>s<\/em><sup>1<\/sup>.<\/p>\r\n\r\n<figure id=\"CNX_Chem_06_04_Valence\">[caption id=\"\" align=\"aligncenter\" width=\"650\"]<a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Valence.jpg\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Valence-2.jpg\" alt=\"This figure includes the element symbol N a, followed by the electron configuration for the element. The first part of the electron configuration, 1 s superscript 2 2 s superscript 2 2 p superscript 6, is shaded in purple and is labeled, \u201ccore electrons.\u201d The last portion, 3 s superscript 1, is shaded orange and is labeled, \u201cvalence electron.\u201d To the right of this configuration is the word \u201cAbbreviation\u201d followed by [ N e ] 3 s superscript 1.\" width=\"650\" height=\"111\" \/><\/a> <strong>Figure 4.<\/strong> A condensed electron configuration (right) replaces the core electrons with the noble gas symbol whose configuration matches the core electron configuration of the other element.[\/caption]<\/figure>\r\n<p id=\"fs-idp28826352\">Similarly, the condensed electron configuration of lithium can be represented as [He]2<em>s<\/em><sup>1<\/sup>, where [He] represents the configuration of the helium atom, which is identical to that of the filled inner shell of lithium. Writing the configurations in this way emphasizes the similarity of the configurations of lithium and sodium. Both atoms, which are in the alkali metal family, have only one electron in a valence <em>s<\/em> subshell outside a filled set of inner shells.<\/p>\r\n\r\n<div class=\"equation\" id=\"fs-idp20565040\" style=\"text-align: center\">$latex \\begin{array}{l} \\text{Li}: [\\text{He}] \\;2s^1 \\\\ \\text{Na}: [\\text{Ne}] \\;3s^1 \\end{array}$<\/div>\r\n<p id=\"fs-idp156268816\">The alkaline earth metal magnesium (atomic number 12), with its 12 electrons in a [Ne]3<em>s<\/em><sup>2<\/sup> configuration, is analogous to its family member beryllium, [He]2<em>s<\/em><sup>2<\/sup>. Both atoms have a filled <em>s<\/em> subshell outside their filled inner shells. Aluminum (atomic number 13), with 13 electrons and the condensed electron configuration [Ne]3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup>, is analogous to its family member boron, [He]2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>1<\/sup>.<\/p>\r\n<p id=\"fs-idp52824064\">The electron configurations of silicon (14 electrons), phosphorus (15 electrons), sulfur (16 electrons), chlorine (17 electrons), and argon (18 electrons) are analogous in the electron configurations of their outer shells to their corresponding family members carbon, nitrogen, oxygen, fluorine, and neon, respectively, except that the principal quantum number of the outer shell of the heavier elements has increased by one to <em>n<\/em> = 3. <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a> shows the lowest energy, or ground-state, electron configuration for these elements as well as that for atoms of each of the known elements.<\/p>\r\n\r\n<figure id=\"CNX_Chem_06_04_Ptableconf\"><figcaption>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"1300\"]<a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Ptableconf.jpg\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Ptableconf-2.jpg\" alt=\"A periodic table, entitled, \u201cElectron Configuration Table\u201d is shown. The table includes the outer electron configuration information, atomic numbers, and element symbols for all elements. A square for the element hydrogen is pulled out beneath the table to provide detail. The blue shaded square includes the atomic number in the upper left corner, which is 1, the element symbol, H in the upper right corner, and the outer electron configuration in the lower, central portion of the square. For H, this is 1 s superscript 1.\" width=\"1300\" height=\"1016\" \/><\/a> <strong>Figure 5.<\/strong> This version of the periodic table shows the outer-shell electron configuration of each element. Note that down each group, the configuration is often similar.[\/caption]\r\n\r\n<\/figcaption><\/figure>\r\n<p id=\"fs-idm8891728\">When we come to the next element in the periodic table, the alkali metal potassium (atomic number 19), we might expect that we would begin to add electrons to the 3<em>d<\/em> subshell. However, all available chemical and physical evidence indicates that potassium is like lithium and sodium, and that the next electron is not added to the 3<em>d<\/em> level but is, instead, added to the 4<em>s<\/em> level (<a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>). Thus, potassium has an electron configuration of [Ar]4<em>s<\/em><sup>1<\/sup>. Hence, potassium corresponds to Li and Na in its valence shell configuration. The next electron is added to complete the 4<em>s<\/em> subshell and calcium has an electron configuration of [Ar]4<em>s<\/em><sup>2<\/sup>. This gives calcium an outer-shell electron configuration corresponding to that of beryllium and magnesium.<\/p>\r\n<p id=\"fs-idp7806208\">Beginning with the transition metal scandium (atomic number 21), additional electrons are added successively to the 3<em>d<\/em> subshell. This subshell is filled to its capacity with 10 electrons. The 4<em>p<\/em> subshell fills next. Note that for three series of elements, scandium (Sc) through copper (Cu), yttrium (Y) through silver (Ag), and lutetium (Lu) through gold (Au), a total of 10 <em>d<\/em> electrons are successively added to the (<em>n<\/em> \u2013 1) shell next to the <em>n<\/em> shell to bring that (<em>n<\/em> \u2013 1) shell from 8 to 18 electrons. For two series, lanthanum (La) through lutetium (Lu) and actinium (Ac) through lawrencium (Lr), 14 <em>f<\/em> electrons are successively added to the (<em>n<\/em> \u2013 2) shell to bring that shell from 18 electrons to a total of 32 electrons.<\/p>\r\n\r\n<div class=\"textbox shaded\" id=\"fs-idp25345424\">\r\n<h3>Example 1<\/h3>\r\n<p id=\"fs-idm59921552\">What is the electron configuration and orbital box diagram for a phosphorus atom?<\/p>\r\n&nbsp;\r\n<p id=\"fs-idp80391584\"><strong>Solution<\/strong>\r\nThe atomic number of phosphorus is 15. Thus, a phosphorus atom contains 15 electrons. The order of filling of the energy levels is 1<em>s<\/em>, 2<em>s<\/em>, 2<em>p<\/em>, 3<em>s<\/em>, 3<em>p<\/em>, 4<em>s<\/em>, . . . The 15 electrons of the phosphorus atom will fill up to the 3<em>p<\/em> orbital, which will contain three electrons:<\/p>\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_PhosphOrb_img-2.jpg\" alt=\"This figure provides the electron configuration 1 s superscript 2 2 s superscript 2 2 p superscript 6 3 s superscript 2 3 p superscript 3. It includes a diagram with two individual squares followed by 3 connected squares, a single square, and another connected group of 3 squares all in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The first group of connected squares is labeled below as, \u201c2 p.\u201d The square that follows is labeled, \u201c3 s,\u201d and the final group of three squares is labeled, \u201c3 p.\u201d All squares except the last group of three squares has a pair of half arrows: one pointing up and the other down. Each of the squares in the last group of 3 contains a single upward pointing arrow.\" \/>\r\n<p id=\"fs-idm6887808\">The last electron added is a 3<em>p<\/em> electron.<\/p>\r\n&nbsp;\r\n<p id=\"fs-idp40041152\"><em><strong>Test Yourself<\/strong><\/em><\/p>\r\nIdentify the atoms from the condensed electron configurations given:\r\n<p id=\"fs-idp255668160\">a) [Ar]4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>5<\/sup><\/p>\r\n<p id=\"fs-idp13258240\">b) [Kr]5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup><\/p>\r\n&nbsp;\r\n\r\n<em><strong>Answers<\/strong><\/em>\r\n\r\na) Mn \u00a0 \u00a0 \u00a0 \u00a0 \u00a0b) Xe\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 2<\/h3>\r\n<p id=\"ball-ch08_s03_p17\" class=\"para\">a) What is the electron configuration for Na, which has 11 electrons?<\/p>\r\nb) What is the predicted electron configuration for Sn, which has 50 electrons?\r\n\r\n&nbsp;\r\n<p class=\"simpara\"><strong>Solution<\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p18\" class=\"para\">a) The first two electrons occupy the 1<em class=\"emphasis\">s<\/em> subshell. The next two occupy the 2<em class=\"emphasis\">s<\/em> subshell, while the next six electrons occupy the 2<em class=\"emphasis\">p<\/em> subshell. This gives us 10 electrons so far, with 1 electron left. This last electron goes into the <em class=\"emphasis\">n<\/em> = 3 shell, <em class=\"emphasis\">s<\/em> subshell. Thus, the electron configuration of Na is 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">1<\/sup>.<\/p>\r\nb) We will follow the chart in Figure 2\u00a0until we can accommodate 50 electrons in the subshells in the proper order:\r\n\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Sn: 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>5<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2<\/sup><\/span><\/span>\r\n<p id=\"ball-ch08_s03_p25\" class=\"para\">Verify by adding the superscripts, which indicate the number of electrons: 2 +\u00a02 +\u00a06 +\u00a02 +\u00a06 +\u00a02 +\u00a010 +\u00a06 +\u00a02 +\u00a010 +\u00a02 = 50, so we have placed all 50 electrons in subshells in the proper order.<\/p>\r\n&nbsp;\r\n<p class=\"simpara\"><strong><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p19\" class=\"para\">a) What is the electron configuration for Mg, which has 12 electrons?<\/p>\r\nb) What is the electron configuration for Ba, which has 56 electrons?\r\n\r\n&nbsp;\r\n<p class=\"simpara\"><strong><em class=\"emphasis\">Answer<\/em><\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p20\" class=\"para\">a) 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/sup>b) 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>5<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>6<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup><span style=\"background-color: #ffffff;font-size: 1em\">\u00a0<\/span><\/p>\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 3<\/h3>\r\n<p id=\"ball-ch08_s03_p31\" class=\"para\">What is the abbreviated electron configuration for P, which has 15 electrons?<\/p>\r\n&nbsp;\r\n<p class=\"simpara\"><strong>Solution<\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p32\" class=\"para\">With 15 electrons, the electron configuration of P is<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">P: 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">3<\/sup><\/span><\/span>\r\n<p id=\"ball-ch08_s03_p33\" class=\"para\">The first immediate noble gas is Ne, which has an electron configuration of 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>. Using the electron configuration of Ne to represent the first 10 electrons, the abbreviated electron configuration of P is<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">P: [Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">3<\/sup><\/span><\/span>\r\n\r\n&nbsp;\r\n<p class=\"simpara\"><strong><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p34\" class=\"para\">What is the abbreviated electron configuration for Rb, which has 37 electrons?<\/p>\r\n&nbsp;\r\n<p class=\"simpara\"><strong><em class=\"emphasis\">Answer<\/em><\/strong><\/p>\r\n<p id=\"ball-ch08_s03_p35\" class=\"para\">[Kr]5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">1<\/sup><\/p>\r\n\r\n<\/div>\r\n<p id=\"fs-idp95342976\">The periodic table can be a powerful tool in predicting the electron configuration of an element. However, we do find exceptions to the order of filling of orbitals that are shown in <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>. For instance, the electron configurations (shown in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>) of the transition metals chromium (Cr; atomic number 24) and copper (Cu; atomic number 29), among others, are not those we would expect. In general, such exceptions involve subshells with very similar energy, and small effects can lead to changes in the order of filling.