{"id":3475,"date":"2018-05-08T14:37:45","date_gmt":"2018-05-08T18:37:45","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/?post_type=chapter&#038;p=3475"},"modified":"2019-06-20T13:58:22","modified_gmt":"2019-06-20T17:58:22","slug":"4-4-end-of-chapter-problems","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/chapter\/4-4-end-of-chapter-problems\/","title":{"raw":"4.4 End of Chapter Problems","rendered":"4.4 End of Chapter Problems"},"content":{"raw":"<p class=\"Questions\">1. Name the following:\r\na)<span>\u00a0 <\/span>CaC<sub>2<\/sub>H<sub>3<\/sub>O<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>Fe<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>S<sub>2<\/sub>F<sub>5<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>H<sub>2<\/sub>SO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>CuNO<sub>3<\/sub>\r\nf)<span>\u00a0 <\/span>PbCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0 <\/span>PF<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>KMnO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0<\/span>B<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0 <\/span>HNO<sub>2<\/sub><\/p>\r\n<p class=\"Questions\">2. Name the following:\r\na)<span>\u00a0 <\/span>CoCl<sub>2<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/sub>b)<span>\u00a0<\/span>Cr(OH)<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>ICl<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>Mg<sub>3<\/sub>P<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>Ag<sub>3<\/sub>N\r\nf)<span>\u00a0 <\/span>NH<sub>4<\/sub>F<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0 <\/span>BaO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>Na<sub>3<\/sub>As<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>ZnBr<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0<\/span>SF<sub>6<\/sub>\r\nk)<span>\u00a0 <\/span>Ba(NO<sub>3<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0<\/span>Ni(ClO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>m)<span>\u00a0 <\/span>Zn(ClO<sub>2<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0<\/span>HNO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>Ca(MnO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span>\r\np)<span>\u00a0 <\/span>CuHCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>q)<span>\u00a0<\/span>HF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>NH<sub>4<\/sub>HSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>s)<span>\u00a0<\/span>HgO<\/p>\r\n<p class=\"Questions\">3. Name the following:\r\na)<span>\u00a0 <\/span>Cd<sub>3<\/sub>P<sub>2<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/sub>b)<span>\u00a0 <\/span>H<sub>2<\/sub>SO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) (NH<sub>4<\/sub>)<sub>2<\/sub>S<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0<\/span>MnF<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0 <\/span>Al<sub>2<\/sub>O<sub>3<\/sub>\r\nf)<span>\u00a0\u00a0 <\/span>HCN<span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>g)<span>\u00a0 <\/span>OF<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>CrN<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>Co<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0 <\/span>P<sub>2<\/sub>O<sub>3<\/sub>\r\nk)<span>\u00a0\u00a0 <\/span>CS<sub>2<\/sub><span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>l)<span>\u00a0 <\/span>CdO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>m)<span>\u00a0 <\/span>AsH<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0 <\/span>IF<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>FePO<sub>4<\/sub>\r\np)<span>\u00a0 <\/span>H<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/span>q)<span>\u00a0 <\/span>TiO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>HClO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>s)<span>\u00a0<\/span>HI<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/p>\r\n<p class=\"Questions\">4. Determine the formula for the following compounds:\r\na)<span>\u00a0 <\/span>aluminum sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>ammonium iodide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>nickel(II) iodide\r\nd)<span>\u00a0 <\/span>lithium phosphide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0 <\/span>gold(III) phosphide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>phosphoric acid\r\ng)<span>\u00a0 <\/span>lithium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>nickel(II) phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>bromic acid\r\nj)<span>\u00a0 <\/span>xenon dioxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k)<span>\u00a0<\/span>bromine monofluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0 <\/span>aluminum