9 2.3 Time, Velocity, and Speed
There is more to motion than distance and displacement. Questions such as, “How long does a foot race take?” and “What was the runner’s speed?” cannot be answered without an understanding of other concepts. In this section we add definitions of time, velocity, and speed to expand our description of motion.
Time
As discussed earlier, the most fundamental physical quantities are defined by how they are measured. This is the case with time. Every measurement of time involves measuring a change in some physical quantity. It may be a number on a digital clock, a heartbeat, or the position of the Sun in the sky. In physics, the definition of time is simple—time is change, or the interval over which change occurs. It is impossible to know that time has passed unless something changes.
The amount of time or change is calibrated by comparison with a standard. The SI unit for time is the second, abbreviated s. We might, for example, observe that a certain pendulum makes one full swing every 0.75 s. We could then use the pendulum to measure time by counting its swings or, of course, by connecting the pendulum to a clock mechanism that registers time on a dial. This allows us to not only measure the amount of time, but also to determine a sequence of events.
How does time relate to motion? We are usually interested in elapsed time for a particular motion, such as how long it takes an airplane passenger to get from his seat to the back of the plane. To find elapsed time, we note the time at the beginning and end of the motion and subtract the two. For example, a lecture may start at 11:00 A.M. and end at 11:50 A.M., so that the elapsed time would be 50 min. Elapsed time Δt is the difference between the ending time and beginning time,
where Δt is the change in time or elapsed time, tf is the time at the end of the motion, and t0 is the time at the beginning of the motion. (As usual, the delta symbol, Δ, means the change in the quantity that follows it.)
Life is simpler if the beginning time t0 is taken to be zero, as when we use a stopwatch. If we were using a stopwatch, it would simply read zero at the start of the lecture and 50 min at the end. If t0=0, then Δt = tf ≡ t.
In this text, for simplicity’s sake,
- motion starts at time equal to zero t0=0
- the symbol t is used for elapsed time unless otherwise specified ( Δt = tf ≡ t )
Velocity
Your notion of velocity is probably the same as its scientific definition. You know that if you have a large displacement in a small amount of time you have a large velocity, and that velocity has units of distance divided by time, such as miles per hour or kilometers per hour.
AVERAGE VELOCITY
Average velocity is displacement (change in position) divided by the time of travel,
where [latex]\boldsymbol{\bar{v}}[/latex] is the average (indicated by the bar over the v) velocity, Δx is the change in position (or displacement), and xf and x0 are the final and beginning positions at times tf and t0, respectively. If the starting time t0 is taken to be zero, then the average velocity is simply
Notice that this definition indicates that velocity is a vector because displacement is a vector. It has both magnitude and direction. The SI unit for velocity is meters per second or m/s, but many other units, such as km/h, mi/h (also written as mph), and cm/s, are in common use. Suppose, for example, an airplane passenger took 5 seconds to move −4 m (the negative sign indicates that displacement is toward the back of the plane). His average velocity would be
The minus sign indicates the average velocity is also toward the rear of the plane.
The average velocity of an object does not tell us anything about what happens to it between the starting point and ending point, however. For example, we cannot tell from average velocity whether the airplane passenger stops momentarily or backs up before he goes to the back of the plane. To get more details, we must consider smaller segments of the trip over smaller time intervals.
The smaller the time intervals considered in a motion, the more detailed the information. When we carry this process to its logical conclusion, we are left with an infinitesimally small interval. Over such an interval, the average velocity becomes the instantaneous velocity or the velocity at a specific instant. A car’s speedometer, for example, shows the magnitude (but not the direction) of the instantaneous velocity of the car. (Police give tickets based on instantaneous velocity, but when calculating how long it will take to get from one place to another on a road trip, you need to use average velocity.) Instantaneous velocity v is the average velocity at a specific instant in time (or over an infinitesimally small time interval).
Mathematically, finding instantaneous velocity, v, at a precise instant t can involve taking a limit, a calculus operation beyond the scope of this text. However, under many circumstances, we can find precise values for instantaneous velocity without calculus.
Speed
In everyday language, most people use the terms “speed” and “velocity” interchangeably. In physics, however, they do not have the same meaning and they are distinct concepts. One major difference is that speed has no direction. Thus speed is a scalar. Just as we need to distinguish between instantaneous velocity and average velocity, we also need to distinguish between instantaneous speed and average speed.
Instantaneous speed is the magnitude of instantaneous velocity. For example, suppose the airplane passenger at one instant had an instantaneous velocity of −3.0 m/s (the minus meaning toward the rear of the plane). At that same time his instantaneous speed was 3.0 m/s. Or suppose that at one time during a shopping trip your instantaneous velocity is 40 km/h due north. Your instantaneous speed at that instant would be 40 km/h—the same magnitude but without a direction. Average speed, however, is very different from average velocity. Average speed is the distance traveled divided by elapsed time.