<\/p>\r\n<p id=\"fs-idp38113648\">In the case of Cr and Cu, we find that half-filled and completely filled subshells apparently represent conditions of preferred stability. This stability is such that an electron shifts from the 4<em>s<\/em> into the 3<em>d<\/em> orbital to gain the extra stability of a half-filled 3<em>d<\/em> subshell (in Cr) or a filled 3<em>d<\/em> subshell (in Cu). Other exceptions also occur. For example, niobium (Nb, atomic number 41) is predicted to have the electron configuration [Kr]5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>3<\/sup>. Experimentally, we observe that its ground-state electron configuration is actually [Kr]5<em>s<\/em><sup>1<\/sup>4<em>d<\/em><sup>4<\/sup>. We can rationalize this observation by saying that the electron\u2013electron repulsions experienced by pairing the electrons in the 5<em>s<\/em> orbital are larger than the gap in energy between the 5<em>s<\/em> and 4<em>d<\/em> orbitals. There is no simple method to predict the exceptions for atoms where the magnitude of the repulsions between electrons is greater than the small differences in energy between subshells.<\/p>\r\n\r\n<\/section><section id=\"fs-idp262041824\">\r\n<h2>Electron Configurations and the Periodic Table<\/h2>\r\n<p id=\"fs-idp3828352\">As described earlier, the periodic table arranges atoms based on increasing atomic number so that elements with the same chemical properties recur periodically. When their electron configurations are added to the table (<a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>), we also see a periodic recurrence of similar electron configurations in the outer shells of these elements. Because they are in the outer shells of an atom, valence electrons play the most important role in chemical reactions. The outer electrons have the highest energy of the electrons in an atom and are more easily lost or shared than the core electrons. Valence electrons are also the determining factor in some physical properties of the elements.<\/p>\r\n<p id=\"fs-idp77726784\">Elements in any one group (or column) have the same number of valence electrons; the alkali metals lithium and sodium each have only one valence electron, the alkaline earth metals beryllium and magnesium each have two, and the halogens fluorine and chlorine each have seven valence electrons. The similarity in chemical properties among elements of the same group occurs because they have the same number of valence electrons. It is the loss, gain, or sharing of valence electrons that defines how elements react.<\/p>\r\n<p id=\"fs-idp150491632\">It is important to remember that the periodic table was developed on the basis of the chemical behavior of the elements, well before any idea of their atomic structure was available. Now we can understand why the periodic table has the arrangement it has\u2014the arrangement puts elements whose atoms have the same number of valence electrons in the same group. This arrangement is emphasized in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>, which shows in periodic-table form the electron configuration of the last subshell to be filled by the Aufbau principle. The colored sections of <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a> show the three categories of elements classified by the orbitals being filled: main group, transition, and inner transition elements. These classifications determine which orbitals are counted in the <strong>valence shell<\/strong>, or highest energy level orbitals of an atom.<\/p>\r\n1.<strong> Main group elements<\/strong> (sometimes called <strong>representative elements<\/strong>) are those in which the last electron added enters an <em>s<\/em> or a <em>p<\/em> orbital in the outermost shell, shown in blue and red in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>. This category includes all the nonmetallic elements, as well as many metals and the intermediate semimetallic elements. The valence electrons for main group elements are those with the highest <em>n<\/em> level. For example, gallium (Ga, atomic number 31) has the electron configuration [Ar]<strong>4<em>s<\/em><sup>2<\/sup><\/strong>3<em>d<\/em><sup>10<\/sup><strong>4<em>p<\/em><sup>1<\/sup><\/strong>, which contains three valence electrons (in bold). The completely filled <em>d<\/em> orbitals count as core, not valence, electrons.\r\n\r\n2. <strong>Transition elements or transition metals<\/strong>. These are metallic elements in which the last electron added enters a <em>d<\/em> orbital. The valence electrons are\u00a0<i><span>the electrons in the outermost shell <\/span><\/i><span>and also include any electrons in partially filled d or f orbitals, as these electrons are also very reactive and have a higher energy despite their lower shell value. \u00a0<\/span>The official IUPAC definition of transition elements specifies those with partially filled <em>d<\/em> orbitals. Thus, the elements with completely filled orbitals (Zn, Cd, Hg, as well as Cu, Ag, and Au in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>) are not technically transition elements. However, the term is frequently used to refer to the entire <em>d<\/em> block (colored yellow in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>), and we will adopt this usage in this textbook.\r\n\r\n3. <strong>Inner transition elements<\/strong> are metallic elements in which the last electron added occupies an <em>f<\/em> orbital. They are shown in green in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>. The valence shells of the inner transition elements consist of the (<em>n<\/em> \u2013 2)<em>f,<\/em> the (<em>n<\/em> \u2013 1)<em>d<\/em>, and the <em>ns<\/em> subshells. There are two inner transition series:\r\n\r\na) The lanthanide series: lanthanide (La) through lutetium (Lu)\r\n\r\nb) The actinide series: actinide (Ac) through lawrencium (Lr)\r\n<p id=\"fs-idm11513792\">Lanthanum and actinium, because of their similarities to the other members of the series, are included and used to name the series, even though they are transition metals with no <em>f<\/em> electrons.<\/p>\r\n\r\n<\/section><section id=\"fs-idp32346944\">\r\n<h2>Electron Configurations of Ions<\/h2>\r\n<p id=\"fs-idp229254240\">We have seen that ions are formed when atoms gain or lose electrons. A cation (positively charged ion) forms when one or more electrons are removed from a parent atom. For main group elements, the electrons that were added last are the first electrons removed. For transition metals and inner transition metals, however, electrons in the <em>s<\/em>\u00a0\u00a0orbital are easier to remove than the <em>d<\/em>\u00a0\u00a0or <em>f<\/em>\u00a0\u00a0electrons, and so the\u00a0\u00a0highest\u00a0\u00a0<em>ns<\/em>\u00a0\u00a0electrons are lost, and then the (<em>n<\/em> \u2013 1)<em>d<\/em>\u00a0\u00a0or\u00a0\u00a0(<em>n<\/em> \u2013 2)<em>f<\/em> electrons are removed. An anion (negatively charged ion) forms when one or more electrons are added to a parent atom. The added electrons fill in the order predicted by the Aufbau principle.<\/p>\r\n\r\n<div class=\"textbox shaded\" id=\"fs-idp31411280\">\r\n<h3>Example 4<\/h3>\r\n<p id=\"fs-idp163270880\">What is the electron configuration and orbital diagram of:<\/p>\r\n<p id=\"fs-idp13273872\">a) Na<sup>+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>b) P<sup>3\u2013 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>c) Al<sup>2+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>d) Fe<sup>2+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>e) Sm<sup>3+<\/sup><\/p>\r\n&nbsp;\r\n<p id=\"fs-idp66116416\"><strong>Solution<\/strong>\r\nFirst, write out the electron configuration for each parent atom. We have chosen to show the full, unabbreviated configurations to provide more practice for students who want it, but listing the core-abbreviated electron configurations is also acceptable.<\/p>\r\n<p id=\"fs-idp165067840\">Next, determine whether an electron is gained or lost. Remember electrons are negatively charged, so ions with a positive charge have <em>lost<\/em> an electron. For main group elements, the last orbital gains or loses the electron. For transition metals, the last <em>s<\/em> orbital loses an electron before the <em>d<\/em> orbitals.<\/p>\r\n<p id=\"fs-idp106203776\">a) Na: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup>.<\/p>\r\nSodium cation loses one electron, so Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup> = Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>.\r\n<p id=\"fs-idp12929312\">b) P: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>3<\/sup>.<\/p>\r\nPhosphorus trianion gains three electrons, so P<sup>3\u2212<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>.\r\n<p id=\"fs-idp103470240\">c) Al: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup>.<\/p>\r\nAluminum dication loses two electrons Al<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup> =\r\n<p id=\"fs-idp159739376\">Al<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup>.<\/p>\r\n<p id=\"fs-idp229539136\">d) Fe: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup>.<\/p>\r\nIron(II) loses two electrons and, since it is a transition metal, they are removed from the 4<em>s<\/em> orbital Fe<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup> = 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>6<\/sup>.\r\n<p id=\"fs-idp203409520\">e). Sm: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>6<\/sup>.<\/p>\r\nSamarium trication loses three electrons. The first two will be lost from the 6<em>s<\/em> orbital, and the final one is removed from the 4<em>f<\/em> orbital. Sm<sup>3+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>6<\/sup> = 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>4<em>f<\/em><sup>5<\/sup>.\r\n\r\n&nbsp;\r\n<p id=\"fs-idp34533056\"><em><strong>Test Yourself<\/strong><\/em>\r\nWhich ion with a +2 charge has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>5<\/sup>? Which ion with a +3 charge has this configuration?<\/p>\r\n<em><strong>Answers<\/strong><\/em>\r\n\r\nTc<sup>2+<\/sup>, Ru<sup>3+<\/sup>\r\n\r\n<\/div>\r\n<\/section><section id=\"fs-idp19121552\" class=\"summary\">\r\n<div class=\"callout block\" id=\"ball-ch08_s04_n03\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Food and Drink App: Artificial Colors<\/h3>\r\n<p id=\"ball-ch08_s04_p18\" class=\"para\">The color of objects comes from a different mechanism than the colors of neon and other discharge lights. Although colored lights produce their colors, objects are colored because they preferentially reflect a certain color from the white light that shines on them. A red tomato, for example, is bright red because it reflects red light while absorbing all the other colors of the rainbow.<\/p>\r\n<p id=\"ball-ch08_s04_p19\" class=\"para\">Many foods, such as tomatoes, are highly colored; in fact, the common statement \u201cyou eat with your eyes first\u201d is an implicit recognition that the visual appeal of food is just as important as its taste. But what about processed foods?<\/p>\r\n<p id=\"ball-ch08_s04_p20\" class=\"para\">Many processed foods have food coloring added to them. There are two types of food coloring: natural and artificial. Natural food coloring include caramelized sugar for brown; annatto, turmeric, and saffron for various shades of orange or yellow; betanin from beets for purple; and even carmine, a deep red dye that is extracted from the cochineal, a small insect that is a parasite on cacti in Central and South America. (That\u2019s right: you may be eating bug juice!)<\/p>\r\n<p id=\"ball-ch08_s04_p21\" class=\"para\">Some coloring agents are artificial. In the United States, the Food and Drug Administration currently approves only seven compounds as artificial coloring in food, beverages, and cosmetics:<\/p>\r\n\r\n<ol id=\"ball-ch08_s04_l06\" class=\"orderedlist\">\r\n \t<li>FD&amp;C Blue #1: Brilliant Blue FCF<\/li>\r\n \t<li>FD&amp;C Blue #2: Indigotine<\/li>\r\n \t<li>FD&amp;C Green #3: Fast Green FCF<\/li>\r\n \t<li>RD&amp;C Red #3: Erythrosine<\/li>\r\n \t<li>FD&amp;C Red #40: Allura Red AC<\/li>\r\n \t<li>FD&amp;C Yellow #5: Tartrazine<\/li>\r\n \t<li>FD&amp;C Yellow #6: Sunset Yellow FCF<\/li>\r\n<\/ol>\r\n<p id=\"ball-ch08_s04_p22\" class=\"para\">Lower-numbered colors are no longer on the market or have been removed for various reasons. Typically, these artificial coloring agents are large molecules that absorb certain colors of light very strongly, making them useful even at very low concentrations in foods and cosmetics. Even at such low amounts, some critics claim that a small portion of the population (especially children) is sensitive to artificial coloring and urge that their use be curtailed or halted. However, formal studies of artificial coloring and their effects on behaviour have been inconclusive or contradictory. Despite this, most people continue to enjoy processed foods with artificial coloring like those shown in Figure 6.