bisulfate\r\nm)<span>\u00a0 <\/span>cobalt(II) carbonate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0<\/span>potassium phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>lithium nitrite<\/p>\r\n<p class=\"Questions\">5. Determine the formula for the following compounds:\r\na)<span>\u00a0 <\/span>gold(III) chloride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>iron(III) oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0<\/span>chloric acid\r\nd)<span>\u00a0 <\/span>manganese(II) bromide<span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>cobalt(II) hydroxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>arsenic dioxide\r\ng)<span>\u00a0 <\/span>copper(II) hydroxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>sulfurous acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>calcium iodide\r\nj)<span>\u00a0 <\/span>cadmium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k)<span>\u00a0<\/span>nitrogen triiodide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0 <\/span>sulfur monoxide\r\n<span lang=\"IT\">m)<span>\u00a0<\/span>iron(III) chromate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0 <\/span>boron trihydride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0<\/span>manganese(III) oxide\r\n<\/span>p)<span>\u00a0 <\/span>sulfur hexafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>q)<span>\u00a0<\/span>strontium hypochlorite<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>cobalt(II) phosphate\r\ns)<span>\u00a0 <\/span>magnesium bicarbonate<\/p>\r\n<p class=\"Questions\">6. Write the formula for the following:\r\na)<span>\u00a0 <\/span>chloric acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>xenon hexafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>iron(III) nitrate\r\nd)<span>\u00a0 <\/span>acetic acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>chromium(III) sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>lithium hydrogen carbonate\r\ng)<span>\u00a0 <\/span>aluminum oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>hydrofluoric acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>copper(II) permanganate<\/p>\r\n7.\u00a0Name each molecule:\r\n\r\na) PF<sub class=\"subscript\">3<\/sub> \u00a0 \u00a0 \u00a0 \u00a0 b)\u00a0CO \u00a0 \u00a0 \u00a0 \u00a0 c)\u00a0Se<sub class=\"subscript\">2<\/sub>Br<sub class=\"subscript\">2 \u00a0 \u00a0 \u00a0\u00a0<\/sub>d) SF<sub class=\"subscript\">4<\/sub>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0e)\u00a0P<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">5 \u00a0 \u00a0 \u00a0 \u00a0<\/sub>f)\u00a0N<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0<\/span>PCl<sub>5<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) O<sub>2<\/sub>F<sub>2 \u00a0<\/sub>\r\n\r\ni) CO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0<\/span>SeF<sub>6<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) NO\r\n\r\n8.\u00a0Name the following ionic compounds:\r\na)<span>\u00a0 <\/span>CuSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>FeBr<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>CsClO<sub>4<\/sub>\r\nd)<span>\u00a0 <\/span>(NH<sub>4<\/sub>)<sub>2<\/sub>Cr<sub>2<\/sub>O<sub>7<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>KHSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>CrF<sub>2<\/sub>\r\n\r\n9.\u00a0Determine the formula for the following ionic compounds:\r\n<p class=\"Indent\">a)<span>\u00a0 <\/span>manganese(IV) oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>magnesium perchlorate\r\nc)<span>\u00a0<\/span>antimony(III) nitrate \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<span><\/span>d)<span>\u00a0 <\/span>sodium iodide<\/p>\r\n10.\u00a0Determine the formula for the following ionic compounds:\r\na)<span>\u00a0 <\/span>potassium permanganate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>iron(II) sulfate\r\nc)<span>\u00a0 <\/span>sodium phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>copper(II) nitride\r\ne)<span>\u00a0 <\/span>aluminum sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>chromium(III) oxide\r\n\r\n11.\u00a0Determine the chemical formula for each of the following:\r\n<p class=\"Indent\"><span>\u00a0<\/span>a)<span>\u00a0 <\/span>dinitrogen pentoxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>hydrochloric acid \u00a0 \u00a0 \u00a0 \u00a0 \u00a0c)<span>\u00a0<\/span>hypochlorous acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>nitric acid<\/p>\r\n12.\u00a0Determine the chemical formulas of the following:\r\n<p class=\"Indent\"><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>a)<span>\u00a0 <\/span>boron trifluoride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>bromic acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0<\/span>sulfurous acid<\/p>\r\n\r\n<h2><\/h2>\r\n<h2>Answers<\/h2>\r\n<p class=\"Answers\">1.