We have noted that distance traveled can be greater than displacement. So average speed can be greater than average velocity, which is displacement divided by time. For example, if you drive to a store and return home in half an hour, and your car’s odometer shows the total distance traveled was 6 km, then your average speed was 12 km/h. Your average velocity, however, was zero, because your displacement for the round trip is zero. (Displacement is change in position and, thus, is zero for a round trip.) Thus average speed is not simply the magnitude of average velocity.
Graphing
Another way of visualizing the motion of an object is to use a graph. A plot of position or of velocity as a function of time can be very useful. You might want to review the basics of graphing. Refer to a good math textbook or play around with the PHET simulation
https://phet.colorado.edu/en/simulation/graphing-slope-intercept
and then
https://phet.colorado.edu/en/simulation/graphing-lines
For example, for this trip to the store, the position, velocity, and speed-vs.-time graphs are displayed in Figure 4 below. (Note that these graphs depict a very simplified model of the trip. We are assuming that speed is constant during the trip, which is unrealistic given that we’ll probably stop at the store. But for simplicity’s sake, we will model it with no stops or changes in speed. We are also assuming that the route between the store and the house is a perfectly straight line.)
MAKING CONNECTIONS: TAKE-HOME INVESTIGATION — GETTING A SENSE OF SPEED
If you have spent much time driving, you probably have a good sense of speeds between about 10 and 70 miles per hour. But what are these in meters per second? What do we mean when we say that something is moving at 10 m/s? To get a better sense of what these values really mean, do some observations and calculations on your own:
- calculate typical car speeds in meters per second
- estimate jogging and walking speed by timing yourself; convert the measurements into both m/s and mi/h
- determine the speed of an ant, snail, or falling leaf
Check Your Understanding
1: A commuter train travels from Baltimore to Washington, DC, and back to Balitmore in 2 hours. The distance between the two stations is approximately 40 miles. What is (a) the average velocity of the train, and (b) the average speed of the train in miles per hour and then m/s?
Section Summary
- Time is measured in terms of change, and its SI unit is the second (s). Elapsed time for an event is Δt = tf – t0 where tf is the final time and t0 is the initial time. The initial time is often taken to be zero, as if measured with a stopwatch; the elapsed time is then just t.
- Average velocity [latex]\boldsymbol{\bar{v}}[/latex] is defined as displacement divided by the travel time. In symbols, average velocity is
[latex]\boldsymbol{\bar{v} =}[/latex] =v average = Δx/Δt = (xf – xo)/ (tf – to)
- The SI unit for velocity is m/s.
- Velocity is a vector and thus has a direction.
- Instantaneous velocity v is the velocity at a specific instant or the average velocity for an infinitesimal interval.
- Instantaneous speed is the magnitude of the instantaneous velocity.
- Instantaneous speed is a scalar quantity, as it has no direction specified.
- Average speed is the total distance traveled divided by the elapsed time. (Average speed is not the magnitude of the average velocity.) Speed is a scalar quantity; it has no direction associated with it.
Conceptual Questions
1: Give an example (but not one from the text) of a device used to measure time and identify what change in that device indicates a change in time.
2: There is a distinction between average speed and the magnitude of average velocity. Give an example that illustrates the difference between these two quantities.
3: Does a car’s odometer measure position or displacement? Does its speedometer measure speed or velocity?
4: If you divide the total distance traveled on a car trip (as determined by the odometer) by the time for the trip, are you calculating the average speed or the magnitude of the average velocity? Under what circumstances are these two quantities the same?
5: How are instantaneous velocity and instantaneous speed related to one another? How do they differ?
Problems & Exercises
1: (a) Calculate Earth’s average speed relative to the Sun. (b) What is its average velocity over a period of one year? Assume that it moves in a circular orbit with a radius of 1.50 x 10 11 meters and it takes one year = 3.16 x 10 7 seconds to complete the one orbit.
2: A helicopter blade spins at exactly 100 revolutions per minute in a circle. Its tip is 5.00 m from the centre of rotation. (a) Calculate the average speed of the blade tip in the helicopter’s frame of reference in metres per second. Remember that there are 60 seconds in one minute and that in one revolution the tip travels in a circle — a distance of 2 π r. (b) What is its average velocity over one revolution?
3: The North American and European continents are moving apart at a rate of about 3 cm/year. At this rate how many years will it take them to drift 500 km farther apart than they are at present?
4: Land west of the San Andreas fault in southern California is moving at an average velocity of about 6 cm/y northwest relative to land east of the fault. Los Angeles is west of the fault and may thus someday be at the same latitude as San Francisco, which is east of the fault. How far in the future will this occur if the displacement to be made is 590 km northwest, assuming the motion remains constant?