<\/p>\r\n\r\n\r\n[caption id=\"attachment_4707\" align=\"aligncenter\" width=\"600\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Food-Colouring.png\"><img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Food-Colouring-1.png\" alt=\"Food Colouring\" width=\"600\" height=\"361\" class=\"wp-image-4707 size-full\" \/><\/a> <strong>Figure 6.<\/strong> Artificial food coloring are found in a variety of food products, such as processed foods, candies, and egg dyes. Even pet foods have artificial food coloring in them, although it\u2019s likely that the animal doesn\u2019t care! Source: Photo courtesy of Matthew Bland, http:\/\/www.flickr.com\/photos\/matthewbland\/3111904731.[\/caption]\r\n\r\n<div class=\"informalfigure large\" id=\"ball-ch08_s04_f12\">\r\n<div class=\"copyright\">\r\n<p class=\"para\"><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<h2><span style=\"font-family: Roboto, Helvetica, Arial, sans-serif\">Key Concepts and Summary<\/span><\/h2>\r\n<\/div>\r\n<p id=\"fs-idp164262336\">The relative energy of the subshells determine the order in which atomic orbitals are filled (1<em>s<\/em>, 2<em>s<\/em>, 2<em>p<\/em>, 3<em>s<\/em>, 3<em>p<\/em>, 4<em>s<\/em>, 3<em>d<\/em>, 4<em>p<\/em>, and so on). Electron configurations and orbital diagrams can be determined by applying the Pauli exclusion principle (no two electrons can have the same set of four quantum numbers) and Hund\u2019s rule (whenever possible, electrons retain unpaired spins in degenerate orbitals).<\/p>\r\n<p id=\"fs-idp170978096\">Electrons in the outermost orbitals, called valence electrons, are responsible for most of the chemical behavior of elements. In the periodic table, elements with analogous valence electron configurations usually occur within the same group. There are some exceptions to the predicted filling order, particularly when half-filled or completely filled orbitals can be formed. The periodic table can be divided into three categories based on the orbital in which the last electron to be added is placed: main group elements (<em>s<\/em> and <em>p<\/em> orbitals), transition elements (<em>d<\/em> orbitals), and inner transition elements (<em>f<\/em> orbitals).<\/p>\r\n\r\n<\/section><section id=\"fs-idp6359712\" class=\"exercises\">\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n1. Read the labels of several commercial products and identify monatomic ions of at least six main group elements contained in the products. Write the complete electron configurations of these cations and anions.\r\n\r\n2. Using complete subshell notation (1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>, and so forth), predict the electron configuration of each of the following atoms:\r\n<p id=\"fs-idm7894080\">a) N \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) Fe \u00a0 \u00a0 \u00a0d) Te \u00a0 \u00a0 \u00a0e) Tb<\/p>\r\n3. What additional information do we need to answer the question \u201cWhich ion has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>\u201d?\r\n\r\n4. Use an orbital diagram to describe the electron configuration of the valence shell of each of the following atoms:\r\n<p id=\"fs-idp43548048\">a) N \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) Fe \u00a0 \u00a0 \u00a0d) Te \u00a0 \u00a0 \u00a0e) Mo<\/p>\r\n5. Which atom has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>2<\/sup>?\r\n\r\n6. Which ion with a +1 charge has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>? Which ion with a \u20132 charge has this configuration?\r\n\r\n7. Which of the following has two unpaired electrons?\r\n<p id=\"fs-idp36721120\">a) Mg \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) S \u00a0 \u00a0 \u00a0d) Both Mg and S \u00a0 \u00a0 \u00a0e) Both Si and S.<\/p>\r\n8. Which atom would be expected to have a half-filled 4<em>s<\/em> subshell?\r\n\r\n9. Thallium was used as a poison in the Agatha Christie mystery story \u201cThe Pale Horse.\u201d Thallium has two possible cationic forms, +1 and +3. The +1 compounds are the more stable. Write the electron structure of the +1 cation of thallium.\r\n\r\n10. Cobalt\u201360 and iodine\u2013131 are radioactive isotopes commonly used in nuclear medicine. How many protons, neutrons, and electrons are in atoms of these isotopes? Write the complete electron configuration for each isotope.\r\n\r\n<span style=\"font-size: 1em\">11. How many subshells are completely filled with electrons for Na? How many subshells are unfilled?<\/span>\r\n\r\n12. What is the maximum number of electrons in the entire <em class=\"emphasis\">n<\/em> = 2 shell?\r\n\r\n13. Write the complete electron configuration for each atom.\r\n\r\na) \u00a0Si, 14 electrons \u00a0 \u00a0 \u00a0 \u00a0\u00a0b) \u00a0Sc, 21 electrons\r\n\r\n<span style=\"font-size: 1em\">14. \u00a0Write the complete electron configuration for each atom.<\/span>\r\n<div class=\"question\">\r\n\r\na) \u00a0Cd, 48 electrons \u00a0 \u00a0 \u00a0 \u00a0\u00a0b) \u00a0Mg, 12 electrons\r\n\r\n15. Write the abbreviated electron configuration for each atom in Exercise 13.\r\n\r\n<\/div>\r\n<span style=\"font-size: 1em\">16. \u00a0Write the abbreviated electron configuration for each atom in Exercise<\/span>\r\n\r\n<span style=\"font-size: 1em\">17. Where on the periodic table are <\/span><em class=\"emphasis\" style=\"font-size: 1em\">s<\/em><span style=\"font-size: 1em\"> subshells being occupied by electrons?<\/span>\r\n\r\n<span style=\"font-size: 1em\">18. In what block is Ra found?<\/span>\r\n\r\n<span style=\"font-size: 1em\">19. What are the valence shell electron configurations of the elements in the second column of the periodic table?<\/span>\r\n\r\n<span style=\"font-size: 1em\">20. What are the valence shell electron configurations of the elements in the first column of the <\/span><em class=\"emphasis\" style=\"font-size: 1em\">p<\/em><span style=\"font-size: 1em\"> block?<\/span>\r\n\r\n<span style=\"font-size: 1em\">21. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/span>\r\n\r\na) \u00a0Sr \u00a0 \u00a0 \u00a0b) \u00a0S\r\n\r\n<span style=\"font-size: 1em\">22. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/span>\r\n<div class=\"question\">\r\n\r\na) \u00a0V \u00a0 \u00a0 \u00a0b) \u00a0Ar\r\n\r\n<\/div>\r\n<div class=\"question\">\r\n<p id=\"ball-ch08_s04_qs01_qd01_p21\" class=\"para\">23. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/p>\r\na) \u00a0Ge \u00a0 \u00a0 \u00a0b) \u00a0C\r\n\r\n<\/div>\r\n&nbsp;\r\n\r\n<strong>Answers<\/strong>\r\n<p id=\"fs-idp160788800\">1. For example, Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>; \u00a0 \u00a0 Ca<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>;<\/p>\r\nSn<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>; \u00a0 \u00a0 \u00a0F<sup>\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>;\r\n\r\nO<sup>2\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>; \u00a0 \u00a0 \u00a0Cl<sup>\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>.\r\n<p id=\"fs-idp142734304\">2. a) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>3\u00a0<\/sup>\u00a0 \u00a0 \u00a0 b) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>2 \u00a0 \u00a0 \u00a0\u00a0<\/sup>c) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup><\/p>\r\nd) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>4<\/sup>\r\n\r\ne) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>9<\/sup>\r\n<p id=\"fs-idp44502912\">3. The charge on the ion.<\/p>\r\n<p id=\"fs-idp8042528\">4. a)\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2a_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d The first square has a pair of half arrows: one pointing up, and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"331\" height=\"64\" class=\"\" \/><\/p>\r\nb)\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2b_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d The first square has a pair of half arrows: one pointing up and the other down. The first two squares in the row of connected squares contain a single upward pointing arrow. The third square is empty.\" width=\"332\" height=\"61\" class=\"\" \/>\r\n\r\nc)\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2c_img-2.jpg\" alt=\"This figure includes a square followed by 5 squares all connected in a single row. The first square is labeled below as, \u201c4 s.\u201d The connected squares are labeled below as, \u201c3 d.\u201d The first square and the left-most square in the row of connected squares each has a pair of half arrows: one pointing up and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"328\" height=\"59\" class=\"\" \/>\r\n\r\nd)\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2d_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c5 s superscript 2.\u201d The connected squares are labeled below as, \u201c5 p. superscript 4.\u201d The first square and the left-most square in the row of connect squares each has a pair of half arrows: one pointing up and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"327\" height=\"60\" class=\"\" \/>\r\n\r\ne)\r\n<img src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2e_img-2.jpg\" alt=\"This figure includes a square followed by 5 squares all connected in a single row. The first square is labeled below as, \u201c5 s.\u201d The connected squares are labeled below as, \u201c4 d superscript 5.\u201d Each of the squares contains a single upward pointing arrow.\" width=\"326\" height=\"58\" class=\"\" \/>\r\n<p id=\"fs-idp121509792\">5. Zr<\/p>\r\n<p id=\"fs-idp23574064\">6. Rb<sup>+<\/sup>, Se<sup>2\u2212<\/sup><\/p>\r\n<p id=\"fs-idm40971904\">7. Although both b) and c) are correct, e) encompasses both and is the best answer.<\/p>\r\n<p id=\"fs-idp45652512\">8. K<\/p>\r\n<p id=\"fs-idp131047056\">9. 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>14<\/sup>5<em>d<\/em><sup>10<\/sup><\/p>\r\n<p id=\"fs-idp45742624\">10. Co has 27 protons, 27 electrons, and 33 neutrons: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>7<\/sup>.<\/p>\r\nI has 53 protons, 53 electrons, and 78 neutrons: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>5<em>p<\/em><sup>5<\/sup>.\r\n\r\n11.\u00a0Three subshells (1<em class=\"emphasis\">s<\/em>, 2<em class=\"emphasis\">s<\/em>, 2<em class=\"emphasis\">p<\/em>) are completely filled, and one shell (3<em class=\"emphasis\">s<\/em>) is partially filled.\r\n\r\n12.\u00a08 electrons\r\n\r\n13.\u00a0a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0\u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">1<\/sup>\r\n\r\n14.\u00a0a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>\r\n\r\n15.\u00a0a) \u00a0[Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a0[Ar]4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">1<\/sup>\r\n\r\n16.\u00a0a) \u00a0[Kr]5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a0[Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>\r\n\r\n17.\u00a0the first two columns\r\n\r\n<span style=\"font-size: 1em\">18.\u00a0the <\/span><em class=\"emphasis\" style=\"font-size: 1em\">s<\/em><span style=\"font-size: 1em\"> block<\/span>\r\n\r\n<em class=\"emphasis\">19. ns<\/em><sup class=\"superscript\">2<\/sup>\r\n\r\n<em class=\"emphasis\">20. ns<\/em><sup class=\"superscript\">2<\/sup><em class=\"emphasis\">np<\/em><sup class=\"superscript\">1<\/sup>\r\n\r\n21. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">4<\/sup>\r\n\r\n22. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">3 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>\r\n\r\n23. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2<\/sup>\r\n\r\n<\/div>\r\n<\/section>\r\n<div>\r\n<h2>Glossary<\/h2>\r\n<strong>Aufbau principle:\u00a0<\/strong>procedure in which the electron configuration of the elements is determined by \u201cbuilding\u201d them in order of atomic numbers, adding one proton to the nucleus and one electron to the proper subshell at a time\r\n\r\n<strong>core electron:\u00a0<\/strong>electron in an atom that occupies the orbitals of the inner shells\r\n\r\n<strong>electron configuration:\u00a0<\/strong>electronic structure of an atom in its ground state given as a listing of the orbitals occupied by the electrons\r\n\r\n<strong>Hund\u2019s rule:\u00a0<\/strong>every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin\r\n\r\n<strong>orbital diagram:\u00a0<\/strong>pictorial representation of the electron configuration showing each orbital as a box and each electron as a half-arrow\r\n\r\n<strong>valence electrons:<\/strong> are\u00a0<i>the electrons in the outermost shell <\/i>and also include any electrons in partially filled d or f orbitals, as these electrons are also very reactive and have a higher energy despite their lower shell value\u00a0of a ground-state atom; they determine how an element reacts\r\n\r\n<strong>valence shell:\u00a0<\/strong>outermost shell of electrons in a ground-state atom; for main group elements, the orbitals with the highest <em>n<\/em> level (<em>s<\/em> and <em>p<\/em> subshells) are in the valence shell, while for transition metals, the highest energy <em>s<\/em> and <em>d<\/em> subshells make up the valence shell and for inner transition elements, the highest <em>s<\/em>, <em>d,<\/em> and <em>f<\/em> subshells are included\r\n\r\n<\/div>","rendered":"<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<p>By the end of this section, you will be able to:<\/p>\n<ul>\n<li>Derive the predicted ground-state electron configurations of atoms<\/li>\n<li>Identify and explain exceptions to predicted electron configurations for atoms and ions<\/li>\n<li>Relate electron configurations to element classifications in the periodic table<\/li>\n<\/ul>\n<\/div>\n<p id=\"fs-idp32474800\">Having introduced the basics of atomic structure and quantum mechanics, we can use our understanding of quantum numbers to determine how atomic orbitals relate to one another. This allows us to determine which orbitals are occupied by electrons in each atom. The specific arrangement of electrons in orbitals of an atom determines many of the chemical properties of that atom.<\/p>\n<section id=\"fs-idp61895104\">\n<h2>Electronic Structure of Atoms<\/h2>\n<p id=\"fs-idp45944160\">The arrangement of electrons in the orbitals of an atom is called the <strong>electron configuration<\/strong> of the atom. We describe an electron configuration with a symbol that contains three pieces of information (<a href=\"#CNX_Chem_06_04_Econfig\" class=\"autogenerated-content\">Figure 1<\/a>):<\/p>\n<ol id=\"fs-idp16888336\">\n<li>The number of the principal quantum <span style=\"text-decoration: underline\">shell<\/span>, <em>n<\/em>,<\/li>\n<li>The letter that designates the orbital type also called the <span style=\"text-decoration: underline\">subshell<\/span>, and<\/li>\n<li>A superscript number that designates the number of electrons in that particular subshell.<\/li>\n<\/ol>\n<p id=\"fs-idp148323904\">For example, the notation 2<em>p<\/em><sup>4<\/sup> (read &#8220;two\u2013p\u2013four&#8221;) indicates four electrons in a <em>p<\/em> subshell with a principal quantum number (<em>n<\/em>) of 2. The notation 3<em>d<\/em><sup>8<\/sup> (read &#8220;three\u2013d\u2013eight&#8221;) indicates eight electrons in the <em>d<\/em> subshell of the principal shell for which <em>n<\/em> = 3.<\/p>\n<figure id=\"CNX_Chem_06_04_Econfig\"><figcaption>\n<figure style=\"width: 975px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Econfig.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Econfig-2.jpg\" alt=\"A light blue hemisphere is labeled H. At a location about midway between the center and outer edge of the hemisphere, a small yellow-orange sphere is shown that is labeled with a negative sign. To the right of this diagram is the electron configuration 1 s superscript 1. The superscript is shown in a small yellow-orange circle. This superscript is labeled, \u201cNumber of electrons in subshell,\u201d and the s is labeled, \u201cSubshell.\u201d\" width=\"975\" height=\"186\" \/><\/a><figcaption class=\"wp-caption-text\"><strong>Figure 1.<\/strong> Electron configuration of hydrogen is 1s<sup>1<\/sup>, which indicates there is one electron in the s subshell of the principal shell n=1.<\/figcaption><\/figure>\n<\/figcaption><\/figure>\n<\/section>\n<section id=\"fs-idp52797152\">\n<h2>The Aufbau Principle<\/h2>\n<p id=\"fs-idp6137968\">To determine the electron configuration for any particular atom, we can \u201cbuild\u201d the structures in the order of atomic numbers. Beginning with hydrogen, and continuing across the periods of the periodic table, we add one proton at a time to the nucleus and one electron to the proper subshell until we have described the electron configurations of all the elements. This procedure is called the <strong>Aufbau principle<\/strong>, from the German word <em>Aufbau<\/em> (\u201cto build up\u201d). Each added electron occupies the subshell of lowest energy available (in the order shown in <a href=\"#CNX_Chem_06_04_eLeveldiag\" class=\"autogenerated-content\">Figure 4 in section 7.3<\/a>), subject to the limitations imposed by the Pauli exclusion principle. Electrons enter higher-energy subshells only after lower-energy subshells have been filled to capacity. <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> illustrates the traditional way to remember the filling order for atomic orbitals. Since the arrangement of the periodic table is based on the electron configurations, Figure 3 and\u00a0<a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 4<\/a> provides an alternative method for determining the electron configuration. The filling order simply begins at hydrogen and includes each subshell as you proceed in increasing <em>Z<\/em> order. For example, after filling the 3<em>p<\/em> block up to Ar, we see the orbital will be 4s (K, Ca), followed by the 3<em>d<\/em> orbitals.<\/p>\n<figure id=\"CNX_Chem_06_04_Efillorder\"><figcaption>\n<figure style=\"width: 650px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Efillorder.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Efillorder-2.jpg\" alt=\"This figure includes a chart used to order the filling of electrons into atoms. At the top is a blue circle labeled \u201c1 s.\u201d In a row beneath this circle are 6 additional blue circles labeled \u201c2 s\u201d through \u201c7 s.\u201d A column to the right begins just right of 2 s and contains pink circles labeled 2 p through 7 p. A column to the right begins just right of 3 p and contains yellow circles labeled 3 d through 6 d. No circles are placed to the right of the 7 s and 7 p circles. A final column on the right begins right of 4 d. It includes grey circles labeled, \u201c4 f\u201d and, \u201c5 f.\u201d No circles are placed right of 6 d. Through these circles, arrows are included in the figure pointing down and to the left. The first arrow begins in the upper right and passes through 1 s. The second arrow begins just below and passes through 2 s. The third arrow passes through 2 p and 3 s. The fourth arrow passes through 3 p and 4 s. This pattern of parallel arrows pointing downward to the left continues through all circles completing the pattern 1 s 2 s 2 p 3 s 3 p 4 s 3 d 4 p 5 s 4 d 5 p 6 s 4 f 5 d 6 p 7 s 5 f 6 d 7 p.\" width=\"650\" height=\"469\" \/><\/a><figcaption class=\"wp-caption-text\"><strong>Figure 2.<\/strong> The arrow leads through each subshell in the appropriate filling order for electron configurations. This chart is straightforward to construct. Simply make a column for all the s orbitals with each <em>n<\/em> shell on a separate row. Repeat for <em>p<\/em>, <em>d<\/em>, and <em>f<\/em>. Be sure to only include orbitals allowed by the quantum numbers (no 1<em>p<\/em> or 2<em>d<\/em>, and so forth). Finally, draw diagonal lines from top to bottom as shown.<\/figcaption><\/figure>\n<p>&nbsp;<\/p>\n<figure id=\"attachment_2379\" aria-describedby=\"caption-attachment-2379\" style=\"width: 600px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1.png\" alt=\"\" width=\"600\" height=\"357\" class=\"wp-image-2379 size-full\" srcset=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1.png 600w, https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1-300x179.png 300w, https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1-65x39.png 65w, https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1-225x134.png 225w, https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Periodic-Table-Blocks-1-350x208.png 350w\" sizes=\"auto, (max-width: 600px) 100vw, 600px\" \/><\/a><figcaption id=\"caption-attachment-2379\" class=\"wp-caption-text\"><strong>Figure 3.<\/strong> The arrangement of the periodic table is based on electron configurations, therefore the four sections here are coloured to stress the final subshell of each atom.<\/figcaption><\/figure>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<\/figcaption>&nbsp;<\/figure>\n<figure id=\"CNX_Chem_06_04_Econtable\"><figcaption>\n<figure style=\"width: 1300px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Econtable.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Econtable-2.jpg\" alt=\"In this figure, a periodic table is shown that is entitled, \u201cElectron Configuration Table.\u201d Beneath the table, a square for the element hydrogen is shown enlarged to provide detail. The element symbol, H, is placed in the upper left corner. In the upper right is the number of electrons, 1. The lower central portion of the element square contains the subshell, 1 s. Helium and elements in groups 1 and 2 are shaded blue. In this region, the rows are labeled 1 s through 7 s moving down the table. Groups 3 through 12 are shaded orange, and the rows are labeled 3 d through 6 d moving down the table. Groups 13 through 18, except helium, are shaded pink and are labeled 2 p through 6 p moving down the table. The lanthanide and actinide series across the bottom of the table are shaded grey and are labeled 4 f and 5 f respectively.\" width=\"1300\" height=\"1016\" \/><\/a><figcaption class=\"wp-caption-text\"><strong>Figure 4.<\/strong> This periodic table shows the electron configuration for each subshell. By \u201cbuilding up\u201d from hydrogen, this table can be used to determine the electron configuration for any atom on the periodic table.<\/figcaption><\/figure>\n<\/figcaption><\/figure>\n<p id=\"fs-idp96036896\">We will now construct the ground-state electron configuration and orbital diagram for a selection of atoms in the first and second periods of the periodic table. <strong>Orbital diagrams<\/strong> are pictorial representations of the electron configuration, showing the individual orbitals and the pairing arrangement of electrons. We start with a single hydrogen atom (atomic number 1), which consists of one proton and one electron. Referring to <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>, we would expect to find the electron in the 1<em>s<\/em> orbital. By convention, spin up = + \\frac{1}{2}$ value is usually filled first. The electron configuration and the orbital box diagram are:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Hydrog1_img-2.jpg\" alt=\"In this figure, the element symbol H is followed by the electron configuration is 1 s superscript 1. An orbital diagram is provided that consists of a single square. The square is labeled below as, \u201c1 s.\u201d It contains a single upward pointing half arrow.\" class=\"alignnone\" \/><\/p>\n<p>Following hydrogen is the noble gas helium, which has an atomic number of 2. The helium atom contains two protons and two electrons. The two electrons will occupy the same orbital but they will have different spin states, one will be spin-up (<span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><span style=\"font-family: Arial, sans-serif\"><span style=\"font-size: large\">\u02e6<\/span><\/span><\/span><\/span>) and the other spin-down (<span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><span style=\"font-family: Arial, sans-serif\"><span style=\"font-size: large\">\u02e8<\/span><\/span><\/span><\/span>).\u00a0This is in accord with the Pauli exclusion principle. \u00a0For orbital diagrams, this means two half-arrows go in each box (representing two electrons in each orbital) and the half-arrows must point in opposite directions (representing paired spins). The electron configuration and orbital box diagram of helium are:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Helium1_img-2.jpg\" alt=\"In this figure, the element symbol H e is followed by the electron configuration, \u201c1 s superscript 2.