<span>\u00a0 <\/span>a) calcium acetate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) iron(III) oxide<span>\u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>c) disulfur pentafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) sulfurous acid<span>\u00a0 <\/span>\r\ne) copper(I) nitrate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) lead(II) carbonate<span>\u00a0 \u00a0 \u00a0\u00a0<\/span>g) phosphorous tetrafluoride<span>\u00a0 \u00a0 \u00a0\u00a0<\/span>h) potassium permanganate<span>\u00a0 <\/span>\r\ni) diboron trioxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) nitrous acid<\/p>\r\n<p class=\"Answers\">2.<span>\u00a0 <\/span>a) cobalt(II) chloride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>b) chromium(III) hydroxide \u00a0\u00a0c) iodine monochloride<span>\u00a0 <\/span>d) magnesium phosphide\r\ne) silver nitride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) ammonium fluoride \u00a0 \u00a0g) barium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) sodium arsenide\r\ni) zinc bromide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) sulfur hexafluoride \u00a0\u00a0k) barium nitrate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) nickel(II) perchlorate\r\nm) zinc chlorite<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n) nitric acid \u00a0 \u00a0o) calcium permanganate \u00a0 \u00a0 \u00a0p) copper(I) hydrogen carbonate<span>\u00a0\u00a0 <\/span><\/p>\r\n<p class=\"Answers\">q) hydrofluoric acid \u00a0 \u00a0r) ammonium hydrogen sulfate<span>\u00a0\u00a0 <\/span>s) mercury(II) oxide<\/p>\r\n<p class=\"Answers\">3.<span>\u00a0 <\/span>a) cadmium phosphide<span>\u00a0 <\/span>b) sulphurous acid \u00a0\u00a0c) ammonium sulfide<span>\u00a0\u00a0\u00a0 <\/span>d) manganese(III) fluoride\r\ne) aluminum oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) hydrocyanic acid \u00a0 \u00a0g) oxygen difluoride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>h) chromium(III) nitride\r\ni) cobalt(III) sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) diphosphorous trioxide \u00a0 \u00a0k) carbon disulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) cadmium oxide\r\nm) arsenic trihydride<span>\u00a0\u00a0\u00a0 <\/span>n) iodine trifluoride \u00a0 \u00a0o) iron(III) phosphate<span>\u00a0\u00a0\u00a0 <\/span>p) phosphoric acid\r\nq) titanium(IV) oxide<span>\u00a0\u00a0\u00a0\u00a0 <\/span>r) hypochlorous acid \u00a0 \u00a0s) hydroiodic acid<\/p>\r\n<p class=\"Answers\"><span lang=\"IT\">4.<span>\u00a0 <\/span>a) Al<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) NH<sub>4<\/sub>I<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) NiI<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) Li<sub>3<\/sub>P \u00a0 \u00a0e) AuP<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) H<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g) Li<sub>2<\/sub>O<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) Ni<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub>\r\ni) HBrO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) XeO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) BrF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) Al(HSO<sub>4<\/sub>)<sub>3 \u00a0 \u00a0<\/sub>m) CoCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span>n) K<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span>o) LiNO<sub>2<\/sub><\/span><\/p>\r\n<p class=\"Answers\"><span lang=\"IT\">5.<span>\u00a0 <\/span>a) AuCl<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) Fe<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) HClO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) MnBr<sub>2 \u00a0 \u00a0 \u00a0<\/sub>e) Co(OH)<sub>2<\/sub><span>\u00a0\u00a0\u00a0 <\/span>f) AsO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g) Cu(OH)<sub>2<\/sub><span>\u00a0\u00a0 <\/span>h) H<sub>2<\/sub>SO<sub>3<\/sub>\r\ni) CaI<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) CdO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) NI<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) SO \u00a0 \u00a0\u00a0m) Fe(CrO<sub>4<\/sub>)<sub>3<\/sub><span>\u00a0 <\/span>n) BH<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o) Mn<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>p) SF<sub>6<\/sub>\r\nq) SrClO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r) Co<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0 <\/span>s) Mg(HCO<sub>3<\/sub>)<sub>2<\/sub><\/span><\/p>\r\n<p class=\"Answers\"><span lang=\"PT-BR\">6.