{"id":2417,"date":"2019-10-15T13:01:55","date_gmt":"2019-10-15T17:01:55","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/?post_type=back-matter&p=2417"},"modified":"2019-10-15T14:03:42","modified_gmt":"2019-10-15T18:03:42","slug":"answer-key-2-6","status":"publish","type":"back-matter","link":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/back-matter\/answer-key-2-6\/","title":{"raw":"Answer Key 2.6","rendered":"Answer Key 2.6"},"content":{"raw":"[latexpage]\r\n
    \r\n \t
  1. (3) + 1 + (4) \u2212 (1)\r\n3 + 1 + 4 \u2212 1\r\n7<\/li>\r\n \t
  2. (5)2<\/sup> + (5) \u2212 (1)\r\n25 + 5 \u2212 1\r\n29<\/li>\r\n \t
  3. (6) \u2212 [(6)(5)\u00a0\u00f7 6]\r\n6 \u2212 [30 \u00f7 6]\r\n6 \u2212 5\r\n1<\/li>\r\n \t
  4. [6 + (4) \u2212 (1)] \u00f7 3\r\n[6 + 4 \u2212 1] \u00f7 3\r\n9 \u00f7 3\r\n3<\/li>\r\n \t
  5. (5)2<\/sup> \u2212 ((3) \u2212 1)\r\n25 \u2212 (3 \u2212 1)\r\n25 \u2212 2\r\n23<\/li>\r\n \t
  6. (6) + 6(4) \u2212 4(4)\r\n6 + 24 \u2212 16\r\n14<\/li>\r\n \t
  7. 5(4) + (2)(5) \u00f7 2\r\n20 + 10 \u00f7 2\r\n20 + 5\r\n25<\/li>\r\n \t
  8. 5((6) + (2)) + 1 + (5)\r\n5(6 + 2) + 1 + 5\r\n5(8) + 6\r\n40 + 6\r\n46<\/li>\r\n \t
  9. [4 \u2212 ((6) \u2212 (4))] \u00f7 2 + (6)\r\n[4 \u2212 (6\u00a0\u2212 4)] \u00f7 2 + 6\r\n[4 \u2212 2] \u00f7 2 + 6\r\n2 \u00f7 2 + 6\r\n1 + 6\r\n7<\/li>\r\n \t
  10. (4) + (5) \u2212 1\r\n4 + 5 \u2212 1\r\n8<\/li>\r\n \t
  11. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\\r\n\\dfrac{ab}{a}&=&\\dfrac{c}{a} \\\\ \\\\\r\nb&=&\\dfrac{c}{a}\r\n\\end{array}\\)<\/li>\r\n \t
  12. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(g=\\dfrac{h}{i}\\right)(i) \\\\ \\\\\r\nh=gi\r\n\\end{array}\\)<\/li>\r\n \t
  13. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\ \\\\\r\n\\left(\\left(\\dfrac{f}{g}\\right)x=b\\right)\\dfrac{g}{f} \\\\ \\\\\r\nx=\\dfrac{bg}{f}\r\n\\end{array}\\)<\/li>\r\n \t
  14. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(p=\\dfrac{3y}{q}\\right)\\left(\\dfrac{q}{3}\\right) \\\\ \\\\\r\ny=\\dfrac{pq}{3}\r\n\\end{array}\\)<\/li>\r\n \t
  15. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(3x=\\dfrac{a}{b}\\right)\\left(\\dfrac{1}{3}\\right) \\\\ \\\\\r\nx=\\dfrac{a}{3b}\r\n\\end{array}\\)<\/li>\r\n \t
  16. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(\\dfrac{ym}{b}=\\dfrac{c}{d}\\right)\\left(\\dfrac{b}{m}\\right) \\\\ \\\\\r\ny=\\dfrac{bc}{dm}\r\n\\end{array}\\)<\/li>\r\n \t