\u201d An orbital diagram is provided that consists of a single square. The square is labeled below as \u201c1 s.\u201d It contains a pair of half arrows: one pointing up and the other down.\" class=\"alignnone\" \/><\/p>\n<p id=\"fs-idp9284128\">The <em>n<\/em> = 1 shell is completely filled in a helium atom.<\/p>\n<p id=\"fs-idp29682592\">The next atom is the alkali metal lithium with an atomic number of 3. The first two electrons in lithium fill the 1<em>s<\/em> orbital. \u00a0The remaining electron must occupy the orbital of next lowest energy, the 2<em>s<\/em> orbital (<a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>). Thus, the electron configuration and orbital box diagram of lithium are:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Lithium12_img-2.jpg\" alt=\"In this figure, the element symbol L i is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 1.\u201d An orbital diagram is provided that consists of two individual squares. The first square is labeled below as, \u201c1 s.\u201d The second square is similarly labeled, \u201c2 s.\u201d The first square contains a pair of half arrows: one pointing up and the other down. The second square contains a single upward pointing arrow.\" \/><\/p>\n<p id=\"fs-idp10466880\">An atom of the alkaline earth metal beryllium, with an atomic number of 4, contains four protons in the nucleus and four electrons surrounding the nucleus. The fourth electron fills the remaining space in the 2<em>s<\/em> orbital.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Beryll12_img-2.jpg\" alt=\"In this figure, the element symbol B e is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2.\u201d An orbital diagram is provided that consists of two individual squares. The first square is labeled below as, \u201c1 s.\u201d The second square is similarly labeled, \u201c2 s.\u201d Both squares contain a pair of half arrows: one pointing up and the other down.\" \/><\/p>\n<p id=\"fs-idp164718432\">An atom of boron (atomic number 5) contains five electrons. The <em>n<\/em> = 1 shell is filled with two electrons and three electrons will occupy the <em>n<\/em> = 2 shell. Because any <em>s<\/em> subshell can contain only two electrons, the fifth electron must occupy the next energy level, which will be a 2<em>p<\/em> orbital. There are three <strong>degenerate<\/strong> 2<em>p<\/em> orbitals, meaning they are equal in energy,\u00a0and the electron can occupy any one of these <em>p<\/em> orbitals. When drawing orbital diagrams, we include empty boxes to depict any empty orbitals in the same subshell that we are filling.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Boron122_img-2.jpg\" alt=\"In this figure, the element symbol B is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2 2 p superscript 1.\u201d The orbital diagram consists of two individual squares followed by 3 connected squares in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected contain a pair of half arrows: one pointing up and the other down. The first square in the group of 3 contains a single upward pointing arrow.\" class=\"alignnone\" \/><\/p>\n<p>In the orbital box diagrams, notice the space between the box for the 1s and 2s orbitals &#8211; space between boxes are used to indicate a difference in energy. \u00a0Therefore, a &#8221; lack of space&#8221; between boxes, indicate the orbitals are degenerate, meaning equal in energy.<\/p>\n<p id=\"fs-idp35410400\">Carbon (atomic number 6) has six electrons. Four of them fill the 1<em>s<\/em> and 2<em>s<\/em> orbitals. The remaining two electrons occupy the 2<em>p<\/em> subshell. We now have a choice of filling one of the 2<em>p<\/em> orbitals and pairing the electrons or of leaving the electrons unpaired in two different, but degenerate, <em>p<\/em> orbitals. The orbitals are filled as described by <strong>Hund\u2019s rule<\/strong>: the lowest-energy configuration for an atom with electrons within a set of degenerate orbitals is that having the maximum number of unpaired electrons. Thus, the two electrons in the carbon 2<em>p<\/em> orbitals occupy different p-orbitals &#8211; this minimizes electron-electron repulsion within the atom. \u00a0The electron configuration and orbital box diagram for carbon are:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Carbon122_img-2.jpg\" alt=\"In this figure, the element symbol C is followed by the electron configuration, \u201c1 s superscript 2 2 s superscript 2 2 p superscript 2.\u201d The orbital diagram consists of two individual squares followed by 3 connected squares in a single row. The first blue square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected to each other contain a pair of half arrows: one pointing up and the other down. The first two squares in the group of 3 each contain a single upward pointing arrow.\" class=\"alignnone\" \/><\/p>\n<p id=\"fs-idp243804816\">Nitrogen (atomic number 7) fills the 1<em>s<\/em> and 2<em>s<\/em> subshells and has one electron in each of the three 2<em>p<\/em> orbitals, in accordance with Hund\u2019s rule. These three electrons have unpaired spins. Oxygen (atomic number 8) has a pair of electrons in any one of the 2<em>p<\/em> orbitals (the electrons have opposite spins) and a single electron in each of the other two. Fluorine (atomic number 9) has only one 2<em>p<\/em> orbital containing an unpaired electron. All of the electrons in the noble gas neon (atomic number 10) are paired, and all of the orbitals in the <em>n<\/em> = 1 and the <em>n<\/em> = 2 shells are filled. The electron configurations and orbital box diagrams of these four elements are:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_NOFNe_img-2.jpg\" alt=\"This figure includes electron configurations and orbital diagrams for four elements, N, O, F, and N e. Each diagram consists of two individual squares followed by 3 connected squares in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d All squares not connected to each other contain a pair of half arrows: one pointing up and the other down. For the element N, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 3. Each of the squares in the group of 3 contains a single upward pointing arrow for this element. For the element O, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 4. The first square in the group of 3 contains a pair of arrows and the last two squares contain single upward pointing arrows. For the element F, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 5. The first two squares in the group of 3 each contain a pair of arrows and the last square contains a single upward pointing arrow. For the element N e, the electron configuration is 1 s superscript 2 2 s superscript 2 2 p superscript 6. The squares in the group of 3 each contains a pair of arrows.\" \/><\/p>\n<p id=\"fs-idm31105888\">The alkali metal sodium (atomic number 11) has one more electron than the neon atom. This electron must go into the lowest-energy subshell available, the 3<em>s<\/em> orbital, giving a 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup> configuration. The electrons occupying the outermost shell orbital(s) (highest value of <em>n<\/em>) are called <strong>outer electrons<\/strong>, and those occupying the inner shell orbitals are called <strong>core electrons or inner electrons<\/strong> (<a href=\"#CNX_Chem_06_04_Valence\" class=\"autogenerated-content\">Figure 4<\/a>). \u00a0<strong>Valence electrons\u00a0<\/strong>are outer electrons plus any electrons found in partially filled d or f orbitals. \u00a0Often valence electron are the same as the outer electrons. \u00a0But there are examples where there is a difference. \u00a0Since the core electron shells correspond to noble gas electron configurations, we can abbreviate electron configurations by writing the noble gas that matches the core electron configuration, along with the valence electrons in a condensed format. For our sodium example, the symbol [Ne] represents core electrons, (1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>) and our abbreviated or condensed electron configuration is [Ne]3<em>s<\/em><sup>1<\/sup>.<\/p>\n<figure id=\"CNX_Chem_06_04_Valence\">\n<figure style=\"width: 650px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Valence.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Valence-2.jpg\" alt=\"This figure includes the element symbol N a, followed by the electron configuration for the element. The first part of the electron configuration, 1 s superscript 2 2 s superscript 2 2 p superscript 6, is shaded in purple and is labeled, \u201ccore electrons.\u201d The last portion, 3 s superscript 1, is shaded orange and is labeled, \u201cvalence electron.\u201d To the right of this configuration is the word \u201cAbbreviation\u201d followed by [ N e ] 3 s superscript 1.\" width=\"650\" height=\"111\" \/><\/a><figcaption class=\"wp-caption-text\"><strong>Figure 4.<\/strong> A condensed electron configuration (right) replaces the core electrons with the noble gas symbol whose configuration matches the core electron configuration of the other element.<\/figcaption><\/figure>\n<\/figure>\n<p id=\"fs-idp28826352\">Similarly, the condensed electron configuration of lithium can be represented as [He]2<em>s<\/em><sup>1<\/sup>, where [He] represents the configuration of the helium atom, which is identical to that of the filled inner shell of lithium. Writing the configurations in this way emphasizes the similarity of the configurations of lithium and sodium. Both atoms, which are in the alkali metal family, have only one electron in a valence <em>s<\/em> subshell outside a filled set of inner shells.<\/p>\n<div class=\"equation\" id=\"fs-idp20565040\" style=\"text-align: center\">[latex]\\begin{array}{l} \\text{Li}: [\\text{He}] \\;2s^1 \\\\ \\text{Na}: [\\text{Ne}] \\;3s^1 \\end{array}[\/latex]<\/div>\n<p id=\"fs-idp156268816\">The alkaline earth metal magnesium (atomic number 12), with its 12 electrons in a [Ne]3<em>s<\/em><sup>2<\/sup> configuration, is analogous to its family member beryllium, [He]2<em>s<\/em><sup>2<\/sup>. Both atoms have a filled <em>s<\/em> subshell outside their filled inner shells. Aluminum (atomic number 13), with 13 electrons and the condensed electron configuration [Ne]3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup>, is analogous to its family member boron, [He]2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>1<\/sup>.<\/p>\n<p id=\"fs-idp52824064\">The electron configurations of silicon (14 electrons), phosphorus (15 electrons), sulfur (16 electrons), chlorine (17 electrons), and argon (18 electrons) are analogous in the electron configurations of their outer shells to their corresponding family members carbon, nitrogen, oxygen, fluorine, and neon, respectively, except that the principal quantum number of the outer shell of the heavier elements has increased by one to <em>n<\/em> = 3. <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a> shows the lowest energy, or ground-state, electron configuration for these elements as well as that for atoms of each of the known elements.<\/p>\n<figure id=\"CNX_Chem_06_04_Ptableconf\"><figcaption>\n<figure style=\"width: 1300px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/chemistry\/wp-content\/uploads\/sites\/150\/2016\/05\/CNX_Chem_06_04_Ptableconf.jpg\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_Ptableconf-2.jpg\" alt=\"A periodic table, entitled, \u201cElectron Configuration Table\u201d is shown. The table includes the outer electron configuration information, atomic numbers, and element symbols for all elements. A square for the element hydrogen is pulled out beneath the table to provide detail. The blue shaded square includes the atomic number in the upper left corner, which is 1, the element symbol, H in the upper right corner, and the outer electron configuration in the lower, central portion of the square. For H, this is 1 s superscript 1.\" width=\"1300\" height=\"1016\" \/><\/a><figcaption class=\"wp-caption-text\"><strong>Figure 5.