<span>\u00a0 <\/span>a) HClO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) XeF<sub>6<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) Fe(NO<sub>3<\/sub>)<sub>3 \u00a0\u00a0<\/sub>d) CH<sub>3<\/sub>COOH<span>\u00a0 <\/span>e) Cr<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) LiHCO<sub>3<\/sub>\r\ng) Al<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) HF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i) Cu(MnO<sub>4<\/sub>)<sub>2<\/sub><\/span><\/p>\r\n7. \u00a0a) phosphorus trifluoride \u00a0b) carbon monoxide \u00a0 c) <em class=\"emphasis\">diselenium dibromide<\/em>\r\n<p class=\"simpara\">d) sulfur tetrafluoride \u00a0 \u00a0 \u00a0 e)\u00a0diphosphorus pentasulfide \u00a0 \u00a0 \u00a0 \u00a0\u00a0<span lang=\"PT-BR\">f) dinitrogen trioxide \u00a0 \u00a0 \u00a0 \u00a0<\/span><\/p>\r\n<p class=\"simpara\"><span lang=\"PT-BR\">g) phosphorous pentachloride \u00a0 \u00a0 \u00a0 \u00a0h) dioxin difluoride \u00a0 \u00a0 \u00a0 \u00a0 \u00a0i) carbon dioxide\u00a0<\/span><\/p>\r\n<p class=\"simpara\"><span lang=\"PT-BR\">j) selenium hexafluoride \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0k) nitrogen monoxide<\/span><\/p>\r\n8.\u00a0a) copper(II) sulfate \u00a0 \u00a0 \u00a0b) iron(III) bromide \u00a0 \u00a0 \u00a0<span>\u00a0<\/span>c) cesium perchlorate \u00a0 \u00a0 \u00a0<span>\u00a0\u00a0<\/span>d) ammonium dichromate\r\n\r\ne) potassium hydrogen sulfate \u00a0 \u00a0 \u00a0<span>\u00a0\u00a0<\/span>f) chromium(II) fluoride\r\n\r\n9.\u00a0<span>\u00a0 <\/span>a)<span>\u00a0 <\/span>First, identify the anion and cation and their charges. Manganese is Mn, and we are told from the name (type II) that it has a charge of +4. Oxide is O<sup>2-<\/sup>. \u00a0Now, do the \u201ccross\u201d method of the charges, and reduce: manganese(IV) oxide = MnO<sub>2<\/sub>\r\n<p class=\"Indentpoints\">b)<span>\u00a0 <\/span>Magnesium is Mg<sup>2+<\/sup>(type I), and perchlorate is ClO<sub>4<\/sub><sup>-<\/sup>;<span>\u00a0 <\/span>magnesium perchlorate = Mg(ClO<sub>4<\/sub>)<sub>2<\/sub><\/p>\r\n<p class=\"Indentpoints\">c)<span>\u00a0 <\/span>Antimony(III) is Sb with a charge of +3, according to the type II name. Nitrate is NO<sub>3<\/sub><sup>-<\/sup><\/p>\r\n<p class=\"Indentpoints\"><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>antimony(III) nitrate = Sb(NO<sub>3<\/sub>)<sub>3<\/sub><\/p>\r\n<p class=\"Indentpoints\">d)<span>\u00a0 <\/span>Sodium is Na<sup>+<\/sup>and iodide is I<sup>-<\/sup><span>\u00a0\u00a0 <\/span>;<span>\u00a0 <\/span>sodium iodide = NaI<\/p>\r\n10.\u00a0<span lang=\"PT-BR\"><span> <\/span>a) KMnO<sub>4 \u00a0<\/sub><span>\u00a0\u00a0<\/span>b) FeSO<sub>4\u00a0<\/sub><span>\u00a0 \u00a0<\/span>c) Na<sub>3<\/sub>PO<sub>4\u00a0<\/sub>\u00a0 \u00a0\u00a0d) Cu<sub>3<\/sub>N<sub>2 \u00a0<\/sub><span>\u00a0\u00a0<\/span>e) Al<sub>2<\/sub>S<sub>3 \u00a0\u00a0<\/sub><span>\u00a0<\/span>f) Cr<sub>2<\/sub>O<sub>3<\/sub><\/span>\r\n\r\n11.a)<span>\u00a0 <\/span>Dinitrogen means 2 nitrogen atoms and pentoxide is five oxygen atoms = N<sub>2<\/sub>O<sub>5<\/sub>\r\n<p class=\"Indentpoints\">b)<span>\u00a0 <\/span>Hydro means that it must be a general acid. \u201cChlor\u201d is the root for Cl, which has a charge of \u20131. Thus H<sup>+<\/sup>and Cl<sup>-<\/sup>together make HCl (note that we have to treat this as an ionic compound, the charges must balance).<\/p>\r\n<p class=\"Indentpoints\">c)<span>\u00a0 <\/span>Be careful!<span>\u00a0 <\/span>Hypo does NOT mean it is a general acid. It is simply the prefix for the polyatomic oxyanion. Because the ending is \u201cous\u201d, we know that the ion ending must be \u201cite\u201d. Thus, this originates from the hypochlorite ion = ClO<sup>-<\/sup>. Together with H<sup>+<\/sup>this makes HClO.<\/p>\r\n<p class=\"Indentpoints\">d)<span>\u00a0 <\/span>\u201cNitric\u201d tells us that this originates from the nitrate ion = NO<sub>3<\/sub><sup>-<\/sup>. With H<sup>+<\/sup>, this makes HNO<sub>3<\/sub><\/p>\r\n12.\u00a0<span lang=\"PT-BR\"><span><\/span>a) BF<sub>3<\/sub>;<span>\u00a0 <\/span>b) HBrO<sub>3<\/sub>;<span>\u00a0 <\/span>c) H<sub>2<\/sub>SO<sub>3<\/sub><\/span>","rendered":"<p class=\"Questions\">1. Name the following:<br \/>\na)<span>\u00a0 <\/span>CaC<sub>2<\/sub>H<sub>3<\/sub>O<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>Fe<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>S<sub>2<\/sub>F<sub>5<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>H<sub>2<\/sub>SO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>CuNO<sub>3<\/sub><br \/>\nf)<span>\u00a0 <\/span>PbCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0 <\/span>PF<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>KMnO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0<\/span>B<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0 <\/span>HNO<sub>2<\/sub><\/p>\n<p