{"id":691,"date":"2019-04-29T16:39:22","date_gmt":"2019-04-29T20:39:22","guid":{"rendered":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/?post_type=chapter&p=691"},"modified":"2019-12-05T13:24:53","modified_gmt":"2019-12-05T18:24:53","slug":"9-7-rational-exponents-increased-difficulty","status":"publish","type":"chapter","link":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/chapter\/9-7-rational-exponents-increased-difficulty\/","title":{"raw":"9.7 Rational Exponents (Increased Difficulty)","rendered":"9.7 Rational Exponents (Increased Difficulty)"},"content":{"raw":"[latexpage]\r\n\r\nSimplifying rational exponents equations that are more difficult generally involves two steps. First, reduce inside the brackets. Second, multiplu the power outside the brackets for all terms inside.\r\n
\r\n

Example 9.7.1<\/p>\r\n\r\n<\/header>\r\n

\r\n\r\nSimplify the following rational exponent expression:\r\n

\\(\\left(\\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\\right)^2\\)<\/p>\r\nFirst, simplifying inside the brackets gives:\r\n

\\(x^{-2--2}y^{-3-4}\\)<\/p>\r\nOr:\r\n

\\(x^0y^{-7}\\)<\/p>\r\nWhich simplifies to:\r\n

\\(y^{-7}\\)<\/p>\r\nSecond, taking the exponent 2 outside the brackets and applying it to the reduced expression gives:\r\n

\\(y^{-7\\cdot 2} \\text{ or }y^{-14}\\)<\/p>\r\nTherefore:\r\n

\\(\\left(\\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\\right)^2=y^{-14}\\)<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

\r\n

Example 9.7.2<\/p>\r\n\r\n<\/header>\r\n

\r\n\r\nSimplify the following rational exponent expression:\r\n

\\(\\left(\\dfrac{x^{-4}y^{-6}}{x^{-5}y^{10}}\\right)^{-3}\\)<\/p>\r\nFirst, simplifying inside the brackets gives:\r\n

\\(x^{-4--5}y^{-6-10}\\)<\/p>\r\nOr:\r\n

\\(x^1y^{-16}\\)<\/p>\r\nWhich simplifies to:\r\n

\\(xy^{-16}\\)<\/p>\r\n

Second, taking the exponent \u22123 outside the brackets and applying it to the reduced expression gives:<\/p>\r\n

\\((xy^{-16})^{-3}\\text{ or }x^{-3}y^{48}\\)<\/p>\r\nTherefore:\r\n

\\(\\left(\\dfrac{x^{-4}y^{-6}}{x^{-5}y^{10}}\\right)^{-3}=x^{-3}y^{48}=\\dfrac{y^{48}}{x^3}\\)<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

\r\n

Example 9.7.3<\/p>\r\n\r\n<\/header>\r\n

\r\n\r\nSimplify the following rational exponent expression:\r\n

\\(\\left(\\dfrac{a^0b^3}{c^6d^{-12}}\\right)^{\\frac{1}{3}}\\)<\/p>\r\n

First, simplifying inside the brackets gives:<\/p>\r\n

\\(\\dfrac{b^3}{c^6d^{-12}}\\)<\/p>\r\nSecond, taking the exponent \\(\\frac{1}{3}\\) outside the brackets and applying it to the reduced expression gives:\r\n

\\(\\dfrac{b^{3\\cdot \\frac{1}{3}}}{c^{6\\cdot \\frac{1}{3}}d^{-12\\cdot \\frac{1}{3}}}\\)<\/p>\r\nOr:\r\n

