{"id":2409,"date":"2019-10-10T14:06:51","date_gmt":"2019-10-10T18:06:51","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/?post_type=back-matter&p=2409"},"modified":"2019-10-11T14:22:01","modified_gmt":"2019-10-11T18:22:01","slug":"answer-key-2-5","status":"publish","type":"back-matter","link":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/back-matter\/answer-key-2-5\/","title":{"raw":"Answer Key 2.5","rendered":"Answer Key 2.5"},"content":{"raw":"[latexpage]\r\n
    \r\n \t
  1. \\(x=\\pm 8\\)<\/li>\r\n \t
  2. \\(n=\\pm 7\\)<\/li>\r\n \t
  3. \\(b=\\pm 1\\)<\/li>\r\n \t
  4. \\(x=\\pm 2\\)<\/li>\r\n \t
  5. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrr}\r\n5&+&8a&=&53 \\\\\r\n-5&&&&-5 \\\\\r\n\\midrule\r\n&&\\dfrac{8a}{8}&=&\\dfrac{48}{8} \\\\ \\\\\r\n&&a&=&6\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrl}\r\n5&+&8a&=&-53 \\\\\r\n-5&&&&-5 \\\\\r\n\\midrule\r\n&&\\dfrac{8a}{8}&=&\\dfrac{-58}{8} \\\\ \\\\\r\n&&a&=&-\\dfrac{58}{8}\\text{ or }-7\\dfrac{1}{4}\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  6. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrl}\r\n9n&+&8&=&46 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{9n}{9}&=&\\dfrac{38}{9} \\\\ \\\\\r\n&&n&=&\\dfrac{38}{9}\\text{ or }4\\dfrac{2}{9}\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n9n&+&8&=&-46 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{9n}{9}&=&\\dfrac{-54}{9} \\\\ \\\\\r\n&&n&=&-6\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  7. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrr}\r\n3k&+&8&=&2 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{3k}{3}&=&\\dfrac{-6}{3} \\\\ \\\\\r\n&&k&=&-2\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n3k&+&8&=&-2 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{3k}{3}&=&\\dfrac{-10}{3} \\\\ \\\\\r\n&&k&=&-\\dfrac{10}{3}\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  8. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\\r\n\\begin{array}{rrrrl}\r\n3&-&x&=&\\phantom{-}6 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&(-x&=&\\phantom{-}3)(-1) \\\\\r\n&&x&=&-3\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrl}\r\n3&-&x&=&-6 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&(-x&=&-9)(-1) \\\\\r\n&&x&=&\\phantom{-}9\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  9. \\(\\begin{array}{rrl}\r\n\\\\ \\\\\r\n\\dfrac{-7}{-7}\\left| -3-3r \\right|&=&\\dfrac{-21}{-7} \\\\\r\n|-3-3r|&=&3\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n-3&-&3r&=&3 \\\\\r\n+3&&&&+3 \\\\\r\n\\midrule\r\n&&\\dfrac{-3r}{-3}&=&\\dfrac{6}{-3} \\\\ \\\\\r\n&&r&=&-2\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n-3&-&3r&=&-3 \\\\\r\n+3&&&&+3 \\\\\r\n\\midrule\r\n&&\\dfrac{-3r}{-3}&=&\\dfrac{0}{-3} \\\\ \\\\\r\n&&r&=&0\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  10. \\(\\begin{array}{rrrrr}\r\n\\\\ \\\\\r\n|2+2b|&+&1&=&3 \\\\\r\n&-&1&&-1 \\\\\r\n\\midrule\r\n|2+2b|&&&=&2\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n2&+&2b&=&2 \\\\\r\n-2&&&&-2 \\\\\r\n\\midrule\r\n&&2b&=&0 \\\\\r\n&&b&=&0\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n2&+&2b&=&-2 \\\\\r\n-2&&&&-2 \\\\\r\n\\midrule\r\n&&\\dfrac{2b}{2}&=&\\dfrac{-4}{2} \\\\ \\\\\r\n&&b&=&-2\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  11. \\(\\begin{array}{rrl}\r\n\\\\ \\\\\r\n\\dfrac{7}{7}|-7x-3|&=&\\dfrac{21}{7} \\\\\r\n|-7x-3|&=&3\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n\\\\ \\\\\r\n-7x&-&3&=&3 \\\\\r\n&+&3&&+3 \\\\\r\n\\midrule\r\n&&\\dfrac{-7x}{-7}&=&\\dfrac{6}{-7} \\\\ \\\\\r\n&&x&=&-\\dfrac{6}{7}\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n-7x&-&3&=&-3 \\\\\r\n&+&3&&+3 \\\\\r\n\\midrule\r\n&&-7x&=&0 \\\\\r\n&&x&=&0\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  12. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrr}\r\n-4&-&3n&=&2 \\\\\r\n+4&&&&+4 \\\\\r\n\\midrule\r\n&&\\dfrac{-3n}{-3}&=&\\dfrac{6}{-3} \\\\ \\\\\r\n&&n&=&-2\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n-4&-&3n&=&-2 \\\\\r\n+4&&&&+4 \\\\\r\n\\midrule\r\n&&\\dfrac{-3n}{-3}&=&\\dfrac{2}{-3} \\\\ \\\\\r\n&&n&=&-\\dfrac{2}{3}\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  13. \\(\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\ \\\\\r\n8|5p &+&8|&-&5&=&11 \\\\\r\n&&&+&5&&+5 \\\\\r\n\\midrule\r\n&&\\dfrac{8}{8}|5p &+&8|&=&\\dfrac{16}{8} \\\\\r\n&&|5p &+&8|&=&2\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n5p&+&8&=&2 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{5p}{5}&=&\\dfrac{-6}{5} \\\\ \\\\\r\n&&p&=&-\\dfrac{6}{5}\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n5p&+&8&=&-2 \\\\\r\n&-&8&&-8 \\\\\r\n\\midrule\r\n&&\\dfrac{5p}{5}&=&\\dfrac{-10}{5} \\\\ \\\\\r\n&&p&=&-2\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  14. \\(\\begin{array}{rrrrrrl}\r\n\\\\ \\\\ \\\\ \\\\\r\n3&-&|6n&+&7|&=&-40 \\\\\r\n-3&&&&&&-3 \\\\\r\n\\midrule\r\n&&(-|6n&+&7|&=&-43)(-1) \\\\\r\n&&|6n&+&7|&=&43\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n6n&+&7&=&43 \\\\\r\n&-&7&&-7 \\\\\r\n\\midrule\r\n&&\\dfrac{6n}{6}&=&\\dfrac{36}{6} \\\\ \\\\\r\n&&n&=&6\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n6n&+&7&=&-43 \\\\\r\n&-&7&&-7 \\\\\r\n\\midrule\r\n&&\\dfrac{6n}{6}&=&\\dfrac{-50}{6} \\\\ \\\\\r\n&&n&=&-\\dfrac{25}{3}\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  15. \\(\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\ \\\\\r\n5|3&+&7m|&+&1&=&51 \\\\\r\n&&&-&1&&-1 \\\\\r\n\\midrule\r\n&&\\dfrac{5}{5}|3&+&7m|&=&\\dfrac{50}{5} \\\\\r\n&&|3&+&7m|&=&10\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n3&+&7m&=&10 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&\\dfrac{7m}{7}&=&\\dfrac{7}{7} \\\\ \\\\\r\n&&m&=&1\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n3&+&7m&=&-10 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&\\dfrac{7m}{7}&=&\\dfrac{-13}{7} \\\\ \\\\\r\n&&m&=&-\\dfrac{13}{7}\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  16. \\(\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\ \\\\\r\n4|r&+&7|&+&3&=&59 \\\\\r\n&&&-&3&&-3 \\\\\r\n\\midrule\r\n&&\\dfrac{4}{4}|r&+&7|&=&\\dfrac{56}{4} \\\\\r\n&&|r&+&7|&=&14\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\nr&+&7&=&14 \\\\\r\n&-&7&&-7 \\\\\r\n\\midrule\r\n&&r&=&7\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\nr&+&7&=&-14 \\\\\r\n&-&7&&-7 \\\\\r\n\\midrule\r\n&&r&=&-21\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  17. \\(\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\ \\\\\r\n-7&+&8|-7x&-&3|&=&73 \\\\\r\n+7&&&&&&+7 \\\\\r\n\\midrule\r\n&&\\dfrac{8}{8}|-7x&-&3|&=&\\dfrac{80}{8} \\\\\r\n&&|-7x&-&3|&=&10\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n-7x&-&3&=&10 \\\\\r\n&+&3&&+3 \\\\\r\n\\midrule\r\n&&\\dfrac{-7x}{-7}&=&\\dfrac{13}{-7} \\\\ \\\\\r\n&&x&=&-\\dfrac{13}{7}\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n-7x&-&3&=&-10 \\\\\r\n&+&3&&+3 \\\\\r\n\\midrule\r\n&&\\dfrac{-7x}{-7}&=&\\dfrac{-7}{-7} \\\\ \\\\\r\n&&x&=&1\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  18. \\(\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\ \\\\\r\n8|3&-&3n|&-&5&=&91 \\\\\r\n&&&+&5&&+5 \\\\\r\n\\midrule\r\n&&\\dfrac{8}{8}|3&-&3n|&=&\\dfrac{96}{8} \\\\\r\n&&|3&-&3n|&=&12\r\n\\end{array}\\)\r\n\\(\\phantom{1}\\)\r\n\\(\\begin{array}{ll}\r\n\\begin{array}{rrrrr}\r\n3&-&3n&=&12 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&\\dfrac{-3n}{-3}&=&\\dfrac{9}{-3} \\\\ \\\\\r\n&&n&=&-3\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrr}\r\n3&-&3n&=&-12 \\\\\r\n-3&&&&-3 \\\\\r\n\\midrule\r\n&&\\dfrac{-3n}{-3}&=&\\dfrac{-15}{-3} \\\\ \\\\\r\n&&n&=&5\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  19. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n5x&+&3&=&2x&-&1 \\\\\r\n-2x&-&3&&-2x&-&3 \\\\\r\n\\midrule\r\n&&\\dfrac{3x}{3}&=&\\dfrac{-4}{3}&& \\\\ \\\\\r\n&&x&=&-\\dfrac{4}{3}&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrrrr}\r\n5x&+&3&=&-2x&+&1 \\\\\r\n+2x&-&3&&+2x&-&3 \\\\\r\n\\midrule\r\n&&\\dfrac{7x}{7}&=&\\dfrac{-2}{7}&& \\\\ \\\\\r\n&&x&=&-\\dfrac{2}{7}&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  20. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n\\\\ \\\\ \\\\\r\n2&+&3x&=&4&-&2x \\\\\r\n-2&+&2x&&-2&+&2x \\\\\r\n\\midrule\r\n&&\\dfrac{5x}{5}&=&\\dfrac{2}{5}&& \\\\ \\\\\r\n&&x&=&\\dfrac{2}{5}&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrrrr}\r\n2&+&3x&=&-4&+&2x \\\\\r\n-2&-&2x&&-2&-&2x \\\\\r\n\\midrule\r\n&&x&=&-6&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  21. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n3x&-&4&=&2x&+&3 \\\\\r\n-2x&+&4&&-2x&+&4 \\\\\r\n\\midrule\r\n&&x&=&7&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrlrr}\r\n\\\\ \\\\ \\\\\r\n3x&-&4&=&-2x&-&3 \\\\\r\n+2x&+&4&&+2x&+&4 \\\\\r\n\\midrule\r\n&&\\dfrac{5x}{5}&=&\\dfrac{1}{5}&& \\\\ \\\\\r\n&&x&=&\\dfrac{1}{5}&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  22. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n2x&-&5&=&3x&+&4 \\\\\r\n-3x&+&5&&-3x&+&5 \\\\\r\n\\midrule\r\n&&-x&=&9&& \\\\\r\n&&x&=&-9&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrlrr}\r\n\\\\ \\\\\r\n2x&-&5&=&-3x&-&4 \\\\\r\n+3x&+&5&&+3x&+&5 \\\\\r\n\\midrule\r\n&&\\dfrac{5x}{5}&=&\\dfrac{1}{5}&& \\\\ \\\\\r\n&&x&=&\\dfrac{1}{5}&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  23. \\(\\begin{array}{ll}\r\n\\\\ \\\\ \\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n4x&-&2&=&6x&+&3 \\\\\r\n-6x&+&2&&-6x&+&2 \\\\\r\n\\midrule\r\n&&\\dfrac{-2x}{-2}&=&\\dfrac{5}{-2}&& \\\\ \\\\\r\n&&x&=&-\\dfrac{5}{2}&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrrrr}\r\n4x&-&2&=&-6x&-&3 \\\\\r\n+6x&+&2&&+6x&+&2 \\\\\r\n\\midrule\r\n&&\\dfrac{10x}{10}&=&\\dfrac{-1}{10}&& \\\\ \\\\\r\n&&x&=&-\\dfrac{1}{10}&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n \t
