Answer Key 2.1

$\begin{array}{rrl} \\ \\ v+9&=&16 \\ -9&&-9 \\ \midrule v&=&7 \end{array}$
$\begin{array}{rrrrr} \\ \\ 14&=&b&+&3 \\ -3&&&-&3 \\ \midrule 11&=&b&& \end{array}$
$\begin{array}{rrrrr} \\ \\ x&-&11&=&-16 \\ &+&11&&+11 \\ \midrule &&x&=&-5 \end{array}$
$\begin{array}{rrrrr} \\ \\ -14&=&x&-&18 \\ +18&&&+&18 \\ \midrule x&=&4&& \end{array}$
$\begin{array}{rrrrr} \\ \\ 30&=&a&+&20 \\ -20&&&-&20 \\ \midrule a&=&10&& \end{array}$
$\begin{array}{rrrrr} \\ \\ -1&+&k&=&5 \\ +1&&&&+1 \\ \midrule &&k&=&6 \end{array}$
$\begin{array}{rrrrr} \\ \\ x&-&7&=&-26 \\ &+&7&&+7 \\ \midrule &&x&=&-19 \end{array}$
$\begin{array}{rrrrr} \\ \\ -13&+&p&=&-19 \\ +13&&&&+13 \\ \midrule &&p&=&-6 \end{array}$
$\begin{array}{rrrrr} \\ \\ 13&=&n&-&5 \\ +5&&&+&5 \\ \midrule n&=&18&& \end{array}$
$\begin{array}{rrrrr} \\ \\ 22&=&16&+&m \\ -16&&-16&& \\ \midrule m&=&6&& \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{340}{-17}&=&\dfrac{-17x}{-17} \\ \\ x&=&-20 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{4r}{4}&=&\dfrac{-28}{4} \\ \\ r&=&-7 \end{array}$
$\begin{array}{l} \\ \\ \left(-9=\dfrac{n}{12}\right)(12) \\ \\ n=-108 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{27}{9}&=&\dfrac{9b}{9} \\ \\ b&=&3 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{20v}{20}&=&\dfrac{-160}{20} \\ \\ v&=&-8 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{-20x}{-20}&=&\dfrac{-80}{-20} \\ \\ x&=&4 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{340}{20}&=&\dfrac{20n}{20} \\ \\ n&=&17 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{12}{8}&=&\dfrac{8a}{8} \\ \\ a&=&\dfrac{3}{2} \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{16x}{16}&=&\dfrac{320}{16} \\ \\ x&=&20 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{8k}{8}&=&\dfrac{-16}{8} \\ \\ k&=&-2 \end{array}$
$\begin{array}{rrrrr} \\ \\ -16&+&n&=&-13 \\ +16&&&&+16 \\ \midrule &&n&=&3 \end{array}$
$\begin{array}{rrrrr} \\ \\ -21&=&x&-&5 \\ +5&&&+&5 \\ \midrule x&=&-16&& \end{array}$
$\begin{array}{rrrrr} \\ \\ p&-&8&=&-21 \\ &+&8&&+8 \\ \midrule &&p&=&-13 \end{array}$
$\begin{array}{rrrrr} \\ \\ m&-&4&=&-13 \\ &+&4&&+4 \\ \midrule &&m&=&-9 \end{array}$
$\begin{array}{l} \\ \\ \left(\dfrac{r}{14}=\dfrac{5}{14}\right)(14) \\ \\ r=5 \end{array}$
$\begin{array}{l} \\ \\ \left(\dfrac{n}{8}=40\right)(8) \\ \\ n=320 \end{array}$
$\begin{array}{rrl} \\ \\ \\ \dfrac{20b}{20}&=&\dfrac{-200}{20} \\ \\ b&=&-10 \end{array}$
$\begin{array}{l} \\ \\ \\ \\ \left(-\dfrac{1}{3}=\dfrac{x}{12}\right) (12) \\ \\ -\dfrac{1}{3}\cdot 12 = x \\ \phantom{-\dfrac{1}{3}\cdot 1}x=-4 \end{array}$

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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