<\/strong> This version of the periodic table shows the outer-shell electron configuration of each element. Note that down each group, the configuration is often similar.<\/figcaption><\/figure>\n<\/figcaption><\/figure>\n<p id=\"fs-idm8891728\">When we come to the next element in the periodic table, the alkali metal potassium (atomic number 19), we might expect that we would begin to add electrons to the 3<em>d<\/em> subshell. However, all available chemical and physical evidence indicates that potassium is like lithium and sodium, and that the next electron is not added to the 3<em>d<\/em> level but is, instead, added to the 4<em>s<\/em> level (<a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>). Thus, potassium has an electron configuration of [Ar]4<em>s<\/em><sup>1<\/sup>. Hence, potassium corresponds to Li and Na in its valence shell configuration. The next electron is added to complete the 4<em>s<\/em> subshell and calcium has an electron configuration of [Ar]4<em>s<\/em><sup>2<\/sup>. This gives calcium an outer-shell electron configuration corresponding to that of beryllium and magnesium.<\/p>\n<p id=\"fs-idp7806208\">Beginning with the transition metal scandium (atomic number 21), additional electrons are added successively to the 3<em>d<\/em> subshell. This subshell is filled to its capacity with 10 electrons. The 4<em>p<\/em> subshell fills next. Note that for three series of elements, scandium (Sc) through copper (Cu), yttrium (Y) through silver (Ag), and lutetium (Lu) through gold (Au), a total of 10 <em>d<\/em> electrons are successively added to the (<em>n<\/em> \u2013 1) shell next to the <em>n<\/em> shell to bring that (<em>n<\/em> \u2013 1) shell from 8 to 18 electrons. For two series, lanthanum (La) through lutetium (Lu) and actinium (Ac) through lawrencium (Lr), 14 <em>f<\/em> electrons are successively added to the (<em>n<\/em> \u2013 2) shell to bring that shell from 18 electrons to a total of 32 electrons.<\/p>\n<div class=\"textbox shaded\" id=\"fs-idp25345424\">\n<h3>Example 1<\/h3>\n<p id=\"fs-idm59921552\">What is the electron configuration and orbital box diagram for a phosphorus atom?<\/p>\n<p>&nbsp;<\/p>\n<p id=\"fs-idp80391584\"><strong>Solution<\/strong><br \/>\nThe atomic number of phosphorus is 15. Thus, a phosphorus atom contains 15 electrons. The order of filling of the energy levels is 1<em>s<\/em>, 2<em>s<\/em>, 2<em>p<\/em>, 3<em>s<\/em>, 3<em>p<\/em>, 4<em>s<\/em>, . . . The 15 electrons of the phosphorus atom will fill up to the 3<em>p<\/em> orbital, which will contain three electrons:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_PhosphOrb_img-2.jpg\" alt=\"This figure provides the electron configuration 1 s superscript 2 2 s superscript 2 2 p superscript 6 3 s superscript 2 3 p superscript 3. It includes a diagram with two individual squares followed by 3 connected squares, a single square, and another connected group of 3 squares all in a single row. The first square is labeled below as, \u201c1 s.\u201d The second is similarly labeled, \u201c2 s.\u201d The first group of connected squares is labeled below as, \u201c2 p.\u201d The square that follows is labeled, \u201c3 s,\u201d and the final group of three squares is labeled, \u201c3 p.\u201d All squares except the last group of three squares has a pair of half arrows: one pointing up and the other down. Each of the squares in the last group of 3 contains a single upward pointing arrow.\" \/><\/p>\n<p id=\"fs-idm6887808\">The last electron added is a 3<em>p<\/em> electron.<\/p>\n<p>&nbsp;<\/p>\n<p id=\"fs-idp40041152\"><em><strong>Test Yourself<\/strong><\/em><\/p>\n<p>Identify the atoms from the condensed electron configurations given:<\/p>\n<p id=\"fs-idp255668160\">a) [Ar]4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>5<\/sup><\/p>\n<p id=\"fs-idp13258240\">b) [Kr]5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup><\/p>\n<p>&nbsp;<\/p>\n<p><em><strong>Answers<\/strong><\/em><\/p>\n<p>a) Mn \u00a0 \u00a0 \u00a0 \u00a0 \u00a0b) Xe<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 2<\/h3>\n<p id=\"ball-ch08_s03_p17\" class=\"para\">a) What is the electron configuration for Na, which has 11 electrons?<\/p>\n<p>b) What is the predicted electron configuration for Sn, which has 50 electrons?<\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong>Solution<\/strong><\/p>\n<p id=\"ball-ch08_s03_p18\" class=\"para\">a) The first two electrons occupy the 1<em class=\"emphasis\">s<\/em> subshell. The next two occupy the 2<em class=\"emphasis\">s<\/em> subshell, while the next six electrons occupy the 2<em class=\"emphasis\">p<\/em> subshell. This gives us 10 electrons so far, with 1 electron left. This last electron goes into the <em class=\"emphasis\">n<\/em> = 3 shell, <em class=\"emphasis\">s<\/em> subshell. Thus, the electron configuration of Na is 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">1<\/sup>.<\/p>\n<p>b) We will follow the chart in Figure 2\u00a0until we can accommodate 50 electrons in the subshells in the proper order:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Sn: 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>5<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2<\/sup><\/span><\/span><\/p>\n<p id=\"ball-ch08_s03_p25\" class=\"para\">Verify by adding the superscripts, which indicate the number of electrons: 2 +\u00a02 +\u00a06 +\u00a02 +\u00a06 +\u00a02 +\u00a010 +\u00a06 +\u00a02 +\u00a010 +\u00a02 = 50, so we have placed all 50 electrons in subshells in the proper order.<\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/strong><\/p>\n<p id=\"ball-ch08_s03_p19\" class=\"para\">a) What is the electron configuration for Mg, which has 12 electrons?<\/p>\n<p>b) What is the electron configuration for Ba, which has 56 electrons?<\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong><em class=\"emphasis\">Answer<\/em><\/strong><\/p>\n<p id=\"ball-ch08_s03_p20\" class=\"para\">a) 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/sup>b) 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>5<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>6<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup><span style=\"background-color: #ffffff;font-size: 1em\">\u00a0<\/span><\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"ball-ch08_s03_p31\" class=\"para\">What is the abbreviated electron configuration for P, which has 15 electrons?<\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong>Solution<\/strong><\/p>\n<p id=\"ball-ch08_s03_p32\" class=\"para\">With 15 electrons, the electron configuration of P is<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">P: 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">3<\/sup><\/span><\/span><\/p>\n<p id=\"ball-ch08_s03_p33\" class=\"para\">The first immediate noble gas is Ne, which has an electron configuration of 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>. Using the electron configuration of Ne to represent the first 10 electrons, the abbreviated electron configuration of P is<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">P: [Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">3<\/sup><\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/strong><\/p>\n<p id=\"ball-ch08_s03_p34\" class=\"para\">What is the abbreviated electron configuration for Rb, which has 37 electrons?<\/p>\n<p>&nbsp;<\/p>\n<p class=\"simpara\"><strong><em class=\"emphasis\">Answer<\/em><\/strong><\/p>\n<p id=\"ball-ch08_s03_p35\" class=\"para\">[Kr]5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">1<\/sup><\/p>\n<\/div>\n<p id=\"fs-idp95342976\">The periodic table can be a powerful tool in predicting the electron configuration of an element. However, we do find exceptions to the order of filling of orbitals that are shown in <a href=\"#CNX_Chem_06_04_Efillorder\" class=\"autogenerated-content\">Figure 2<\/a> or <a href=\"#CNX_Chem_06_04_Econtable\" class=\"autogenerated-content\">Figure 3<\/a>. For instance, the electron configurations (shown in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>) of the transition metals chromium (Cr; atomic number 24) and copper (Cu; atomic number 29), among others, are not those we would expect. In general, such exceptions involve subshells with very similar energy, and small effects can lead to changes in the order of filling.<\/p>\n<p id=\"fs-idp38113648\">In the case of Cr and Cu, we find that half-filled and completely filled subshells apparently represent conditions of preferred stability. This stability is such that an electron shifts from the 4<em>s<\/em> into the 3<em>d<\/em> orbital to gain the extra stability of a half-filled 3<em>d<\/em> subshell (in Cr) or a filled 3<em>d<\/em> subshell (in Cu). Other exceptions also occur. For example, niobium (Nb, atomic number 41) is predicted to have the electron configuration [Kr]5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>3<\/sup>. Experimentally, we observe that its ground-state electron configuration is actually [Kr]5<em>s<\/em><sup>1<\/sup>4<em>d<\/em><sup>4<\/sup>. We can rationalize this observation by saying that the electron\u2013electron repulsions experienced by pairing the electrons in the 5<em>s<\/em> orbital are larger than the gap in energy between the 5<em>s<\/em> and 4<em>d<\/em> orbitals. There is no simple method to predict the exceptions for atoms where the magnitude of the repulsions between electrons is greater than the small differences in energy between subshells.<\/p>\n<\/section>\n<section id=\"fs-idp262041824\">\n<h2>Electron Configurations and the Periodic Table<\/h2>\n<p id=\"fs-idp3828352\">As described earlier, the periodic table arranges atoms based on increasing atomic number so that elements with the same chemical properties recur periodically. When their electron configurations are added to the table (<a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>), we also see a periodic recurrence of similar electron configurations in the outer shells of these elements. Because they are in the outer shells of an atom, valence electrons play the most important role in chemical reactions. The outer electrons have the highest energy of the electrons in an atom and are more easily lost or shared than the core electrons. Valence electrons are also the determining factor in some physical properties of the elements.<\/p>\n<p id=\"fs-idp77726784\">Elements in any one group (or column) have the same number of valence electrons; the alkali metals lithium and sodium each have only one valence electron, the alkaline earth metals beryllium and magnesium each have two, and the halogens fluorine and chlorine each have seven valence electrons. The similarity in chemical properties among elements of the same group occurs because they have the same number of valence electrons. It is the loss, gain, or sharing of valence electrons that defines how elements react.<\/p>\n<p id=\"fs-idp150491632\">It is important to remember that the periodic table was developed on the basis of the chemical behavior of the elements, well before any idea of their atomic structure was available. Now we can understand why the periodic table has the arrangement it has\u2014the arrangement puts elements whose atoms have the same number of valence electrons in the same group. This arrangement is emphasized in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>, which shows in periodic-table form the electron configuration of the last subshell to be filled by the Aufbau principle. The colored sections of <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a> show the three categories of elements classified by the orbitals being filled: main group, transition, and inner transition elements. These classifications determine which orbitals are counted in the <strong>valence shell<\/strong>, or highest energy level orbitals of an atom.<\/p>\n<p>1.<strong> Main group elements<\/strong> (sometimes called <strong>representative elements<\/strong>) are those in which the last electron added enters an <em>s<\/em> or a <em>p<\/em> orbital in the outermost shell, shown in blue and red in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>. This category includes all the nonmetallic elements, as well as many metals and the intermediate semimetallic elements. The valence electrons for main group elements are those with the highest <em>n<\/em> level. For example, gallium (Ga, atomic number 31) has the electron configuration [Ar]<strong>4<em>s<\/em><sup>2<\/sup><\/strong>3<em>d<\/em><sup>10<\/sup><strong>4<em>p<\/em><sup>1<\/sup><\/strong>, which contains three valence electrons (in bold). The completely filled <em>d<\/em> orbitals count as core, not valence, electrons.