\\(\\dfrac{b}{c^2d^{-4}}\\)<\/p>\r\nWhich simplifies to:\r\n

\\(\\dfrac{bd^4}{c^2}\\)<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

Questions<\/h1>\r\nSimplify the following rational exponents.\r\n
    \r\n \t
  1. \\(\\left(\\dfrac{x^{-2}y^{-6}}{x^{-2}y^4}\\right)^2\\)<\/li>\r\n \t
  2. \\(\\left(\\dfrac{x^{-3}y^{-3}}{x^{-1}y^6}\\right)^3\\)<\/li>\r\n \t
  3. \\(\\left(\\dfrac{x^{-2}y^{-4}}{x^2y^{-4}}\\right)^2\\)<\/li>\r\n \t
  4. \\(\\left(\\dfrac{x^{-5}y^{-3}}{x^{-4}y^2}\\right)^4\\)<\/li>\r\n \t
  5. \\(\\left(\\dfrac{x^{-2}y^{-2}}{x^{-3}y^3}\\right)^8\\)<\/li>\r\n \t
  6. \\(\\left(\\dfrac{x^{-4}y^{-3}}{x^{-3}y^2}\\right)^5\\)<\/li>\r\n \t
  7. \\(\\left(\\dfrac{x^{-2}y^{-4}}{x^{-2}y^4}\\right)^{-2}\\)<\/li>\r\n \t
  8. \\(\\left(\\dfrac{x^{-2}y^{-3}}{x^{-5}y^3}\\right)^{-3}\\)<\/li>\r\n \t
  9. \\(\\left(\\dfrac{x^{-2}y^{-3}}{x^{-2}y^{-3}}\\right)^{-1}\\)<\/li>\r\n \t
  10. \\(\\left(\\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\\right)^{-2}\\)<\/li>\r\n \t
  11. \\(\\left(\\dfrac{x^0y^{-3}}{x^{-2}y^0}\\right)^{-5}\\)<\/li>\r\n \t
  12. \\(\\left(\\dfrac{x^{-22}y^{-36}}{x^{-24}y^{12}}\\right)^0\\)<\/li>\r\n \t
  13. \\(\\left(\\dfrac{a^0b^3}{a^6b^{-12}}\\right)^{-\\frac{1}{3}}\\)<\/li>\r\n \t
  14. \\(\\left(\\dfrac{a^{12}b^4}{a^8c^{-12}}\\right)^{\\frac{1}{4}}\\)<\/li>\r\n \t
  15. \\(\\left(\\dfrac{a^5c^{10}}{b^5d^{-15}}\\right)^{\\frac{2}{5}}\\)<\/li>\r\n \t
  16. \\(\\left(\\dfrac{a^2b^8}{a^6b^{-12}}\\right)^{-\\frac{3}{4}}\\)<\/li>\r\n \t
  17. \\(\\left(\\dfrac{a^0b^3}{c^6d^{-12}}\\right)^{\\frac{0}{3}}\\)<\/li>\r\n \t
  18. \\(\\left(\\dfrac{a^0b^3}{c^6d^{-12}}\\right)^{\\frac{1}{10}}\\)<\/li>\r\n<\/ol>\r\nAnswer Key 9.7<\/a>","rendered":"

    Simplifying rational exponents equations that are more difficult generally involves two steps. First, reduce inside the brackets. Second, multiplu the power outside the brackets for all terms inside.<\/p>\n

    \n
    \n

    Example 9.7.1<\/p>\n<\/header>\n

    \n

    Simplify the following rational exponent expression:<\/p>\n

    \"\left(\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\right)^2\"<\/p>\n

    First, simplifying inside the brackets gives:<\/p>\n

    \"x^{-2--2}y^{-3-4}\"<\/p>\n

    Or:<\/p>\n

    \"x^0y^{-7}\"<\/p>\n

    Which simplifies to:<\/p>\n

    \"y^{-7}\"<\/p>\n

    Second, taking the exponent 2 outside the brackets and applying it to the reduced expression gives:<\/p>\n

    \"y^{-7\cdot 2} \text{ or }y^{-14}\"<\/p>\n

    Therefore:<\/p>\n

    \"\left(\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\right)^2=y^{-14}\"<\/p>\n<\/div>\n<\/div>\n

    \n
    \n

    Example 9.7.2<\/p>\n<\/header>\n

    \n

    Simplify the following rational exponent expression:<\/p>\n

    \"\left(\dfrac{x^{-4}y^{-6}}{x^{-5}y^{10}}\right)^{-3}\"<\/p>\n

    First, simplifying inside the brackets gives:<\/p>\n

    \"x^{-4--5}y^{-6-10}\"<\/p>\n

    Or:<\/p>\n

    \"x^1y^{-16}\"<\/p>\n

    Which simplifies to:<\/p>\n

    \"xy^{-16}\"<\/p>\n

    Second, taking the exponent \u22123 outside the brackets and applying it to the reduced expression gives:<\/p>\n

    \"(xy^{-16})^{-3}\text{ or }x^{-3}y^{48}\"<\/p>\n

    Therefore:<\/p>\n

    \"\left(\dfrac{x^{-4}y^{-6}}{x^{-5}y^{10}}\right)^{-3}=x^{-3}y^{48}=\dfrac{y^{48}}{x^3}\"<\/p>\n<\/div>\n<\/div>\n