class=\"Questions\">2. Name the following:<br \/>\na)<span>\u00a0 <\/span>CoCl<sub>2<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/sub>b)<span>\u00a0<\/span>Cr(OH)<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>ICl<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>Mg<sub>3<\/sub>P<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>Ag<sub>3<\/sub>N<br \/>\nf)<span>\u00a0 <\/span>NH<sub>4<\/sub>F<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0 <\/span>BaO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>Na<sub>3<\/sub>As<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>ZnBr<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0<\/span>SF<sub>6<\/sub><br \/>\nk)<span>\u00a0 <\/span>Ba(NO<sub>3<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0<\/span>Ni(ClO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>m)<span>\u00a0 <\/span>Zn(ClO<sub>2<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0<\/span>HNO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>Ca(MnO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span><br \/>\np)<span>\u00a0 <\/span>CuHCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>q)<span>\u00a0<\/span>HF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>NH<sub>4<\/sub>HSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>s)<span>\u00a0<\/span>HgO<\/p>\n<p class=\"Questions\">3. Name the following:<br \/>\na)<span>\u00a0 <\/span>Cd<sub>3<\/sub>P<sub>2<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/sub>b)<span>\u00a0 <\/span>H<sub>2<\/sub>SO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) (NH<sub>4<\/sub>)<sub>2<\/sub>S<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0<\/span>MnF<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0 <\/span>Al<sub>2<\/sub>O<sub>3<\/sub><br \/>\nf)<span>\u00a0\u00a0 <\/span>HCN<span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>g)<span>\u00a0 <\/span>OF<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0 <\/span>CrN<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>Co<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0 <\/span>P<sub>2<\/sub>O<sub>3<\/sub><br \/>\nk)<span>\u00a0\u00a0 <\/span>CS<sub>2<\/sub><span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>l)<span>\u00a0 <\/span>CdO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>m)<span>\u00a0 <\/span>AsH<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0 <\/span>IF<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>FePO<sub>4<\/sub><br \/>\np)<span>\u00a0 <\/span>H<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<\/span>q)<span>\u00a0 <\/span>TiO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>HClO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>s)<span>\u00a0<\/span>HI<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/p>\n<p class=\"Questions\">4. Determine the formula for the following compounds:<br \/>\na)<span>\u00a0 <\/span>aluminum sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>ammonium iodide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>nickel(II) iodide<br \/>\nd)<span>\u00a0 <\/span>lithium phosphide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0 <\/span>gold(III) phosphide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>phosphoric acid<br \/>\ng)<span>\u00a0 <\/span>lithium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>nickel(II) phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>bromic acid<br \/>\nj)<span>\u00a0 <\/span>xenon dioxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k)<span>\u00a0<\/span>bromine monofluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0 <\/span>aluminum bisulfate<br \/>\nm)<span>\u00a0 <\/span>cobalt(II) carbonate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0<\/span>potassium phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0 <\/span>lithium nitrite<\/p>\n<p class=\"Questions\">5. Determine the formula for the following compounds:<br \/>\na)<span>\u00a0 <\/span>gold(III) chloride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>iron(III) oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0<\/span>chloric acid<br \/>\nd)<span>\u00a0 <\/span>manganese(II) bromide<span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>cobalt(II) hydroxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>arsenic dioxide<br \/>\ng)<span>\u00a0 <\/span>copper(II) hydroxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>sulfurous acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>calcium iodide<br \/>\nj)<span>\u00a0 <\/span>cadmium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k)<span>\u00a0<\/span>nitrogen triiodide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l)<span>\u00a0 <\/span>sulfur monoxide<br \/>\n<span lang=\"IT\">m)<span>\u00a0<\/span>iron(III) chromate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n)<span>\u00a0 <\/span>boron trihydride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o)<span>\u00a0<\/span>manganese(III) oxide<br \/>\n<\/span>p)<span>\u00a0 <\/span>sulfur hexafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>q)<span>\u00a0<\/span>strontium hypochlorite<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r)<span>\u00a0 <\/span>cobalt(II) phosphate<br \/>\ns)<span>\u00a0 <\/span>magnesium bicarbonate<\/p>\n<p class=\"Questions\">6. Write the formula for the following:<br \/>\na)<span>\u00a0 <\/span>chloric acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>xenon hexafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>iron(III) nitrate<br \/>\nd)<span>\u00a0 <\/span>acetic acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>chromium(III) sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>lithium hydrogen carbonate<br \/>\ng)<span>\u00a0 <\/span>aluminum oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h)<span>\u00a0<\/span>hydrofluoric acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i)<span>\u00a0 <\/span>copper(II) permanganate<\/p>\n<p>7.\u00a0Name each molecule:<\/p>\n<p>a) PF<sub class=\"subscript\">3<\/sub> \u00a0 \u00a0 \u00a0 \u00a0 b)\u00a0CO \u00a0 \u00a0 \u00a0 \u00a0 c)\u00a0Se<sub class=\"subscript\">2<\/sub>Br<sub class=\"subscript\">2 \u00a0 \u00a0 \u00a0\u00a0<\/sub>d) SF<sub class=\"subscript\">4<\/sub>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0e)\u00a0P<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">5 \u00a0 \u00a0 \u00a0 \u00a0<\/sub>f)\u00a0N<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g)<span>\u00a0<\/span>PCl<sub>5<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) O<sub>2<\/sub>F<sub>2 \u00a0<\/sub><\/p>\n<p>i) CO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j)<span>\u00a0<\/span>SeF<sub>6<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) NO<\/p>\n<p>8.\u00a0Name the following ionic compounds:<br \/>\na)<span>\u00a0 <\/span>CuSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>FeBr<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0 <\/span>CsClO<sub>4<\/sub><br \/>\nd)<span>\u00a0 <\/span>(NH<sub>4<\/sub>)<sub>2<\/sub>Cr<sub>2<\/sub>O<sub>7<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>e)<span>\u00a0<\/span>KHSO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>CrF<sub>2<\/sub><\/p>\n<p>9.\u00a0Determine the formula for the following ionic compounds:<\/p>\n<p class=\"Indent\">a)<span>\u00a0 <\/span>manganese(IV) oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>magnesium perchlorate<br \/>\nc)<span>\u00a0<\/span>antimony(III) nitrate \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<span><\/span>d)<span>\u00a0 <\/span>sodium iodide<\/p>\n<p>10.\u00a0Determine the formula for the following ionic compounds:<br \/>\na)<span>\u00a0 <\/span>potassium permanganate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0<\/span>iron(II) sulfate<br \/>\nc)<span>\u00a0 <\/span>sodium phosphate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>copper(II) nitride<br \/>\ne)<span>\u00a0 <\/span>aluminum sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f)<span>\u00a0 <\/span>chromium(III) oxide<\/p>\n<p>11.\u00a0Determine the chemical formula for each of the following:<\/p>\n<p class=\"Indent\"><span>\u00a0<\/span>a)<span>\u00a0 <\/span>dinitrogen pentoxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>hydrochloric acid \u00a0 \u00a0 \u00a0 \u00a0 \u00a0c)<span>\u00a0<\/span>hypochlorous acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d)<span>\u00a0 <\/span>nitric acid<\/p>\n<p>12.\u00a0Determine the chemical formulas of the following:<\/p>\n<p class=\"Indent\"><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>a)<span>\u00a0 <\/span>boron trifluoride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>b)<span>\u00a0 <\/span>bromic acid<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c)<span>\u00a0<\/span>sulfurous acid<\/p>\n<h2><\/h2>\n<h2>Answers<\/h2>\n<p class=\"Answers\">1.<span>\u00a0 <\/span>a) calcium acetate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) iron(III) oxide<span>\u00a0 \u00a0 \u00a0 \u00a0\u00a0<\/span>c) disulfur pentafluoride<span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) sulfurous acid<span>\u00a0 <\/span><br \/>\ne) copper(I) nitrate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) lead(II) carbonate<span>\u00a0 \u00a0 \u00a0\u00a0<\/span>g) phosphorous tetrafluoride<span>\u00a0 \u00a0 \u00a0\u00a0<\/span>h) potassium permanganate<span>\u00a0 <\/span><br \/>\ni) diboron trioxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) nitrous acid<\/p>\n<p class=\"Answers\">2.