  17. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(V=\\dfrac{4}{3}\\pi r^3\\right)\\left(\\dfrac{3}{4r^3}\\right) \\\\ \\\\\r\n\\pi=\\dfrac{3V}{4r^3}\r\n\\end{array}\\)<\/li>\r\n \t
  18. \\(\\begin{array}{l}\r\n\\\\ \\\\\r\n\\left(E=mv^2\\right)\\left(\\dfrac{1}{v^2}\\right) \\\\ \\\\\r\nm=\\dfrac{E}{v^2}\r\n\\end{array}\\)<\/li>\r\n \t
  19. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(c=\\dfrac{4y}{m+n}\\right)\\left(\\dfrac{m+n}{4}\\right) \\\\ \\\\\r\ny=\\dfrac{c(m+n)}{4}\r\n\\end{array}\\)<\/li>\r\n \t
  20. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(\\dfrac{rs}{a-3}=k\\right)\\left(\\dfrac{a-3}{s}\\right) \\\\ \\\\\r\nr=\\dfrac{k(a-3)}{s}\r\n\\end{array}\\)<\/li>\r\n \t
  21. \\(\\begin{array}{l}\r\n\\\\ \\\\ \\\\\r\n\\left(V=\\dfrac{\\pi Dn}{12}\\right)\\left(\\dfrac{12}{\\pi n}\\right) \\\\ \\\\\r\nD=\\dfrac{12V}{\\pi n}\r\n\\end{array}\\)<\/li>\r\n \t
  22. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\nF\\phantom{+kL}&=&kR-kL \\\\\r\n+kL&&\\phantom{kR}+kL \\\\\r\n\\midrule\r\n\\dfrac{F+kL}{k}&=&\\dfrac{kR}{k} \\\\ \\\\\r\nR&=&\\dfrac{F+kL}{k}\r\n\\end{array}\\)<\/li>\r\n \t
  23. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\nP\\phantom{-np}&=&\\phantom{-}np-nc \\\\\r\n-np&&-np \\\\\r\n\\midrule\r\n\\dfrac{P-np}{-n}&=&\\dfrac{-nc}{-n} \\\\ \\\\\r\nc&=&\\dfrac{P-np}{-n}\r\n\\end{array}\\)<\/li>\r\n \t
  24. \\(\\begin{array}{rrrrr}\r\n\\\\ \\\\ \\\\\r\nS\\phantom{-2B}&=&L&+&2B \\\\\r\n-2B&&&-&2B \\\\\r\n\\midrule\r\nL&=&S&-&2B\r\n\\end{array}\\)<\/li>\r\n \t
  25. \\(\\phantom{1}\\)\r\n\\(\\left(T=\\dfrac{D-d}{L}\\right)(L) \\\\ \\)\r\n\\(\\begin{array}{rrrrr}\r\nTL\\phantom{+d}&=&D&-&d \\\\\r\n+d&&&+&d \\\\\r\n\\midrule\r\nD&=&TL&+&d\r\n\\end{array}\\)<\/li>\r\n \t
  26. \\(\\phantom{1}\\)\r\n\\(\\left(I=\\dfrac{E_a-E_q}{R}\\right)(R) \\\\ \\)\r\n\\(\\begin{array}{rrrrr}\r\nIR&=&E_a&-&E_q \\\\\r\n+E_q&&&+&E_q \\\\\r\n\\midrule\r\nE_a&=&IR&+&E_q\r\n\\end{array}\\)<\/li>\r\n \t
  27. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\\r\n\\dfrac{L}{1+at}&=&\\dfrac{L_o(1+at)}{1+at} \\\\ \\\\\r\nL_o&=&\\dfrac{L}{1+at}\r\n\\end{array}\\)<\/li>\r\n \t
  28. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\n2m+p&=&\\phantom{-}4m+q \\\\\r\n-2m-q&&-2m-q \\\\\r\n\\midrule\r\n\\dfrac{p-q}{2}&=&\\dfrac{2m}{2} \\\\ \\\\\r\nm&=&\\dfrac{p-q}{2}\r\n\\end{array}\\)<\/li>\r\n \t