    \n
    \n

    Example 9.7.3<\/p>\n<\/header>\n

    \n

    Simplify the following rational exponent expression:<\/p>\n

    \"\left(\dfrac{a^0b^3}{c^6d^{-12}}\right)^{\frac{1}{3}}\"<\/p>\n

    First, simplifying inside the brackets gives:<\/p>\n

    \"\dfrac{b^3}{c^6d^{-12}}\"<\/p>\n

    Second, taking the exponent \"\frac{1}{3}\" outside the brackets and applying it to the reduced expression gives:<\/p>\n

    \"\dfrac{b^{3\cdot \frac{1}{3}}}{c^{6\cdot \frac{1}{3}}d^{-12\cdot \frac{1}{3}}}\"<\/p>\n

    Or:<\/p>\n

    \"\dfrac{b}{c^2d^{-4}}\"<\/p>\n

    Which simplifies to:<\/p>\n

    \"\dfrac{bd^4}{c^2}\"<\/p>\n<\/div>\n<\/div>\n

    Questions<\/h1>\n

    Simplify the following rational exponents.<\/p>\n

      \n
    1. \"\left(\dfrac{x^{-2}y^{-6}}{x^{-2}y^4}\right)^2\"<\/li>\n
    2. \"\left(\dfrac{x^{-3}y^{-3}}{x^{-1}y^6}\right)^3\"<\/li>\n
    3. \"\left(\dfrac{x^{-2}y^{-4}}{x^2y^{-4}}\right)^2\"<\/li>\n
    4. \"\left(\dfrac{x^{-5}y^{-3}}{x^{-4}y^2}\right)^4\"<\/li>\n
    5. \"\left(\dfrac{x^{-2}y^{-2}}{x^{-3}y^3}\right)^8\"<\/li>\n
    6. \"\left(\dfrac{x^{-4}y^{-3}}{x^{-3}y^2}\right)^5\"<\/li>\n
    7. \"\left(\dfrac{x^{-2}y^{-4}}{x^{-2}y^4}\right)^{-2}\"<\/li>\n
    8. \"\left(\dfrac{x^{-2}y^{-3}}{x^{-5}y^3}\right)^{-3}\"<\/li>\n
    9. \"\left(\dfrac{x^{-2}y^{-3}}{x^{-2}y^{-3}}\right)^{-1}\"<\/li>\n
    10. \"\left(\dfrac{x^{-2}y^{-3}}{x^{-2}y^4}\right)^{-2}\"<\/li>\n
    11. \"\left(\dfrac{x^0y^{-3}}{x^{-2}y^0}\right)^{-5}\"<\/li>\n
    12. \"\left(\dfrac{x^{-22}y^{-36}}{x^{-24}y^{12}}\right)^0\"<\/li>\n
    13. \"\left(\dfrac{a^0b^3}{a^6b^{-12}}\right)^{-\frac{1}{3}}\"<\/li>\n
    14. \"\left(\dfrac{a^{12}b^4}{a^8c^{-12}}\right)^{\frac{1}{4}}\"<\/li>\n
    15. \"\left(\dfrac{a^5c^{10}}{b^5d^{-15}}\right)^{\frac{2}{5}}\"<\/li>\n
    16. \"\left(\dfrac{a^2b^8}{a^6b^{-12}}\right)^{-\frac{3}{4}}\"<\/li>\n
    17. \"\left(\dfrac{a^0b^3}{c^6d^{-12}}\right)^{\frac{0}{3}}\"<\/li>\n
    18. \"\left(\dfrac{a^0b^3}{c^6d^{-12}}\right)^{\frac{1}{10}}\"<\/li>\n<\/ol>\n

      Answer Key 9.7<\/a><\/p>\n","protected":false},"author":540,"menu_order":24,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-691","chapter","type-chapter","status-publish","hentry"],"part":389,"_links":{"self":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapters\/691","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/users\/540"}],"version-history":[{"count":7,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapters\/691\/revisions"}],"predecessor-version":[{"id":3643,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapters\/691\/revisions\/3643"}],"part":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/parts\/389"}],"metadata":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapters\/691\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/media?parent=691"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/pressbooks\/v2\/chapter-type?post=691"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/contributor?post=691"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.bccampus.ca\/intermediatealgebrakpu\/wp-json\/wp\/v2\/license?post=691"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}