  24. \\(\\begin{array}{ll}\r\n\\\\ \\\\\r\n\\begin{array}{rrrrrrr}\r\n3x&+&2&=&2x&-&3 \\\\\r\n-2x&-&2&&-2x&-&2 \\\\\r\n\\midrule\r\n&&x&=&-5&&\r\n\\end{array}\r\n& \\hspace{0.5in}\r\n\\begin{array}{rrrrlrr}\r\n\\\\ \\\\ \\\\\r\n3x&+&2&=&-2x&+&3 \\\\\r\n+2x&-&2&&+2x&-&2 \\\\\r\n\\midrule\r\n&&\\dfrac{5x}{5}&=&\\dfrac{1}{5}&& \\\\ \\\\\r\n&&x&=&\\dfrac{1}{5}&&\r\n\\end{array}\r\n\\end{array}\\)<\/li>\r\n<\/ol>","rendered":"
      \n
    1. \"x=\pm 8\"<\/li>\n
    2. \"n=\pm 7\"<\/li>\n
    3. \"b=\pm 1\"<\/li>\n
    4. \"x=\pm 2\"<\/li>\n
    5. \"\begin{array}{ll}<\/li>\n
    6. \"\begin{array}{ll}<\/li>\n
    7. \"\begin{array}{ll}<\/li>\n
    8. \"\begin{array}{ll}<\/li>\n
    9. \"\begin{array}{rrl}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    10. \"\begin{array}{rrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    11. \"\begin{array}{rrl}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    12. \"\begin{array}{ll}<\/li>\n
    13. \"\begin{array}{rrrrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    14. \"\begin{array}{rrrrrrl}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    15. \"\begin{array}{rrrrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    16. \"\begin{array}{rrrrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    17. \"\begin{array}{rrrrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    18. \"\begin{array}{rrrrrrr}
      \n\"\phantom{1}\"
      \n\"\begin{array}{ll}<\/li>\n
    19. \"\begin{array}{ll}<\/li>\n
    20. \"\begin{array}{ll}<\/li>\n
    21. \"\begin{array}{ll}<\/li>\n
    22. \"\begin{array}{ll}<\/li>\n
    23. \"\begin{array}{ll}<\/li>\n
    24. \"\begin{array}{ll}<\/li>\n<\/ol>\n","protected":false},"author":727,"menu_order":14,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"back-matter-type":[],"contributor":[],"license":[],"class_list":["post-2409","back-matter","type-back-matter","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2409","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/users\/727"}],"version-history":[{"count":4,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2409\/revisions"}],"predecessor-version":[{"id":2413,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2409\/revisions\/2413"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2409\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/media?parent=2409"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter-type?post=2409"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/contributor?post=2409"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/license?post=2409"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}