  29. \\(\\phantom{1}\\)\r\n\\(\\left(\\dfrac{k-m}{r}=q\\right)(r) \\\\ \\)\r\n\\(\\begin{array}{rrl}\r\nk-m&=&qr \\\\\r\n+m&&\\phantom{qr}+m \\\\\r\n\\midrule\r\nk&=&qr+m\r\n\\end{array}\\)<\/li>\r\n \t
  30. \\(\\begin{array}{rrrrr}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\nR\\phantom{-b}&=&aT&+&b \\\\\r\n-b&&&-&b \\\\\r\n\\midrule\r\n\\dfrac{R-b}{a}&=&\\dfrac{aT}{a}&& \\\\ \\\\\r\nT&=&\\dfrac{R-b}{a}&&\r\n\\end{array}\\)<\/li>\r\n \t
  31. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\nQ_1\\phantom{+PQ_1}&=&PQ_2-PQ_1 \\\\\r\n+PQ_1&&\\phantom{PQ_2}+PQ_1 \\\\\r\n\\midrule\r\n\\dfrac{Q_1+PQ_1}{P}&=&\\dfrac{PQ_2}{P} \\\\ \\\\\r\nQ_2&=&\\dfrac{Q_1+PQ_1}{P}\r\n\\end{array}\\)<\/li>\r\n \t
  32. \\(\\begin{array}{rrl}\r\n\\\\ \\\\ \\\\ \\\\ \\\\ \\\\\r\nL\\phantom{-\\pi r_2-2d}&=&\\pi r_1+\\pi r_2+2d \\\\\r\n-\\pi r_2-2d&&\\phantom{\\pi r_1}-\\pi r_2-2d \\\\\r\n\\midrule\r\n\\dfrac{L-\\pi r_2-2d}{\\pi}&=&\\dfrac{\\pi r_1}{\\pi} \\\\ \\\\\r\nr_1&=&\\dfrac{L-\\pi r_2-2d}{\\pi}\r\n\\end{array}\\)<\/li>\r\n \t
  33. \\(\\phantom{1}\\)\r\n\\(\\left(R=\\dfrac{kA(T+T_1)}{d}\\right)\\left(\\dfrac{d}{kA}\\right) \\\\ \\)\r\n\\(\\begin{array}{rrl}\r\n\\dfrac{Rd}{kA}\\phantom{-T}&=&\\phantom{-}T+T_1 \\\\\r\n-T&&-T \\\\\r\n\\midrule\r\nT_1&=&\\dfrac{Rd}{kA}-T\r\n\\end{array}\\)<\/li>\r\n \t
  34. \\(\\phantom{1}\\)\r\n\\(\\left(P=\\dfrac{V_1(V_2-V_1)}{g}\\right)\\left(\\dfrac{g}{V_1}\\right) \\\\ \\)\r\n\\(\\begin{array}{rrl}\r\n\\dfrac{Pg}{V_1}\\phantom{+V_1}&=&V_2-V_1 \\\\\r\n+V_1&&\\phantom{V_2}+V_1 \\\\\r\n\\midrule\r\nV_2&=&\\dfrac{Pg}{V_1}+V_1\r\n\\end{array}\\)<\/li>\r\n<\/ol>","rendered":"
      \n
    1. (3) + 1 + (4) \u2212 (1)
      \n3 + 1 + 4 \u2212 1
      \n7<\/li>\n
    2. (5)2<\/sup> + (5) \u2212 (1)
      \n25 + 5 \u2212 1
      \n29<\/li>\n
    3. (6) \u2212 [(6)(5)\u00a0\u00f7 6]
      \n6 \u2212 [30 \u00f7 6]
      \n6 \u2212 5
      \n1<\/li>\n
    4. [6 + (4) \u2212 (1)] \u00f7 3
      \n[6 + 4 \u2212 1] \u00f7 3
      \n9 \u00f7 3
      \n3<\/li>\n
    5. (5)2<\/sup> \u2212 ((3) \u2212 1)
      \n25 \u2212 (3 \u2212 1)
      \n25 \u2212 2
      \n23<\/li>\n
    6. (6) + 6(4) \u2212 4(4)
      \n6 + 24 \u2212 16
      \n14<\/li>\n
    7. 5(4) + (2)(5) \u00f7 2
      \n20 + 10 \u00f7 2
      \n20 + 5
      \n25<\/li>\n
    8. 5((6) + (2)) + 1 + (5)
      \n5(6 + 2) + 1 + 5
      \n5(8) + 6
      \n40 + 6
      \n46<\/li>\n
    9. [4 \u2212 ((6) \u2212 (4))] \u00f7 2 + (6)
      \n[4 \u2212 (6\u00a0\u2212 4)] \u00f7 2 + 6