<span>\u00a0 <\/span>a) cobalt(II) chloride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>b) chromium(III) hydroxide \u00a0\u00a0c) iodine monochloride<span>\u00a0 <\/span>d) magnesium phosphide<br \/>\ne) silver nitride<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) ammonium fluoride \u00a0 \u00a0g) barium oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) sodium arsenide<br \/>\ni) zinc bromide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) sulfur hexafluoride \u00a0\u00a0k) barium nitrate<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) nickel(II) perchlorate<br \/>\nm) zinc chlorite<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>n) nitric acid \u00a0 \u00a0o) calcium permanganate \u00a0 \u00a0 \u00a0p) copper(I) hydrogen carbonate<span>\u00a0\u00a0 <\/span><\/p>\n<p class=\"Answers\">q) hydrofluoric acid \u00a0 \u00a0r) ammonium hydrogen sulfate<span>\u00a0\u00a0 <\/span>s) mercury(II) oxide<\/p>\n<p class=\"Answers\">3.<span>\u00a0 <\/span>a) cadmium phosphide<span>\u00a0 <\/span>b) sulphurous acid \u00a0\u00a0c) ammonium sulfide<span>\u00a0\u00a0\u00a0 <\/span>d) manganese(III) fluoride<br \/>\ne) aluminum oxide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) hydrocyanic acid \u00a0 \u00a0g) oxygen difluoride<span>\u00a0\u00a0\u00a0\u00a0 <\/span>h) chromium(III) nitride<br \/>\ni) cobalt(III) sulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) diphosphorous trioxide \u00a0 \u00a0k) carbon disulfide<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) cadmium oxide<br \/>\nm) arsenic trihydride<span>\u00a0\u00a0\u00a0 <\/span>n) iodine trifluoride \u00a0 \u00a0o) iron(III) phosphate<span>\u00a0\u00a0\u00a0 <\/span>p) phosphoric acid<br \/>\nq) titanium(IV) oxide<span>\u00a0\u00a0\u00a0\u00a0 <\/span>r) hypochlorous acid \u00a0 \u00a0s) hydroiodic acid<\/p>\n<p class=\"Answers\"><span lang=\"IT\">4.<span>\u00a0 <\/span>a) Al<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) NH<sub>4<\/sub>I<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) NiI<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) Li<sub>3<\/sub>P \u00a0 \u00a0e) AuP<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) H<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g) Li<sub>2<\/sub>O<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) Ni<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub><br \/>\ni) HBrO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) XeO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) BrF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) Al(HSO<sub>4<\/sub>)<sub>3 \u00a0 \u00a0<\/sub>m) CoCO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span>n) K<sub>3<\/sub>PO<sub>4<\/sub><span>\u00a0\u00a0\u00a0\u00a0 <\/span>o) LiNO<sub>2<\/sub><\/span><\/p>\n<p class=\"Answers\"><span lang=\"IT\">5.<span>\u00a0 <\/span>a) AuCl<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) Fe<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) HClO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>d) MnBr<sub>2 \u00a0 \u00a0 \u00a0<\/sub>e) Co(OH)<sub>2<\/sub><span>\u00a0\u00a0\u00a0 <\/span>f) AsO<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>g) Cu(OH)<sub>2<\/sub><span>\u00a0\u00a0 <\/span>h) H<sub>2<\/sub>SO<sub>3<\/sub><br \/>\ni) CaI<sub>2<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>j) CdO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>k) NI<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>l) SO \u00a0 \u00a0\u00a0m) Fe(CrO<sub>4<\/sub>)<sub>3<\/sub><span>\u00a0 <\/span>n) BH<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>o) Mn<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>p) SF<sub>6<\/sub><br \/>\nq) SrClO<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>r) Co<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub><span>\u00a0 <\/span>s) Mg(HCO<sub>3<\/sub>)<sub>2<\/sub><\/span><\/p>\n<p class=\"Answers\"><span lang=\"PT-BR\">6.<span>\u00a0 <\/span>a) HClO<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>b) XeF<sub>6<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>c) Fe(NO<sub>3<\/sub>)<sub>3 \u00a0\u00a0<\/sub>d) CH<sub>3<\/sub>COOH<span>\u00a0 <\/span>e) Cr<sub>2<\/sub>S<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>f) LiHCO<sub>3<\/sub><br \/>\ng) Al<sub>2<\/sub>O<sub>3<\/sub><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>h) HF<span>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>i) Cu(MnO<sub>4<\/sub>)<sub>2<\/sub><\/span><\/p>\n<p>7. \u00a0a) phosphorus trifluoride \u00a0b) carbon monoxide \u00a0 c) <em class=\"emphasis\">diselenium dibromide<\/em><\/p>\n<p class=\"simpara\">d) sulfur tetrafluoride \u00a0 \u00a0 \u00a0 e)\u00a0diphosphorus pentasulfide \u00a0 \u00a0 \u00a0 \u00a0\u00a0<span lang=\"PT-BR\">f) dinitrogen trioxide \u00a0 \u00a0 \u00a0 \u00a0<\/span><\/p>\n<p class=\"simpara\"><span lang=\"PT-BR\">g) phosphorous pentachloride \u00a0 \u00a0 \u00a0 \u00a0h) dioxin difluoride \u00a0 \u00a0 \u00a0 \u00a0 \u00a0i) carbon dioxide\u00a0<\/span><\/p>\n<p class=\"simpara\"><span lang=\"PT-BR\">j) selenium hexafluoride \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0k) nitrogen monoxide<\/span><\/p>\n<p>8.