5: On May 26, 1934, a streamlined, stainless steel diesel train called the Zephyr set the world’s nonstop long-distance speed record for trains. Its run from Denver to Chicago took 13 hours, 4 minutes, 58 seconds, and was witnessed by more than a million people along the route. The total distance traveled was 1633.8 km. What was its average speed in km/h and m/s?
6: Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the Moon is increasing in radius at a rate of approximately 4 cm/year. Assuming this to be a constant rate, how many years will pass before the radius of the Moon’s orbit increases by 3.84 × 106 m (1%)?
7: A student drove to the university from her home and noted that the odometer reading of her car increased by 12.0 km. The trip took 18.0 min. (a) What was her average speed in km/h? Remember that there are 60 minutes in one hour. (b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity? (c) If she returned home by the same path 8.00 hours after she left her home, what were her average speed and velocity for the entire trip?
8: The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.1 m long, and the nerve impulse speed is 18 m/s, how long does it take for the nerve signal to travel this distance? This is one of the factors in your reaction time. It takes time for humans to respond to any stimulus.
9: Conversations with astronauts on the lunar surface were characterized by a kind of echo in which the earthbound person’s voice was so loud in the astronaut’s space helmet that it was picked up by the astronaut’s microphone and transmitted back to Earth. It is reasonable to assume that the echo time equals the time necessary for the radio wave to travel from the Earth to the Moon and back (that is, neglecting any time delays in the electronic equipment). Calculate the distance from Earth to the Moon given that the echo time was 2.56 s and that radio waves travel at the speed of light (3.00 × 108 m/s).
10: A football quarterback runs 15.0 m straight down the playing field in 2.50 s. He is then hit and pushed 3.00 m straight backward in 1.75 s. He breaks the tackle and runs straight forward another 21.0 m in 5.20 s. Calculate his average velocity (a) for each of the three intervals and (b) for the entire motion.
11: The planetary model of the atom pictures electrons orbiting the atomic nucleus much as planets orbit the Sun. In this model you can view hydrogen, the simplest atom, as having a single electron in a circular orbit 5.30 × 10-11 m in diameter. (a) If the average speed of the electron in this orbit is known to be 2.20 × 106 m/s, calculate the number of revolutions per second it makes about the nucleus. Hint: Find the distance travelled in one circular orbit first. (b) What is the electron’s average velocity?
Glossary
- average speed
- distance traveled divided by time during which motion occurs
- average velocity
- displacement divided by time over which displacement occurs
- instantaneous velocity
- velocity at a specific instant, or the average velocity over an infinitesimal time interval
- instantaneous speed
- magnitude of the instantaneous velocity
- time
- change, or the interval over which change occurs
- model
- simplified description that contains only those elements necessary to describe the physics of a physical situation
- elapsed time
- the difference between the ending time and beginning time
Solutions
Check Your Understanding
1: (a) The average velocity of the train is zero because Δx = 0. The train ends up at the same place it starts.
(b) The average speed of the train is calculated below. Note that the train travels 40 miles one way and 40 miles back, for a total distance of 80 miles.
speed = distance / time = 2 x 40 miles / (2 hours) = 40 miles/hour
1 mile = 1609 meters
1 hour = 3600 seconds
speed = (2 x 40 miles x 1609 m/mile) / (2 hours x 3600 s/hour) = 18 m/s to two significant figures. You could argue this is a 1 significant figure question and give the answer of 20 m/s.
Problems & Exercises
1: (a) 2 π r / 3.16×107 s = 3.0 x 104 m/s (b) 0 m/s because in one year the displacement is 0 m.
2. 52.3 m/s b) 0 as the displacement is zero.
3: 2 x 107 years
4. 1 x 107 years
5: 34.689 m/s = 124.88 km/h
6. 1 x 108 years. One significant figure as 4 cm/year has only one significant figure.
7: (a) 40.0 km/h (b) 34.3 km/h , 25 o S of E. (c) average speed=3.00 km/h, average v = 0 m/s as the displacement is 0.
8: 6.1 x 10-2 s
9: 384,000 km Remember that you were asked for the distance between Earth and Moon, a one way trip, though the time given in the question was for the two way trip there and back again.
10: a) 15.0 m/ 2.50 s = 6.00 m/s forward then – 3.00 m / 1.75 s = – 1.71 m/s then 21.0 m / 5.20 s = 4.04 m/s Overall displacement = ( + 15.0 – 3.00 + 21.0 m) / (2.50 + 1.75 + 5.20 s) = 3.49 m/s
11: (a) 6.61 x 1015 rev/s (b) 0 m/s
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