      \n[4 \u2212 2] \u00f7 2 + 6
      \n2 \u00f7 2 + 6
      \n1 + 6
      \n7<\/li>\n
    10. (4) + (5) \u2212 1
      \n4 + 5 \u2212 1
      \n8<\/li>\n
    11. \"\begin{array}{rrl}<\/li>\n
    12. \"\begin{array}{l}<\/li>\n
    13. \"\begin{array}{l}<\/li>\n
    14. \"\begin{array}{l}<\/li>\n
    15. \"\begin{array}{l}<\/li>\n
    16. \"\begin{array}{l}<\/li>\n
    17. \"\begin{array}{l}<\/li>\n
    18. \"\begin{array}{l}<\/li>\n
    19. \"\begin{array}{l}<\/li>\n
    20. \"\begin{array}{l}<\/li>\n
    21. \"\begin{array}{l}<\/li>\n
    22. \"\begin{array}{rrl}<\/li>\n
    23. \"\begin{array}{rrl}<\/li>\n
    24. \"\begin{array}{rrrrr}<\/li>\n
    25. \"\phantom{1}\"
      \n\"\left(T=\dfrac{D-d}{L}\right)(L) \\\"
      \n\"\begin{array}{rrrrr}<\/li>\n
    26. \"\phantom{1}\"
      \n\"\left(I=\dfrac{E_a-E_q}{R}\right)(R) \\\"
      \n\"\begin{array}{rrrrr}<\/li>\n
    27. \"\begin{array}{rrl}<\/li>\n
    28. \"\begin{array}{rrl}<\/li>\n
    29. \"\phantom{1}\"
      \n\"\left(\dfrac{k-m}{r}=q\right)(r) \\\"
      \n\"\begin{array}{rrl}<\/li>\n
    30. \"\begin{array}{rrrrr}<\/li>\n
    31. \"\begin{array}{rrl}<\/li>\n
    32. \"\begin{array}{rrl}<\/li>\n
    33. \"\phantom{1}\"
      \n\"\left(R=\dfrac{kA(T+T_1)}{d}\right)\left(\dfrac{d}{kA}\right) \\\"
      \n\"\begin{array}{rrl}<\/li>\n
    34. \"\phantom{1}\"
      \n\"\left(P=\dfrac{V_1(V_2-V_1)}{g}\right)\left(\dfrac{g}{V_1}\right) \\\"
      \n\"\begin{array}{rrl}<\/li>\n<\/ol>\n","protected":false},"author":727,"menu_order":15,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"back-matter-type":[],"contributor":[],"license":[],"class_list":["post-2417","back-matter","type-back-matter","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2417","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/users\/727"}],"version-history":[{"count":3,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2417\/revisions"}],"predecessor-version":[{"id":2420,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2417\/revisions\/2420"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter\/2417\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/media?parent=2417"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/back-matter-type?post=2417"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/contributor?post=2417"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/license?post=2417"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}