<\/p>\n<p>2. <strong>Transition elements or transition metals<\/strong>. These are metallic elements in which the last electron added enters a <em>d<\/em> orbital. The valence electrons are\u00a0<i><span>the electrons in the outermost shell <\/span><\/i><span>and also include any electrons in partially filled d or f orbitals, as these electrons are also very reactive and have a higher energy despite their lower shell value. \u00a0<\/span>The official IUPAC definition of transition elements specifies those with partially filled <em>d<\/em> orbitals. Thus, the elements with completely filled orbitals (Zn, Cd, Hg, as well as Cu, Ag, and Au in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>) are not technically transition elements. However, the term is frequently used to refer to the entire <em>d<\/em> block (colored yellow in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>), and we will adopt this usage in this textbook.<\/p>\n<p>3. <strong>Inner transition elements<\/strong> are metallic elements in which the last electron added occupies an <em>f<\/em> orbital. They are shown in green in <a href=\"#CNX_Chem_06_04_Ptableconf\" class=\"autogenerated-content\">Figure 5<\/a>. The valence shells of the inner transition elements consist of the (<em>n<\/em> \u2013 2)<em>f,<\/em> the (<em>n<\/em> \u2013 1)<em>d<\/em>, and the <em>ns<\/em> subshells. There are two inner transition series:<\/p>\n<p>a) The lanthanide series: lanthanide (La) through lutetium (Lu)<\/p>\n<p>b) The actinide series: actinide (Ac) through lawrencium (Lr)<\/p>\n<p id=\"fs-idm11513792\">Lanthanum and actinium, because of their similarities to the other members of the series, are included and used to name the series, even though they are transition metals with no <em>f<\/em> electrons.<\/p>\n<\/section>\n<section id=\"fs-idp32346944\">\n<h2>Electron Configurations of Ions<\/h2>\n<p id=\"fs-idp229254240\">We have seen that ions are formed when atoms gain or lose electrons. A cation (positively charged ion) forms when one or more electrons are removed from a parent atom. For main group elements, the electrons that were added last are the first electrons removed. For transition metals and inner transition metals, however, electrons in the <em>s<\/em>\u00a0\u00a0orbital are easier to remove than the <em>d<\/em>\u00a0\u00a0or <em>f<\/em>\u00a0\u00a0electrons, and so the\u00a0\u00a0highest\u00a0\u00a0<em>ns<\/em>\u00a0\u00a0electrons are lost, and then the (<em>n<\/em> \u2013 1)<em>d<\/em>\u00a0\u00a0or\u00a0\u00a0(<em>n<\/em> \u2013 2)<em>f<\/em> electrons are removed. An anion (negatively charged ion) forms when one or more electrons are added to a parent atom. The added electrons fill in the order predicted by the Aufbau principle.<\/p>\n<div class=\"textbox shaded\" id=\"fs-idp31411280\">\n<h3>Example 4<\/h3>\n<p id=\"fs-idp163270880\">What is the electron configuration and orbital diagram of:<\/p>\n<p id=\"fs-idp13273872\">a) Na<sup>+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>b) P<sup>3\u2013 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>c) Al<sup>2+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>d) Fe<sup>2+ \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/sup>e) Sm<sup>3+<\/sup><\/p>\n<p>&nbsp;<\/p>\n<p id=\"fs-idp66116416\"><strong>Solution<\/strong><br \/>\nFirst, write out the electron configuration for each parent atom. We have chosen to show the full, unabbreviated configurations to provide more practice for students who want it, but listing the core-abbreviated electron configurations is also acceptable.<\/p>\n<p id=\"fs-idp165067840\">Next, determine whether an electron is gained or lost. Remember electrons are negatively charged, so ions with a positive charge have <em>lost<\/em> an electron. For main group elements, the last orbital gains or loses the electron. For transition metals, the last <em>s<\/em> orbital loses an electron before the <em>d<\/em> orbitals.<\/p>\n<p id=\"fs-idp106203776\">a) Na: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup>.<\/p>\n<p>Sodium cation loses one electron, so Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup> = Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>.<\/p>\n<p id=\"fs-idp12929312\">b) P: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>3<\/sup>.<\/p>\n<p>Phosphorus trianion gains three electrons, so P<sup>3\u2212<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>.<\/p>\n<p id=\"fs-idp103470240\">c) Al: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup>.<\/p>\n<p>Aluminum dication loses two electrons Al<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>1<\/sup> =<\/p>\n<p id=\"fs-idp159739376\">Al<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>1<\/sup>.<\/p>\n<p id=\"fs-idp229539136\">d) Fe: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup>.<\/p>\n<p>Iron(II) loses two electrons and, since it is a transition metal, they are removed from the 4<em>s<\/em> orbital Fe<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup> = 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>6<\/sup>.<\/p>\n<p id=\"fs-idp203409520\">e). Sm: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>6<\/sup>.<\/p>\n<p>Samarium trication loses three electrons. The first two will be lost from the 6<em>s<\/em> orbital, and the final one is removed from the 4<em>f<\/em> orbital. Sm<sup>3+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>6<\/sup> = 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>4<em>f<\/em><sup>5<\/sup>.<\/p>\n<p>&nbsp;<\/p>\n<p id=\"fs-idp34533056\"><em><strong>Test Yourself<\/strong><\/em><br \/>\nWhich ion with a +2 charge has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>5<\/sup>? Which ion with a +3 charge has this configuration?<\/p>\n<p><em><strong>Answers<\/strong><\/em><\/p>\n<p>Tc<sup>2+<\/sup>, Ru<sup>3+<\/sup><\/p>\n<\/div>\n<\/section>\n<section id=\"fs-idp19121552\" class=\"summary\">\n<div class=\"callout block\" id=\"ball-ch08_s04_n03\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Food and Drink App: Artificial Colors<\/h3>\n<p id=\"ball-ch08_s04_p18\" class=\"para\">The color of objects comes from a different mechanism than the colors of neon and other discharge lights. Although colored lights produce their colors, objects are colored because they preferentially reflect a certain color from the white light that shines on them. A red tomato, for example, is bright red because it reflects red light while absorbing all the other colors of the rainbow.<\/p>\n<p id=\"ball-ch08_s04_p19\" class=\"para\">Many foods, such as tomatoes, are highly colored; in fact, the common statement \u201cyou eat with your eyes first\u201d is an implicit recognition that the visual appeal of food is just as important as its taste. But what about processed foods?<\/p>\n<p id=\"ball-ch08_s04_p20\" class=\"para\">Many processed foods have food coloring added to them. There are two types of food coloring: natural and artificial. Natural food coloring include caramelized sugar for brown; annatto, turmeric, and saffron for various shades of orange or yellow; betanin from beets for purple; and even carmine, a deep red dye that is extracted from the cochineal, a small insect that is a parasite on cacti in Central and South America. (That\u2019s right: you may be eating bug juice!)<\/p>\n<p id=\"ball-ch08_s04_p21\" class=\"para\">Some coloring agents are artificial. In the United States, the Food and Drug Administration currently approves only seven compounds as artificial coloring in food, beverages, and cosmetics:<\/p>\n<ol id=\"ball-ch08_s04_l06\" class=\"orderedlist\">\n<li>FD&amp;C Blue #1: Brilliant Blue FCF<\/li>\n<li>FD&amp;C Blue #2: Indigotine<\/li>\n<li>FD&amp;C Green #3: Fast Green FCF<\/li>\n<li>RD&amp;C Red #3: Erythrosine<\/li>\n<li>FD&amp;C Red #40: Allura Red AC<\/li>\n<li>FD&amp;C Yellow #5: Tartrazine<\/li>\n<li>FD&amp;C Yellow #6: Sunset Yellow FCF<\/li>\n<\/ol>\n<p id=\"ball-ch08_s04_p22\" class=\"para\">Lower-numbered colors are no longer on the market or have been removed for various reasons. Typically, these artificial coloring agents are large molecules that absorb certain colors of light very strongly, making them useful even at very low concentrations in foods and cosmetics. Even at such low amounts, some critics claim that a small portion of the population (especially children) is sensitive to artificial coloring and urge that their use be curtailed or halted. However, formal studies of artificial coloring and their effects on behaviour have been inconclusive or contradictory. Despite this, most people continue to enjoy processed foods with artificial coloring like those shown in Figure 6.<\/p>\n<figure id=\"attachment_4707\" aria-describedby=\"caption-attachment-4707\" style=\"width: 600px\" class=\"wp-caption aligncenter\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Food-Colouring.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/Food-Colouring-1.png\" alt=\"Food Colouring\" width=\"600\" height=\"361\" class=\"wp-image-4707 size-full\" \/><\/a><figcaption id=\"caption-attachment-4707\" class=\"wp-caption-text\"><strong>Figure 6.<\/strong> Artificial food coloring are found in a variety of food products, such as processed foods, candies, and egg dyes. Even pet foods have artificial food coloring in them, although it\u2019s likely that the animal doesn\u2019t care! Source: Photo courtesy of Matthew Bland, http:\/\/www.flickr.com\/photos\/matthewbland\/3111904731.<\/figcaption><\/figure>\n<div class=\"informalfigure large\" id=\"ball-ch08_s04_f12\">\n<div class=\"copyright\">\n<p class=\"para\">\n<\/div>\n<\/div>\n<\/div>\n<h2><span style=\"font-family: Roboto, Helvetica, Arial, sans-serif\">Key Concepts and Summary<\/span><\/h2>\n<\/div>\n<p id=\"fs-idp164262336\">The relative energy of the subshells determine the order in which atomic orbitals are filled (1<em>s<\/em>, 2<em>s<\/em>, 2<em>p<\/em>, 3<em>s<\/em>, 3<em>p<\/em>, 4<em>s<\/em>, 3<em>d<\/em>, 4<em>p<\/em>, and so on). Electron configurations and orbital diagrams can be determined by applying the Pauli exclusion principle (no two electrons can have the same set of four quantum numbers) and Hund\u2019s rule (whenever possible, electrons retain unpaired spins in degenerate orbitals).<\/p>\n<p id=\"fs-idp170978096\">Electrons in the outermost orbitals, called valence electrons, are responsible for most of the chemical behavior of elements. In the periodic table, elements with analogous valence electron configurations usually occur within the same group. There are some exceptions to the predicted filling order, particularly when half-filled or completely filled orbitals can be formed. The periodic table can be divided into three categories based on the orbital in which the last electron to be added is placed: main group elements (<em>s<\/em> and <em>p<\/em> orbitals), transition elements (<em>d<\/em> orbitals), and inner transition elements (<em>f<\/em> orbitals).<\/p>\n<\/section>\n<section id=\"fs-idp6359712\" class=\"exercises\">\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<p>1. Read the labels of several commercial products and identify monatomic ions of at least six main group elements contained in the products. Write the complete electron configurations of these cations and anions.<\/p>\n<p>2. Using complete subshell notation (1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>, and so forth), predict the electron configuration of each of the following atoms:<\/p>\n<p id=\"fs-idm7894080\">a) N \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) Fe \u00a0 \u00a0 \u00a0d) Te \u00a0 \u00a0 \u00a0e) Tb<\/p>\n<p>3. What additional information do we need to answer the question \u201cWhich ion has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>\u201d?<\/p>\n<p>4. Use an orbital diagram to describe the electron configuration of the valence shell of each of the following atoms:<\/p>\n<p id=\"fs-idp43548048\">a) N \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) Fe \u00a0 \u00a0 \u00a0d) Te \u00a0 \u00a0 \u00a0e) Mo<\/p>\n<p>5. Which atom has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>2<\/sup>?