\u00a0a) copper(II) sulfate \u00a0 \u00a0 \u00a0b) iron(III) bromide \u00a0 \u00a0 \u00a0<span>\u00a0<\/span>c) cesium perchlorate \u00a0 \u00a0 \u00a0<span>\u00a0\u00a0<\/span>d) ammonium dichromate<\/p>\n<p>e) potassium hydrogen sulfate \u00a0 \u00a0 \u00a0<span>\u00a0\u00a0<\/span>f) chromium(II) fluoride<\/p>\n<p>9.\u00a0<span>\u00a0 <\/span>a)<span>\u00a0 <\/span>First, identify the anion and cation and their charges. Manganese is Mn, and we are told from the name (type II) that it has a charge of +4. Oxide is O<sup>2-<\/sup>. \u00a0Now, do the \u201ccross\u201d method of the charges, and reduce: manganese(IV) oxide = MnO<sub>2<\/sub><\/p>\n<p class=\"Indentpoints\">b)<span>\u00a0 <\/span>Magnesium is Mg<sup>2+<\/sup>(type I), and perchlorate is ClO<sub>4<\/sub><sup>&#8211;<\/sup>;<span>\u00a0 <\/span>magnesium perchlorate = Mg(ClO<sub>4<\/sub>)<sub>2<\/sub><\/p>\n<p class=\"Indentpoints\">c)<span>\u00a0 <\/span>Antimony(III) is Sb with a charge of +3, according to the type II name. Nitrate is NO<sub>3<\/sub><sup>&#8211;<\/sup><\/p>\n<p class=\"Indentpoints\"><span>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>antimony(III) nitrate = Sb(NO<sub>3<\/sub>)<sub>3<\/sub><\/p>\n<p class=\"Indentpoints\">d)<span>\u00a0 <\/span>Sodium is Na<sup>+<\/sup>and iodide is I<sup>&#8211;<\/sup><span>\u00a0\u00a0 <\/span>;<span>\u00a0 <\/span>sodium iodide = NaI<\/p>\n<p>10.\u00a0<span lang=\"PT-BR\"><span> <\/span>a) KMnO<sub>4 \u00a0<\/sub><span>\u00a0\u00a0<\/span>b) FeSO<sub>4\u00a0<\/sub><span>\u00a0 \u00a0<\/span>c) Na<sub>3<\/sub>PO<sub>4\u00a0<\/sub>\u00a0 \u00a0\u00a0d) Cu<sub>3<\/sub>N<sub>2 \u00a0<\/sub><span>\u00a0\u00a0<\/span>e) Al<sub>2<\/sub>S<sub>3 \u00a0\u00a0<\/sub><span>\u00a0<\/span>f) Cr<sub>2<\/sub>O<sub>3<\/sub><\/span><\/p>\n<p>11.a)<span>\u00a0 <\/span>Dinitrogen means 2 nitrogen atoms and pentoxide is five oxygen atoms = N<sub>2<\/sub>O<sub>5<\/sub><\/p>\n<p class=\"Indentpoints\">b)<span>\u00a0 <\/span>Hydro means that it must be a general acid. \u201cChlor\u201d is the root for Cl, which has a charge of \u20131. Thus H<sup>+<\/sup>and Cl<sup>&#8211;<\/sup>together make HCl (note that we have to treat this as an ionic compound, the charges must balance).<\/p>\n<p class=\"Indentpoints\">c)<span>\u00a0 <\/span>Be careful!<span>\u00a0 <\/span>Hypo does NOT mean it is a general acid. It is simply the prefix for the polyatomic oxyanion. Because the ending is \u201cous\u201d, we know that the ion ending must be \u201cite\u201d. Thus, this originates from the hypochlorite ion = ClO<sup>&#8211;<\/sup>. Together with H<sup>+<\/sup>this makes HClO.<\/p>\n<p class=\"Indentpoints\">d)<span>\u00a0 <\/span>\u201cNitric\u201d tells us that this originates from the nitrate ion = NO<sub>3<\/sub><sup>&#8211;<\/sup>. With H<sup>+<\/sup>, this makes HNO<sub>3<\/sub><\/p>\n<p>12.\u00a0<span lang=\"PT-BR\"><span><\/span>a) BF<sub>3<\/sub>;<span>\u00a0 <\/span>b) HBrO<sub>3<\/sub>;<span>\u00a0 <\/span>c) H<sub>2<\/sub>SO<sub>3<\/sub><\/span><\/p>\n","protected":false},"author":330,"menu_order":5,"template":"","meta":{"pb_show_title":"on","pb_short_title":"4.4 End of Chapter Problems","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"chapter-type":[],"contributor":[],"license":[54],"class_list":["post-3475","chapter","type-chapter","status-publish","hentry","license-cc-by-nc-sa"],"part":2141,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/3475","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/users\/330"}],"version-history":[{"count":6,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/3475\/revisions"}],"predecessor-version":[{"id":4923,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/3475\/revisions\/4923"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/parts\/2141"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapters\/3475\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/media?parent=3475"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/pressbooks\/v2\/chapter-type?post=3475"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/contributor?post=3475"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/chem1114langaracollege\/wp-json\/wp\/v2\/license?post=3475"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}