<\/p>\n<p>6. Which ion with a +1 charge has the electron configuration 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>? Which ion with a \u20132 charge has this configuration?<\/p>\n<p>7. Which of the following has two unpaired electrons?<\/p>\n<p id=\"fs-idp36721120\">a) Mg \u00a0 \u00a0 \u00a0b) Si \u00a0 \u00a0 \u00a0c) S \u00a0 \u00a0 \u00a0d) Both Mg and S \u00a0 \u00a0 \u00a0e) Both Si and S.<\/p>\n<p>8. Which atom would be expected to have a half-filled 4<em>s<\/em> subshell?<\/p>\n<p>9. Thallium was used as a poison in the Agatha Christie mystery story \u201cThe Pale Horse.\u201d Thallium has two possible cationic forms, +1 and +3. The +1 compounds are the more stable. Write the electron structure of the +1 cation of thallium.<\/p>\n<p>10. Cobalt\u201360 and iodine\u2013131 are radioactive isotopes commonly used in nuclear medicine. How many protons, neutrons, and electrons are in atoms of these isotopes? Write the complete electron configuration for each isotope.<\/p>\n<p><span style=\"font-size: 1em\">11. How many subshells are completely filled with electrons for Na? How many subshells are unfilled?<\/span><\/p>\n<p>12. What is the maximum number of electrons in the entire <em class=\"emphasis\">n<\/em> = 2 shell?<\/p>\n<p>13. Write the complete electron configuration for each atom.<\/p>\n<p>a) \u00a0Si, 14 electrons \u00a0 \u00a0 \u00a0 \u00a0\u00a0b) \u00a0Sc, 21 electrons<\/p>\n<p><span style=\"font-size: 1em\">14. \u00a0Write the complete electron configuration for each atom.<\/span><\/p>\n<div class=\"question\">\n<p>a) \u00a0Cd, 48 electrons \u00a0 \u00a0 \u00a0 \u00a0\u00a0b) \u00a0Mg, 12 electrons<\/p>\n<p>15. Write the abbreviated electron configuration for each atom in Exercise 13.<\/p>\n<\/div>\n<p><span style=\"font-size: 1em\">16. \u00a0Write the abbreviated electron configuration for each atom in Exercise<\/span><\/p>\n<p><span style=\"font-size: 1em\">17. Where on the periodic table are <\/span><em class=\"emphasis\" style=\"font-size: 1em\">s<\/em><span style=\"font-size: 1em\"> subshells being occupied by electrons?<\/span><\/p>\n<p><span style=\"font-size: 1em\">18. In what block is Ra found?<\/span><\/p>\n<p><span style=\"font-size: 1em\">19. What are the valence shell electron configurations of the elements in the second column of the periodic table?<\/span><\/p>\n<p><span style=\"font-size: 1em\">20. What are the valence shell electron configurations of the elements in the first column of the <\/span><em class=\"emphasis\" style=\"font-size: 1em\">p<\/em><span style=\"font-size: 1em\"> block?<\/span><\/p>\n<p><span style=\"font-size: 1em\">21. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/span><\/p>\n<p>a) \u00a0Sr \u00a0 \u00a0 \u00a0b) \u00a0S<\/p>\n<p><span style=\"font-size: 1em\">22. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/span><\/p>\n<div class=\"question\">\n<p>a) \u00a0V \u00a0 \u00a0 \u00a0b) \u00a0Ar<\/p>\n<\/div>\n<div class=\"question\">\n<p id=\"ball-ch08_s04_qs01_qd01_p21\" class=\"para\">23. From the element\u2019s position on the periodic table, predict the electron configuration of each atom.<\/p>\n<p>a) \u00a0Ge \u00a0 \u00a0 \u00a0b) \u00a0C<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<p><strong>Answers<\/strong><\/p>\n<p id=\"fs-idp160788800\">1. For example, Na<sup>+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>; \u00a0 \u00a0 Ca<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>;<\/p>\n<p>Sn<sup>2+<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>; \u00a0 \u00a0 \u00a0F<sup>\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>;<\/p>\n<p>O<sup>2\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>; \u00a0 \u00a0 \u00a0Cl<sup>\u2013<\/sup>: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>.<\/p>\n<p id=\"fs-idp142734304\">2. a) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>3\u00a0<\/sup>\u00a0 \u00a0 \u00a0 b) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>2 \u00a0 \u00a0 \u00a0\u00a0<\/sup>c) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>6<\/sup><\/p>\n<p>d) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>4<\/sup><\/p>\n<p>e) 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>p<\/em><sup>6<\/sup>5<em>s<\/em><sup>2<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>9<\/sup><\/p>\n<p id=\"fs-idp44502912\">3. The charge on the ion.<\/p>\n<p id=\"fs-idp8042528\">4. a)<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2a_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d The first square has a pair of half arrows: one pointing up, and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"331\" height=\"64\" class=\"\" \/><\/p>\n<p>b)<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2b_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c2 s.\u201d The connected squares are labeled below as, \u201c2 p.\u201d The first square has a pair of half arrows: one pointing up and the other down. The first two squares in the row of connected squares contain a single upward pointing arrow. The third square is empty.\" width=\"332\" height=\"61\" class=\"\" \/><\/p>\n<p>c)<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2c_img-2.jpg\" alt=\"This figure includes a square followed by 5 squares all connected in a single row. The first square is labeled below as, \u201c4 s.\u201d The connected squares are labeled below as, \u201c3 d.\u201d The first square and the left-most square in the row of connected squares each has a pair of half arrows: one pointing up and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"328\" height=\"59\" class=\"\" \/><\/p>\n<p>d)<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2d_img-2.jpg\" alt=\"This figure includes a square followed by 3 squares all connected in a single row. The first square is labeled below as, \u201c5 s superscript 2.\u201d The connected squares are labeled below as, \u201c5 p. superscript 4.\u201d The first square and the left-most square in the row of connect squares each has a pair of half arrows: one pointing up and the other down. Each of the remaining squares contains a single upward pointing arrow.\" width=\"327\" height=\"60\" class=\"\" \/><\/p>\n<p>e)<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-content\/uploads\/sites\/387\/2018\/04\/CNX_Chem_06_04_OrbDiaSh2e_img-2.jpg\" alt=\"This figure includes a square followed by 5 squares all connected in a single row. The first square is labeled below as, \u201c5 s.\u201d The connected squares are labeled below as, \u201c4 d superscript 5.\u201d Each of the squares contains a single upward pointing arrow.\" width=\"326\" height=\"58\" class=\"\" \/><\/p>\n<p id=\"fs-idp121509792\">5. Zr<\/p>\n<p id=\"fs-idp23574064\">6. Rb<sup>+<\/sup>, Se<sup>2\u2212<\/sup><\/p>\n<p id=\"fs-idm40971904\">7. Although both b) and c) are correct, e) encompasses both and is the best answer.<\/p>\n<p id=\"fs-idp45652512\">8. K<\/p>\n<p id=\"fs-idp131047056\">9. 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>5<em>p<\/em><sup>6<\/sup>6<em>s<\/em><sup>2<\/sup>4<em>f<\/em><sup>14<\/sup>5<em>d<\/em><sup>10<\/sup><\/p>\n<p id=\"fs-idp45742624\">10. Co has 27 protons, 27 electrons, and 33 neutrons: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>4<em>s<\/em><sup>2<\/sup>3<em>d<\/em><sup>7<\/sup>.<\/p>\n<p>I has 53 protons, 53 electrons, and 78 neutrons: 1<em>s<\/em><sup>2<\/sup>2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>6<\/sup>3<em>s<\/em><sup>2<\/sup>3<em>p<\/em><sup>6<\/sup>3<em>d<\/em><sup>10<\/sup>4<em>s<\/em><sup>2<\/sup>4<em>p<\/em><sup>6<\/sup>4<em>d<\/em><sup>10<\/sup>5<em>s<\/em><sup>2<\/sup>5<em>p<\/em><sup>5<\/sup>.<\/p>\n<p>11.\u00a0Three subshells (1<em class=\"emphasis\">s<\/em>, 2<em class=\"emphasis\">s<\/em>, 2<em class=\"emphasis\">p<\/em>) are completely filled, and one shell (3<em class=\"emphasis\">s<\/em>) is partially filled.<\/p>\n<p>12.\u00a08 electrons<\/p>\n<p>13.\u00a0a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0\u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">1<\/sup><\/p>\n<p>14.\u00a0a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup><\/p>\n<p>15.\u00a0a) \u00a0[Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a0[Ar]4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">1<\/sup><\/p>\n<p>16.\u00a0a) \u00a0[Kr]5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>4<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a0[Ne]3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup><\/p>\n<p>17.\u00a0the first two columns<\/p>\n<p><span style=\"font-size: 1em\">18.\u00a0the <\/span><em class=\"emphasis\" style=\"font-size: 1em\">s<\/em><span style=\"font-size: 1em\"> block<\/span><\/p>\n<p><em class=\"emphasis\">19. ns<\/em><sup class=\"superscript\">2<\/sup><\/p>\n<p><em class=\"emphasis\">20. ns<\/em><sup class=\"superscript\">2<\/sup><em class=\"emphasis\">np<\/em><sup class=\"superscript\">1<\/sup><\/p>\n<p>21. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>5<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">4<\/sup><\/p>\n<p>22. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">3 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\n<p>23. a) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>4<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">d<\/em><sup class=\"superscript\">10<\/sup>4<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2 \u00a0 \u00a0 \u00a0<\/sup>b) \u00a01<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">2<\/sup><\/p>\n<\/div>\n<\/section>\n<div>\n<h2>Glossary<\/h2>\n<p><strong>Aufbau principle:\u00a0<\/strong>procedure in which the electron configuration of the elements is determined by \u201cbuilding\u201d them in order of atomic numbers, adding one proton to the nucleus and one electron to the proper subshell at a time<\/p>\n<p><strong>core electron:\u00a0<\/strong>electron in an atom that occupies the orbitals of the inner shells<\/p>\n<p><strong>electron configuration:\u00a0<\/strong>electronic structure of an atom in its ground state given as a listing of the orbitals occupied by the electrons<\/p>\n<p><strong>Hund\u2019s rule:\u00a0<\/strong>every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin<\/p>\n<p><strong>orbital diagram:\u00a0<\/strong>pictorial representation of the electron configuration showing each orbital as a box and each electron as a half-arrow<\/p>\n<p><strong>valence electrons:<\/strong> are\u00a0<i>the electrons in the outermost shell <\/i>and also include any electrons in partially filled d or f orbitals, as these electrons are also very reactive and have a higher energy despite their lower shell value\u00a0of a ground-state atom; they determine how an element reacts<\/p>\n<p><strong>valence shell:\u00a0<\/strong>outermost shell of electrons in a ground-state atom; for main group elements, the orbitals with the highest <em>n<\/em> level (<em>s<\/em> and <em>p<\/em> subshells) are in the valence shell, while for transition metals, the highest energy <em>s<\/em> and <em>d<\/em> subshells make up the valence shell and for inner transition elements, the highest <em>s<\/em>, <em>d,<\/em> and <em>f<\/em> subshells are included<\/p>\n<\/div>\n","protected":false},"author":330,"menu_order":5,"template":"","meta":{"pb_show_title":"on","pb_short_title":"8.4 Electronic Structure of Atoms","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"chapter-type":[],"contributor":[],"license":[54],"class_list":["post-1528","chapter","type-chapter","status-publish","hentry","license-cc-by-nc-sa"],"part":2362,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/1528","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/users\/330"}],"version-history":[{"count":21,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/1528\/revisions"}],"predecessor-version":[{"id":4851,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/1528\/revisions\/4851"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/parts\/2362"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/1528\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/media?parent=1528"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapter-type?post=1528"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/contributor?post=1528"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/license?post=1528"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}